1.Solve d simultaneous equationz usin the system of Matrix Inversion ....
10x1+3x2+6x3=76
4x1 + 5x3y=41
5x1+2x2 + 2x3 =5


2).
A renewable natural resources R will allow an estimated maximum consumtion rate of 200 million units per annum. Current annual usage is 6.5 million units. If d annual level of usage grows continually at an annual rate of 7.5%,will there be sufficient R to satisfy annual demand after

a)5 years b)10 years c)15 years and d)20 years ?

Make una solve dis nw,,,.....or u mean say d question tough?

^lol, what is tough there? You have to understand that some folks use their mobiles and it takes time to type and post solutions. I'm a little busy too, I will check it out later and if the solution hasn't been posted, I will take out time to help.

Also check and make sure question 1 is correct esp equation 2 like 2nioshine suggested. I believe there is an error in question 1.

Goodboy2012: 1.Solve d simultaneous equationz usin the system of Matrix Inversion ....
10x1+3x2+6x3=76
4x1 + 5x3y=41
5x1+2x2 + 2x3 =5


2).
A renewable natural resources R will allow an estimated maximum consumtion rate of 200 million units per annum. Current annual usage is 6.5 million units. If d annual level of usage grows continually at an annual rate of 7.5%,will there be sufficient R to satisfy annual demand after

a)5 years b)10 years c)15 years and d)20 years ?

Make una solve dis nw,,,.....or u mean say d question tough?

it shows u r nt even following..dont mean any insult plz..but chk previous post 2 verify ur soln

doubleDx: ^lol, what is tough there? You have to understand that some folks use their mobiles and it takes time to type and post solutions. I'm a little busy too, I will check it out later and if the solution hasn't been posted, I will take out time to help.

Also check and make sure question 1 is correct esp equation 2 like 2nioshine suggested. I believe there is an error in question 1.

yea typing dis stof on m.phone is even more dificult dan d question itself...u av bn doing a great job nix wuk

2nioshine: it shows u r nt even following..dont mean any insult plz..but chk previous post 2 verify ur soln

^lol, maybe he wants to be spoon-fed. He should have used your hints to solve question 2 instead of waiting for everything to be done for him!

Goodboy2012: 1.Solve d simultaneous equationz usin the system of Matrix Inversion ....
10x1+3x2+6x3=76
4x1 + 5x3y=41
5x1+2x2 + 2x3 =5

Make una solve dis nw,,,.....or u mean say d question tough?

I took an effort to solve this the way I feel the eqns should be. Always try to get the right eqns across for prompt help

Who can factorize

(x^4) - 1 ?

Pls gurus elp me solve dis... Determine d sum of 8^3 + 9^3 + 10^3 + ... + 200^3

Hardfact: Who can factorize

(x^4) - 1 ?

hmmm let try this...(x^4)-(1^4)..since1^4=1...simplifying further we have(x^2)^2-(1^2)^2..4rm laws of indices...aplying diff of 2square we have(x^2-1^2)(x^2+1^2)...stil aplying same principle we have(x-1)(x+1)(x^2+1)

PortHarcourtBoy: Una say na "Mathematics" thread meanwhile all of una dey speak "English"

Some dey solve Indices, others dey solve Simultaneous equations...very soon another person go come solve Quadratic equations...abi na SS1 students dey here?

Wey the Engineers dem make we solve some First Order Differential Equations...and apply am to Fluid transfer and Thermodynamics

Meanwhile wey my Gala and La Casera?

am ready if u are

Goodboy2012: 1.Solve d simultaneous equationz usin the system of Matrix Inversion ....
10x1+3x2+6x3=76
4x1 + 5x3 =41
5x1+2x2 + 2x3 = 5

I believe phy has corrected the error in your question and has also given you a solution to it by determinant method.

Below is the solution by inverse method:

10x1 + 3x2 + 6x3 = 76 ... Eqtn 1
4x1 + 5x3 = 41 ....Eqtn 2
5x1 + 2x2 +2x3 = 5 ....Eqtn 3

Writing the above given system as a single matrix equation gives:

[10 3 6] [ x1] [76]
[4 0 5] . [ x2] = [41]
[5 2 2] [ x3] [ 5 ]

^A^ ^F^ ^B^
If (F) represents the unknowns and (A) represents the matrix,

(A) . (F) = ( B )
F = ( B ) . A^(-1)
Where A^(-1) is the inverse of the Matrix (A).

The determinant of the Matrix (A) is:
|A| = = 10.(0 - 10) - 3(8 - 25) + 6(8 - 0)
|A| = -100 + 51 + 48
|A| = -1

Computing A^(-1) yields =>

[ -10 6 15 ]
[17 -10 -26 ].{1/|A|}
[ 8 -5 -12]

=>

[-10 6 15 ]
[ 17 -10 -26] . {1/-1}
[ 8 -5 -12]

[ 10 -6 -15 ]
[-17 10 26 ]
[ -8 5 12 ]

A^(-1) =
[ 10 -6 -15 ]
[-17 10 26 ]
[ -8 5 12 ]

F = ( B ) . A^(-1) =>

[76] [10 -6 -15]
[41] * [-17 10 26]
[ 5 ] [-8 2 12]

F = ( B ) . A^(-1) =>
[ 76(10) + 41(-6) + 5(-15) ]
[ 76(-17) + 41(10) + 5(26)]
[ 76(-8 ) + 41(5) + 5(12)]

F = ( B ) . A^(-1) =>

[ 760 - 246 - 75]
[-1292 + 410 + 130]
[ -608 + 205 + 60]

F = ( B ) . A^(-1) =>

[x1] [ 439 ]
[x2] = [- 752]
[x3] [-342 ]

Thus, x1 = 439, x2 = -752, x3 = -343

Well done guys the guy na kpas
That is why Windows failed against Open source
The power of the cloud is better than single source

If u want to make contribtuions, do so
If u want to learn , learn and appreciate
if u have nutin to do, buzz off

Just to let u know, its not easy typing also
I normally use notepad then paste in

biolabee: Well done guys the guy na kpas
That is why Windows failed against Open source
The power of the cloud is better than single source

If u want to make contribtuions, do so
If u want to learn , learn and appreciate
if u have nutin to do, buzz off

Just to let u know, its not easy typing also
I normally use notepad then paste in

^Thank you for that point bro. It aint easy typing all those things on a mobile device.

pls maths guru, do you know where i can find a good qualified mathematics teacher who can teach maths to a child not interested in figures but needs to pass maths to move to the next level in school? suggestions please, anyone!

Gurus pls solve dis na.. Find d sum of 8^3 + 9^3 + 10^3 + ... + 200^3

lanre074: Gurus pls solve dis na.. Find d sum of 8^3 + 9^3 + 10^3 + ... + 200^3

Boom!!! Memba mi tell yu.

Sum n=1 to 193,
(n+7)^3= 404009216

Hardfact: Who can factorize

(x^4) - 1 ?

Lemme expand 2nioshine's solution so you can understand better.

x^4 - 1
Can be written as:
(x^2)^2 - 1^2

Lets x^2 = P

P^2 - 1^2
Since a^2 - b^2 = (a - b)(a + b) - difference of two squares
P^2 - 1^2
= (P - 1)(P + 1)
Substituting P = x^2 yields:

= (x^2 - 1)(x^2 +1)
= (x^2 - 1^2)(x^2 +1)
Appylying the difference of two squares to (x^2 -1^2) gives : (x -1)(x + 1)

:. x^4 - 1 = (x -1)(x + 1)(x^2 +1)

@doubleDX once again gr8 wuk....any who can should try this...2^x=4x.... question2
x+y+z=2, x^2+y^2+z^2=26,
x^3+y^3+z^3=38....plz no graphical soln..ans=4....Q2ans=4,-3 &1

Doubledx ... Godbless u ...
Keep up d good work ... Let's all appreciate doubledx and odaz wu provide solutions 2 sum mathematical problems here ...
Kuz it ain't easy Solvin maths,and most especially typing with ur mobil fone/PC and posting here.... Bless

House gurus help with this questions pls :

1. Prove that sec (x) cos (3x) - cos (2x) = -2sin^2 x

2. (a) Solve the simultaneous equation for the value(s) of x and y.

x + y = 3
x√(y) - 3y +1 = 0

(b) Find the value(s) of (x - y)

phy:

The equation should be S= UT + (1/2)AT^2 or S= UT + (AT^2)/2 for clarity. Pls find my solution below:

NB: Remember that t = time, it can not be negative, so you can play with the eqn.

[img][/img]

Do you know what it means to claim a solution you cut/posted (snipped) straight from a textbook page as your personal solution in a public forum? Be careful!

BoboYekini: Lol. All I have seen here is some very pithy attempts at mathematics, in fact bordering on simple arithmetic. Let's have some hard-core simulation and pursuit theory.

If you are sure of your high level in maths, then solve the question posted as:

a + b + c = 8
a² + b² + c² = 16
a³ + b³ + c³ = 64

Find a, b and c.

If you satisfy us, then we will go further and higher. Thanks in anticipation.

arbitrage:

If you are sure of your high level in maths, then solve the question posted as:

a + b + c = 8
a² + b² + c² = 16
a³ + b³ + c³ = 64

Find a, b and c.

If you satisfy us, then we will go further and higher. Thanks in anticipation.

Why do u keep recycling this question?

ositadima1:

Why do u keep recycling this question?

Because there is no answer yet.

If Q = xyz
Prove that the Curl of Grad Q = 0

arbitrage:

Because there is no answer yet.

Ok

arbitrage:

Do you know what it means to claim a solution you cut/posted (snipped) straight from a textbook page as your personal solution in a public forum? Be careful!

Let me tell you, I don't cut and paste solutions. I went the extra mile to use equation editor to type all the solutions I give because I want people to understand the solutions. I have made up my mind to help any Nigerian students to any length I can. If I can type it out, I will rather not post in here. If you have a prove of plagiarism, pls bring it forward. I am a professional and I am in an environment where plagiarism will never be supported.

Pls next time if you're inquisitive about how people do their stuffs ask questions rather than rushing to conclusions. If you approached me physically with this accusation in my terrain, I would have sued you for this. Pls always ask questions. I guess I should be using pidgin English in my solutions for you to know I went the extra mile to type it for clarity.

Ghettoguru: House gurus help with this questions pls :
2. (a) Solve the simultaneous equation for the value(s) of x and y.

x + y = 3
x√(y) - 3y +1 = 0

(b) Find the value(s) of (x - y)

If you need more details or have more questions, ask.

I may be back with a proof to the trig. question.

so BABE! the fin sabi maths...

Talking about complimentary angles








Coogar