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Nairaland Mathematicians, Please Come And Help Me Solve This - Education - Nairaland

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Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN(op): 4:36pm On Jan 16, 2023
Please I really need help with this.
I just can't get to the answer and I don't know why

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by don4real: 5:15pm On Jan 16, 2023
X=4
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Chaos14: 6:10pm On Jan 16, 2023
don4real:
X=4
Wrong -4
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by doggedemmy(m): 6:30pm On Jan 16, 2023
sqlPAIN:
Please I really need help with this.
I just can't get to the answer and I don't know why

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by steeltrust: 7:20pm On Jan 16, 2023
To solve this equation, we can start by multiplying both sides of the equation by x(x+2) to eliminate the fractions:

1/x + 1/2 = 3/x
x(x+2) = (x+2)

Next, we can distribute the x on the left side of the equation:

x^2 + 2x = x + 2

Then, we can subtract x from both sides:

x^2 + x = 2

Finally, we can subtract 2 from both sides:

x^2 + x - 2 = 0

Now, we can factor the left side of the equation:

(x-1)(x+2)=0

This gives us two solutions:
x = 1 or x = -2

Hence the solutions are x = 1, and x = -2
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN(op): 7:31pm On Jan 16, 2023
Chaos14:
Wrong -4
the Answer is 4 bro
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN(op): 7:32pm On Jan 16, 2023
steeltrust:
To solve this equation, we can start by multiplying both sides of the equation by x(x+2) to eliminate the fractions:

1/x + 1/2 = 3/x
x(x+2) = (x+2)

Next, we can distribute the x on the left side of the equation:

x^2 + 2x = x + 2

Then, we can subtract x from both sides:

x^2 + x = 2

Finally, we can subtract 2 from both sides:

x^2 + x - 2 = 0

Now, we can factor the left side of the equation:

(x-1)(x+2)=0

This gives us two solutions:
x = 1 or x = -2

Hence the solutions are x = 1, and x = -2
just solving absolute rubbish. only God knows where you dey get "^" from
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by shox: 7:32pm On Jan 16, 2023
steeltrust:
To solve this equation, we can start by multiplying both sides of the equation by x(x+2) to eliminate the fractions:

1/x + 1/2 = 3/x
x(x+2) = (x+2)

Next, we can distribute the x on the left side of the equation:

x^2 + 2x = x + 2

Then, we can subtract x from both sides:

x^2 + x = 2

Finally, we can subtract 2 from both sides:

x^2 + x - 2 = 0

Now, we can factor the left side of the equation:

(x-1)(x+2)=0

This gives us two solutions:
x = 1 or x = -2

Hence the solutions are x = 1, and x = -2
Wrong answers.

X=4

1/4+ 1/2= 3/4. Making the equation right
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sqlPAIN(op): 7:38pm On Jan 16, 2023
[quote author=doggedemmy post=120095361][/quote]Thanks so much bro. Please in this your solution, can you explain why x(2+x) is equal to 2+x and not 2x+x^2 and also why 3(2x) equal to 6 and not 6x

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by doggedemmy(m): 7:41pm On Jan 16, 2023
sqlPAIN:
Thanks so much bro. Please in this your solution, can you explain why x(2+x) is equal to 2+x and not 2x+x^2 and also why 3(2x) equal to 6 and not 6x
You can cancel the x from both sides since it’s a common factor.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by ozonelayer79: 7:52pm On Jan 16, 2023
If that equation is correct then it means x has no solution because with the equation like that, what you have after solving it is x^2 (that is, x square ) = 4x
In summary, x^2=4x
X= square root of 4x.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Googleus(m): 7:57pm On Jan 16, 2023
Solving
Sl
1/x + 1/2 = 3/x

To solve the equation 1/x + 1/2 = 3/x, we can start by multiplying both sides of the equation by the least common multiple of the denominators, which in this case is x. This gives us:

x(1/x) + (x)(1/2) = (3)(x)/x

Simplifying the left side of the equation by canceling out the x's on the numerator and denominator, we get:

1 + (x/2) = 3

We can then subtract x/2 from both sides of the equation:

1 = 3 - x/2

Multiply both sides by 2 to get rid of the fraction:

2 = 6 - x

Finally, adding x to both sides of the equation:

x = 6 - 2

x = 4

So the solution is x = 4.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by doggedemmy(m): 8:04pm On Jan 16, 2023
ozonelayer79:
If that equation is correct then it means x has no solution because with the equation like that, what you have after solving it is x^2 (that is, x square ) = 4x
In summary, x^2=4x
X= square root of 4x.
If x2=4x, you can divide both sides by x and get x as 4.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by FromZeroToHero(m): 8:04pm On Jan 16, 2023
Very simple

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by ozonelayer79: 8:13pm On Jan 16, 2023
doggedemmy:
If x2=4x, you can divide both sides by x and get x as 4.
That is, x × x = 4 × x
Which means X cancels out X which finally gives x = 4

That's very correct.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by steeltrust: 8:15pm On Jan 16, 2023
sqlPAIN:
just solving absolute rubbish. only God knows where you dey get "^" from
that not nice
You can correct me in a calm manner

I’m not God who knows it all
Atlist I made an attempt correct me where I’m wrong not shouting as we are enemies

It not nice
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by NaijaphiliaBlog: 8:16pm On Jan 16, 2023
EQUATION: 1/X + 1/2 = 3/X

SOLUTION:
Since the right side of the equation is 3/X, let's multiply everything by X in order to cancel the X on the right side i.e.


X(1/X + 1/2) = X(3/X)

X/X + X/2 = 3X/X

1 + X/2 = 3

Lets move the 1 to the right side of the equation i.e.

X/2 = 3 - 1

X/2 = 2

Let's finally multiply both sides by 2 i.e.

2(X/2) = 2(2)

X = 4

QED
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Spare124: 8:16pm On Jan 16, 2023
Please can you help with this

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Drrnie(m): 8:34pm On Jan 16, 2023
sqlPAIN:
the Answer is 4 bro
Bro leave that one... Na only God know where e get -4 from
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Edmaths: 8:51pm On Jan 16, 2023
steeltrust:
that not nice
You can correct me in a calm manner

I’m not God who knows it all
Atlist I made an attempt correct me where I’m wrong not shouting as we are enemies

It not nice
Sorry about that.

The equation has two answers: x = 0 or x = 4
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Nobody: 8:59pm On Jan 16, 2023
Spare124:
Please can you help with this
Example 1
6*5=30
30/2=15
How they got 15

15/5=3
3*2= 6
How they got 6

6*5=30
30/15=2
How they got 2

15*2=30
30/6=5
How they got 5
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by don4real: 9:06pm On Jan 16, 2023
See confidence chai. You are the one that is wrong. Check the solving below
Chaos14:
Wrong -4
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by MIRACULOUS123(m): 9:22pm On Jan 16, 2023
Chaos14:
Wrong -4
Seems I'm the only one that understand you.

I thought the first step before solving anything is to collect the like terms.
1/x +1/2=3/x
Collect the like terms.
1/x -3/x=-1/2
Then finding the LCM.
-2/x=-1/2
Lastly,cross multiply
X=-4
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by sholey4love: 9:33pm On Jan 16, 2023
Here is the answer

Just copy and paste this on Google

1/x+1/2=3/x

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Alusiizizi(m): 10:03pm On Jan 16, 2023
sqlPAIN:
Please I really need help with this.
I just can't get to the answer and I don't know why
M0ron!!
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by jeromestarks:
Una no Sabi anything for this forum.

1/x +1/2 = 3/x


Find LCM you have

2+3/2x = 3/x

Cross multiply, you have


6x = x(2 + x)

Opening the brackets, you have


6x = 2x + x^2 i.e x square
Collecting like terms , you have


6x -2x = x^2
4x = x^2
X^2 -4x = 0

Factorise it and I get
X (x -4) = 0

Divide both sides by x
X (x - 4)/X = 0/x
X - 4 = 0

X = 4
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by TONYE001(m): 10:42pm On Jan 16, 2023
x = 4.

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Goodlady(f): 10:58pm On Jan 16, 2023
sqlPAIN:
Please I really need help with this.
I just can't get to the answer and I don't know why
The answer is 2. It's dark here I d v shown you my wokings.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Awesome80(m): 11:59pm On Jan 16, 2023
Here's my own solution...

The LCM of x, 2 and x in the equation:
1/X +1/2 = 3/X is 2X.

Multiply through by 2x, i.e

1/X x 2X + 1/2 x 2X = 3/X x 2X

Here a couple of things happen...
1. The X in 2X cancels out X in 1/X leaving you with 1 x 2 = 2.

2. The 2 in 2X cancels out 2 in 1/2 leaving you with 1 x X = X.

3. The X in 2X cancels out X in 3/X leaving you with 3 x 2 = 6.

So we now have 2 + X = 6.

After collecting like terms, we have
X = 6 - 2
Therefore, X = 4.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Bam17(f): 12:23am On Jan 17, 2023
4... like everyone got kiss

Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Bam17(f): 12:26am On Jan 17, 2023
Spare124:
Please can you help with this
Here, you multiply the first two, then divide by the 3rd to get the final answer.
Re: Nairaland Mathematicians, Please Come And Help Me Solve This by Bam17(f): 12:28am On Jan 17, 2023
Spare124:
Please can you help with this
To understand better.


Modified: Then you start applying the steps to the rest of the sums cheesy

1 2 Reply

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