₦airaland Forum

Reekadict04:
We will all pass IJN

AMEN O..u d0n reprint?

WisdomCanada:
That's my governor of our Abia state, lalasticlala shey u no dat Abia is our Abia state, i saw u inside the same keke wey i enter for Bata, but u never knew i knew it you. Lol, u looked so humble nd loyal like an erect d*ck dat was splashed hot water, somebody will not even know u are a supermod in nairaland....who dey sew ur shirts?

na me de sew 4 am

Umartins1:
M² + n² = 29 ...... (1)
M+n=7....... (2)


From eqn (2), m+n= 7

M= 7-n


Sub for m in eqn (1)


(7-n)² + n² = 29


(7-n)(7-n) + n² = 29


49-7n-7n+n²+n² = 29

49-14n+2n² = 29

2n²-14n+49-29= 0


2n²-14n+20= 0


n²-7n+10= 0


n²-5n-2n+10= 0


n(n-5)-2(n-5) = 0


(n-2)(n-5) = 0


n=2 or n=5


When n=2,


Sub for n in eqn (2)


M+n=7


M+2=7


M= 7-2


M= 5



When n=5


Sub for n in eqn (2)


M+n= 7


M+5= 7


M= 7-5


M= 2



(2,5) (5,2)

dis one na surd.
2/1-₹3

Umartins1:
M² + n² = 29 ...... (1)
M+n=7....... (2)


From eqn (2), m+n= 7

M= 7-n


Sub for m in eqn (1)


(7-n)² + n² = 29


(7-n)(7-n) + n² = 29


49-7n-7n+n²+n² = 29

49-14n+2n² = 29

2n²-14n+49-29= 0


2n²-14n+20= 0


n²-7n+10= 0


n²-5n-2n+10= 0


n(n-5)-2(n-5) = 0


(n-2)(n-5) = 0


n=2 or n=5


When n=2,


Sub for n in eqn (2)


M+n=7


M+2=7


M= 7-2


M= 5



When n=5


Sub for n in eqn (2)


M+n= 7


M+5= 7


M= 7-5


M= 2



(2,5) (5,2)

tank u sir

Solve d eqn. m^2 + n^2 =29; m + n=7

Hallexander:
Its very simple, just rethink, the answer is already in the question

talk am

afonomics:
costless?

do u knw abt d skul..tel me pls

Brother firstly i want you to understand that masturbation is a sin. And sin is a spirit greater than a man. You cant stop it on your own except you genuinely give your life to Jesus Christ. The growth of the Word of God in you becomes your empowerment to overcome masturbation. The next thing is for you to do away with objects that leads to it.

uzeba:
27= 8^5 - x
27= 32768 - x
x= 32768 - 27
x = 32741

thanks but its not in the options

Elisean:
Cc seun
he knows maths

what of u

Solve 27=8^5-x

Please how can i get jamb 2016 syllabus for Mathematics,physics, and chemistry

Drniyi4u:
Q1 is kinda odd, they rarely ask to find constants. Nonetheless, to solve for 2 (i.e making 2 d subject), take the log of both sides,
log (2^n) = log y
n log 2 = log y
log 2 = (log y)/n
take the natural log of both sides
ln (log 2) = ln [(log y)/ n]
2 = ln [(log y)/ n]

Q2. represent 5^x by p, then substitute
p² - 15 * p + 50 = 0
p² - 15p + 50 = 0
solving it quadratically gives 5 and 10
i.e p = 5 and p=10

substitute p by 5^x
5^x = 5 and 5^x = 10
5^x = 5¹ and 5^x = 10(taking log of both sides)
x =1 and log (5^x) = log 10
x = 1 and x log 5 = log 10
x = 1 and x = [(log 10) / (log 5)]

i dnt undastnd Q1.. Wat is "ln"

(1) if 2^n =y. Find 2
(2) 25* - 15 x 5* + 50 =0

N/B 2^n is 2 raise to power n and 25* is 25 raise to power x. Same with 5*

Please help me solve this indices. If 2^n =y. Find 2