Please Help Me Solve This - Crime - Nairaland
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| Please Help Me Solve This by Flamees(op): 5:06pm On Aug 15, 2021 |
A mass 25kg has its Gravitational potential seven times another Mass when it is 60km from the surface of the Earth What is the Height of the second mass above The earth surface Cc:Seun |
| Re: Please Help Me Solve This by Flamees(op): 5:06pm On Aug 15, 2021 |
Please ohh I posted it at crime section cause People are much here Help ohh ![]() |
| Re: Please Help Me Solve This by Flamees(op): 5:07pm On Aug 15, 2021 |
Been Solving this for Almost 30mins ![]() Please Mods Push it To FP so that People can Help a Nigga ![]() |
| Re: Please Help Me Solve This by Truvelisback(m): 9:35pm On Aug 15, 2021 |
Flamees:Are these grammars not too big "Gravitational Potential" |
| Re: Please Help Me Solve This by CALCULUS16: 9:59pm On Aug 15, 2021*. Modified: 10:20pm On Aug 15, 2021 |
Flamees:Gravitational potential = GM/R , that is the formula u will use. See both G and Mass of the earth are constant, G is universal gravitational constant while M is the mass of the earth. Interpreting mass 25kg has its Gravitational potential seven times another Mass GM/R = 7 x GM/R2 You know G and M will cancel each other Then we have 1/R = 7/R2 cross multiply, R stand for the height of the first mass while R2 stands for the height of the second mass R2= 7R But the height of the first mass is 60km, then R2=7 x 60 = 420km Mind you, all objects fall under the same acceleration on earth regardless of the mass, that's why the mass given there is useless. Know this too, the higher the potential , the lower the height or altitude and the lower the potential , the higher the altitude, thats why the second objects height is higher than the first. I am offering an online tutorial on physics, mechanics, chemistry and maths. If u wish to join u can message me. I am taking waec online tutorial or if u are in 100 level , I can help u in mechanics. |
| Re: Please Help Me Solve This by Flamees(op): 3:25am On Aug 16, 2021 |
CALCULUS16:Thank you Sir I appreciate How do you take your Online Class ? |
| Re: Please Help Me Solve This by Flamees(op): 3:35am On Aug 16, 2021 |
Truvelisback: u don see am na |
| Re: Please Help Me Solve This by Flamees(op): 5:28am On Aug 16, 2021 |
CALCULUS16:But sir I taught R is the radius of The Earth The confusing part there is that We were giving the formula as -GM/R+H Where H is the Height And according to the Question We are looking for The Mas of M2 and it's Height |
| Re: Please Help Me Solve This by CALCULUS16: 6:44am On Aug 16, 2021 |
Flamees:Message me here, I will privately give you my number, so that u can join the class |
| Re: Please Help Me Solve This by CALCULUS16: 6:48am On Aug 16, 2021*. Modified: 7:25am On Aug 16, 2021 |
Flamees:No R stands for the distance between the test mass m and the surface of the another mass M which is earth in this case. We use R to denote distance between two quantities in physics, just like couloumbs law , which is synonymous to newtons law of universal gravitation, F= KQq/r^2, u can see that r there stands for distance between the too charges. |
| Re: Please Help Me Solve This by CALCULUS16: 7:25am On Aug 16, 2021*. Modified: 7:43am On Aug 16, 2021 |
Flamees:Wait, you can message me ur number, so that I can add you to the online group |
| Re: Please Help Me Solve This by CALCULUS16: 7:39am On Aug 16, 2021 |
Flamees:Potential energy is P.E = -GMm/r From this equation P.E = gravitational potential x mass of the object Interpreting first statement Let V represent the potential of first mass So 7V x mass of 1st object = V xmass of second object V cancel V Mass of first object is 25kg 25 x 7 =mass of second object Mass of second object = 25 x 7 =175kg |
| Re: Please Help Me Solve This by gulfer: 12:46pm On Aug 16, 2021 |
CALCULUS16:@Calculus, your answer looks more plausible..... The original solver tried as well; I don't seem to remember these to things very well again ![]() |
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u don see am na