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Solve This Simple Maths by Nobody: 5:42pm On Jan 07, 2016
A contractor agreeing to finish a work in 150 days employed 75 men each working 10 hours daily. After 90 days, only 1/4 of the work was completed. Increasing the number of men by …………. each working now for 15 hours daily, the work can be completed in time.

1 Like

Re: Solve This Simple Maths by Nobody: 5:44pm On Jan 07, 2016
CarlOzeki, Snowland, Tinkybabe, flawlesRebirth, misshoree, seun, Lalasticlala, Mynd44, eroticangel,
paranorman, vengeance, kobonaire.... YOUR
ATTENTIONS ARE NEEDED
Re: Solve This Simple Maths by Kenzico(m): 5:55pm On Jan 07, 2016
Am not good in maths....But this one looks sweet
Re: Solve This Simple Maths by chiefolododo(m): 6:16pm On Jan 07, 2016
hopelink1:
CarlOzeki, Snowland, Tinkybabe, flawlesRebirth, misshoree, seun, Lalasticlala, Mynd44, eroticangel,
paranorman, vengeance, kobonaire.... YOUR
ATTENTIONS ARE NEEDED
you come dey mention Lalasticlala?
Re: Solve This Simple Maths by denniece1(m): 6:29pm On Jan 07, 2016
150men
Re: Solve This Simple Maths by paranorman(m): 7:03pm On Jan 07, 2016
hopelink1:
A contractor agreeing to finish a work in 150
days employed 75 men each working 10 hours
daily. After 90 days, only 1/4 of the work was
completed. Increasing the number of men by
…………. each working now for 15 hours daily, the
work can be completed in time.
dude, the trick in solving this kinda question is to quantify the amount of work done or to be done yourself, if you cannot solve it straight.
Say total work to be done is 10000kg. For 150 days, twil take (100000/150)kg per day.

So, after 90 days, 1/4 of the work was done= 1/4(10000)kg=2500kg

work/day = (2500/90)kg

work/day/man = (2500/90)/75

work/day/man/hours=((2500/90)/75))/10= quantity of work that can be done per man for an hour.

According to contract, (150-90) days left, work is to be completed in 60days.

Work left to be done is 10000-2500;

after you have found work/day/man/hours, calculate amount of work done by a man for 15 hours.
Remember, new men will be added.

From this info, you should to able to manipulate and get your answer.
Re: Solve This Simple Maths by chiefolododo(m): 7:56pm On Jan 07, 2016
Kenzico:
Am not good in maths....But this one looks sweet
guy you no sabi
Re: Solve This Simple Maths by Sibrah: 8:27pm On Jan 07, 2016
You increase the No of men by minimum of 18.85 but since men cannot be in fraction and question require the " additional number of men required to complete the job on time" it is 19 at minimum.
19

The question should be modified to request the minimum number of men request cos if any one gives an answer greater than the minimum required it will satisfy the condition that request "the number of men to be added to complete the job on time"
Re: Solve This Simple Maths by Nobody: 8:32pm On Jan 07, 2016
Sibrah:
You increase the No of men by minimum of 18.85 but since men cannot be in fraction and question require the " additional number of men required to complete the job on time" it is 19 at minimum.
19

The question should be modified to request the minimum number of men request cos if any one gives an answer greater than the minimum required it will satisfy the condition that request "the number of men to be added to complete the job on time"
you are wrong
Re: Solve This Simple Maths by Sibrah: 8:41pm On Jan 07, 2016
hopelink1:
you are wrong
I did a quick cross-check. It is 19 men to be added to 75 on ground. 19 or 94 depending on how you see it.
Re: Solve This Simple Maths by Nobody: 9:55pm On Jan 07, 2016
chiefolododo:
you come dey mention Lalasticlala?
lala no know mathematics?
Re: Solve This Simple Maths by Nobody: 9:56pm On Jan 07, 2016
paranorman:

dude, the trick in solving this kinda question is to quantify the amount of work done or to be done yourself, if you cannot solve it straight.
Say total work to be done is 10000kg. For 150 days, twil take (100000/150)kg per day.

So, after 90 days, 1/4 of the work was done= 1/4(10000)kg=2500kg

work/day = (2500/90)kg

work/day/man = (2500/90)/75

work/day/man/hours=((2500/90)/75))/10= quantity of work that can be done per man for an hour.

According to contract, (150-90) days left, work is to be completed in 60days.

Work left to be done is 10000-2500;

after you have found work/day/man/hours, calculate amount of work done by a man for 15 hours.
Remember, new men will be added.

From this info, you should to able to manipulate and get your answer.
ans only
Re: Solve This Simple Maths by Damfash(m): 10:45pm On Jan 07, 2016
.
Re: Solve This Simple Maths by Damfash(m): 11:07pm On Jan 07, 2016
Definitely 150 men. Let me try and explain this in a simple way. The first set of men spent 900 hours (10 hours each day for 90 days). The second set of men also spent 900 hours(15 hours each day for 60 days). Knowing that they spent the same number of hours, if the first group (comprising 75 men) could do one quarter of a work, how many men would do three quarters (the remainder) of that same work under the same duration? This will be (75*3)=225. So, 225 men finised the work. By now, I hope you agree with me that 150 men were added.

1 Like

Re: Solve This Simple Maths by Damfash(m): 3:52pm On Jan 08, 2016
.
Re: Solve This Simple Maths by Nobody: 4:41pm On Jan 08, 2016
Damfash:
Definitely 150 men. Let me try and explain this in a simple way. The first set of men spent 900 hours (10 hours each day for 90 days). The second set of men also spent 900 hours(15 hours each day for 60 days). Knowing that they spent the same number of hours, if the first group (comprising 75 men) could do one quarter of a work, how many men would do three quarters (the remainder) of that same work under the same duration? This will be (75*3)=225. So, 225 men finised the work. By now, I hope you agree with me that 150 men were added.
yea
Re: Solve This Simple Maths by Sibrah: 5:58pm On Jan 08, 2016
hopelink1:
yea
Provide a convincing explanation please. I believe your question isn't clear enough.
Re: Solve This Simple Maths by octalbell(m): 9:55pm On Jan 08, 2016
This is my solution

Re: Solve This Simple Maths by Nobody: 10:48pm On Jan 08, 2016
octalbell:
This is my solution
wrong

1 Like

Re: Solve This Simple Maths by Nobody: 11:02pm On Jan 08, 2016
Sibrah:
Provide a convincing explanation please. I believe your question isn't clear enough.
1/4(x) is equivalent to 90days x 10hours x 75men and 3/4(x) is equivalent to 60days x 15hours x W men. Taking ratio of These equation i. E
1
---x = 90 x 10 x 75
4
--- - - - - - - - - - -
3
--x = 60*15*W
4



W, the total number of men to complete the job from This equation is 225, Therefor it requires (225--75)=150men to complete 3/4 of the work in the remaining 60 days if They work for 15hours per day
Re: Solve This Simple Maths by Sibrah: 3:45am On Jan 09, 2016
hopelink1:
1/4(x) is equivalent to 90days x 10hours x 75men and 3/4(x) is equivalent to 60days x 15hours x W men. Taking ratio of These equation i. E
1
---x = 90 x 10 x 75
4
--- - - - - - - - - - -
3
--x = 60*15*W
4



W, the total number of men to complete the job from This equation is 225, These for it requires (225--75)=150men to complete 3/4 of the work in the remaining 60 days if They work for 15hours per day

I followed a similar principle with MS Excel but end up having a diff ans. Must have mixed things up somewhere.
Re: Solve This Simple Maths by misshoree(f): 9:47am On Jan 11, 2016
hopelink1:
A contractor agreeing to finish a work in 150
days employed 75 men each working 10 hours
daily. After 90 days, only 1/4 of the work was
completed. Increasing the number of men by
…………. each working now for 15 hours daily, the
work can be completed in time.
Am not a mathematician, I deal with drugs tongue
Re: Solve This Simple Maths by Nobody: 8:33pm On Jan 12, 2016
misshoree:
Am not a mathematician, I deal with drugs tongue
hard drugs
Re: Solve This Simple Maths by Nobody: 8:33pm On Jan 12, 2016
misshoree:
Am not a mathematician, I deal with drugs tongue
hard drugs?
Re: Solve This Simple Maths by Tinkybabe(f): 11:34am On Jan 31, 2016
CarlOzeki, Snowland, Tinkybabe, flawlesRebirth, misshoree, seun, Lalasticlala, Mynd44, eroticangel,
paranorman, vengeance, kobonaire.... YOUR
ATTENTIONS ARE NEEDED

I'm sorry, just seeing the mention.
Ans= 150

Let total work to be completed be X

It takes 75 men 10 hours to complete X/4 work in 90days

750 hrs x 90 = X/4
X =270,000 arbitrary unit

We have only (150- 90)days left to complete the work at 15 hours per person. If total no of people required to complete the remaining job is R
Then

15R x 60 =3/4 X
Note X =270,00

R = 225

Men to be added to previous is 225- 75 = 150 men
Re: Solve This Simple Maths by paranorman(m): 11:58am On Jan 31, 2016
Tinkybabe:


I'm sorry, just seeing the mention.
Ans= 150

Let total work to be completed be X

It takes 75 men 10 hours to complete X/4 work in 90days

750 hrs x 90 = X/4
X =270,000 arbitrary unit

We have only (150- 90)days left to complete the work at 15 hours per person. If total no of people required to complete the remaining job is R
Then

15R x 60 =3/4 X
Note X =270,00

R = 225

Men to be added to previous is 225- 75 = 150 men
brilliant gurl!
Re: Solve This Simple Maths by Tinkybabe(f): 12:12pm On Jan 31, 2016
paranorman:

brilliant gurl!

Paranorman!! Long time!
You maths whiz cheesy
Compliments of the season.
Re: Solve This Simple Maths by paranorman(m): 12:16pm On Jan 31, 2016
Tinkybabe:


Paranorman!! Long time!
You maths whiz cheesy
Compliments of the season.
honestly, I admire you maths skills.
That question you just solved, I hate its likes mehn.. Infact, I gotta do some 'quantifying' before solving such. How have you been?
Re: Solve This Simple Maths by kobonaire(m): 5:17pm On Jan 31, 2016
@Tinkybabe solution is spot-on. I question the legality/ability of people to work 15 hour days for 60 days continually ... grin
Re: Solve This Simple Maths by Tinkybabe(f): 2:57pm On Feb 03, 2016
Thanks Paranorman.

kobonaire:
@Tinkybabe solution is spot-on. I question the legality/ability of people to work 15 hour days for 60 days continually ... grin

Legality is indeed questionable but ability is not only possible but happening .

How are you?
Re: Solve This Simple Maths by kobonaire(m): 4:04pm On Feb 03, 2016
Tinkybabe:
Thanks Paranorman.



Legality is indeed questionable but ability is not only possible but happening .

How are you?
I'm fine thank you my dear, keep up your great work of rockin' in Mathematics and sharing your knowledge...

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