₦airaland Forum

At last.. today is my screening... I hope I'll be back here at night to give my testimony

hormorlorlah:
dearie u sudnt av filled anytin. Just leave it till 2morow. Go very early 2 school so dat if u need 2 reprint d screening form u wud do dat on time.

Lola.. thanks a whole lot

peeps... my screening is tomorrow and I've compiled all my credentials but on my screening form some things were missing and I've filled them with pen... hope I'm safe?

please who knows if wassce Nov/dec 2014/15 certificate is out

fellow akokaites... please the stuff is telling me to upload waec certificate and I don't have it yet... can I upload the statement of result

FrancisTony:
I don't have my reference letter yet until sunday, can I start uploading those bio-data and is reference letter required to be uploaded too?

Tony.. abeg which course

jephri:
Sorry for those that have registered, in my screening form , utme reg number , utme score & exam center & town are blank .. Is it meant to be like that ?

Jephri.. are you on the supplementary list.. I'm on supp list And I've not been able to login

Debravo.. please mathematics screening date and venue....(Mathematics science)

Tosap:
I don tire jare

Whalai... me too... which course you dey?

Tosap:
Please,has anyone been able to log in to Students account??it's like the site is down sef

Tosap... longest time... me self I don dey try ham since Saturday

I tire for this Unilag site o... supplementary list screening starts tomorrow.. yet we've not been able to log in and print the screening form

mherceedaniels:
.naxo o..same here..nd person nid to upload docs too b4 d screening...#iranu

Whalai.... Unilag is a bureaucratic school

Screening starts tomorrow... yet this undergraduate login is still saying username/password mismatch... I tire oh

davbravo:
Am a DE student, Medical Laboratory sciences

. oh nice one bro

debravo... what course?

davbravo:
Same here. I don't think our portal as been created, let's wait till tomorrow

Unilag's site self hasn't been loading since yesterday night

Please would there be a screening timetable for each faculty... I mean the supplementary list screening

Dsd1pumpking:
To all student @ Faculty of science should join group chat on whatsapp. Science only pls!

Drop ur number!

08142139264

Please how much is the total fee for science students

#TeamMathematicsScience

lordmizzy:
same here bro ... I can't stay at home for 1-yr naa . although its my 1st jamb ... am juz praying my name appears den I ll ryt anoda jamb .. mech engr(UNIOSUN) ..

no qualms bro... meet you at the top

kayodewizzy:
ok oooo,,,,i wish u ALL THE BEST

thanks man

lordmizzy:
wow . got 214 dis yr pet engr (futo) but didn't pass cut off .. but I also applied for UNIOSUN(mathematics) ..

I also proposed for mathematics science at Unilag for change of course... but guy seriously I know my worth! I can't do it

kayodewizzy:
see u;;;;u av given up already,,,,no faith....cant u wait for 2nd list::::::and mind u,everyday is not xmas

wizzy I proposed for mathematics science In my change of course... and I can't do it because I know what I'm capable of

lordmizzy:
lol u r funny . d question is if u have got what it takes to get 250 in jamb and get 70% in post jamb ... u funny oo

mizzy... I will try my best... had 267 in my utme this year tho and aggregate of 65.88 for petroleum and gas engr in Unilag but I didn't meet the cut off... so I believe I should get into funaab next year

Isomerizm:

...like you even have what it takes to be given the course in the first place.

isomerism.. my olevel is maths a1.. Eng b3... Chem b3... phy b3... biology... b3... I had 267 in my jamb this year with a composite of 65.88 for petroleum and gas at Unilag this year but I didn't meet the cut off.... I was 1.5 marks behind... so nothing's gonna stop me in funaab next year..

I'm aspiring funaab to study electrical/electronics engineering next year... please I really want to know if the school has what it takes to offer this course

hello funaabites... I'm aspiring funaab to study electrical/electronics engineering next year... please I really want to know if the school has what it takes to offer this course

[color=#770077][/color] please is there any funaab prospective scholar for next year here?

Orezy5:
example three:

find the value of p, if the line which passes through (-1, -p) and (-2p, 2) is parallel to the line 2y + 8x - 17=0

solution
since both lines are parallel, they have the same slope/gradient.
let's find the gradient of 2y + 8x -17=0
as you all know that the general form of straight line equations is y=mx + c, let's re-arrange the equation to suit this arrangement:

2y + 8x - 17=0
2y= -8x + 17
make y the subject of the formula by dividing both sides by 2:

2y/2= -8x/2 + 17/2
y= -4x + 17/2
therefore, the gradient is -4.

now that we've gotten the value of the slope, let's find the value of p by using the gradient formula:
m=y2 - y1/x2 - x1

m=-4,
x1= -1,
x2= -2p,
y1= -p,
y2= 2.

-4= 2-(-p)/-2p -(-1)

-4= 2 + p/-2p + 1
cross multiply:
-4(-2p + 1)= 2 + p
open the bracket:

8p - 4= 2 + p
collect like terms:

8p - p= 2 + 4
7p= 6

divide both sides by 7:
7p/7 = 6/7
therefore, the value of p is= 6/7.

nice one orezy... I would love to teach statistics though

Orezy5:
[color=#000099]example three:

find the value of p, if the line which passes through (-1, -p) and (-2p, 2) is parallel to the line 2y + 8x - 17=0

solution
since both lines are parallel, they have the same slope/gradient.
let's find the gradient of 2y + 8x -17=0
as you all know that the general form of straight line equations is y=mx + c, let's re-arrange the equation to suit this arrangement:

2y + 8x - 17=0
2y= -8x + 17
make y the subject of the formula by dividing both sides by 2:

2y/2= -8x/2 + 17/2
y= -4x + 17/2
therefore, the gradient is -4.

now that we've gotten the value of the slope, let's find the value of p by using the gradient formula:
m=y2 - y1/x2 - x1

m=-4,
x1= -1,
x2= -2p,
y1= -p,
y2= 2.

-4= 2-(-p)/-2p -(-1)

-4= 2 + p/-2p + 1
cross multiply:
-4(-2p + 1)= 2 + p
open the bracket:

8p - 4= 2 + p
collect like terms:

8p - p= 2 + 4
7p= 6

divide both sides by 7:
7p/7 = 6/7
therefore, the value of p is= 6/7.

nice one orezy... I would love to teach statistics though[/color]

Orezy5:
example three:

find the value of p, if the line which passes through (-1, -p) and (-2p, 2) is parallel to the line 2y + 8x - 17=0

solution
since both lines are parallel, they have the same slope/gradient.
let's find the gradient of 2y + 8x -17=0
as you all know that the general form of straight line equations is y=mx + c, let's re-arrange the equation to suit this arrangement:

2y + 8x - 17=0
2y= -8x + 17
make y the subject of the formula by dividing both sides by 2:

2y/2= -8x/2 + 17/2
y= -4x + 17/2
therefore, the gradient is -4.

now that we've gotten the value of the slope, let's find the value of p by using the gradient formula:
m=y2 - y1/x2 - x1

m=-4,
x1= -1,
x2= -2p,
y1= -p,
y2= 2.

-4= 2-(-p)/-2p -(-1)

-4= 2 + p/-2p + 1
cross multiply:
-4(-2p + 1)= 2 + p
open the bracket:

8p - 4= 2 + p
collect like terms:

8p - p= 2 + 4
7p= 6

divide both sides by 7:
7p/7 = 6/7
therefore, the value of p is= 6/7.

nice one orezy... I would love to teach statistics though

Orezy5:
example three:

find the value of p, if the line which passes through (-1, -p) and (-2p, 2) is parallel to the line 2y + 8x - 17=0

solution
since both lines are parallel, they have the same slope/gradient.
let's find the gradient of 2y + 8x -17=0
as you all know that the general form of straight line equations is y=mx + c, let's re-arrange the equation to suit this arrangement:

2y + 8x - 17=0
2y= -8x + 17
make y the subject of the formula by dividing both sides by 2:

2y/2= -8x/2 + 17/2
y= -4x + 17/2
therefore, the gradient is -4.

now that we've gotten the value of the slope, let's find the value of p by using the gradient formula:
m=y2 - y1/x2 - x1

m=-4,
x1= -1,
x2= -2p,
y1= -p,
y2= 2.

-4= 2-(-p)/-2p -(-1)

-4= 2 + p/-2p + 1
cross multiply:
-4(-2p + 1)= 2 + p
open the bracket:

8p - 4= 2 + p
collect like terms:

8p - p= 2 + 4
7p= 6

divide both sides by 7:
7p/7 = 6/7
therefore, the value of p is= 6/7.

nice one orezy... I would love to teach statistics though

Tosap:
Yea.

But,am a little bit confused petroleum engineering and petroleum and gas engineering... is there any difference?

But I believe you should gain admission.

its the same bro... unilag is just spilling tautology.. whats petroleum without gas? the best I give it is petroleum eng... are u also an aspirant of that course?