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Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)
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Re: UI 2018/2019 Admission Thread by Gracy3535(f): 6:09pm On Apr 20, 2018 |
Eben331: s=distance/time s=220/9 s=24.4km |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 6:12pm On Apr 20, 2018 |
Eben331: 200=44 220=x 200x=9680 x=48.4km which is correct |
Re: UI 2018/2019 Admission Thread by Eben331: 6:16pm On Apr 20, 2018 |
Gracy3535:both are wrong. let give others the chance to solve, if nobody can't solve it, i will do the correction. Try the other questions. |
Re: UI 2018/2019 Admission Thread by Eben331: 6:18pm On Apr 20, 2018 |
vicstiqs95:I got 3.83m/s. |
Re: UI 2018/2019 Admission Thread by Hardebaryor(m): 6:26pm On Apr 20, 2018 |
Eben331: For the first 200km, the time spent is 200÷44=4.54hrs For the next 220km, the average speed is 220/9-4.54hrs This is because the total time spent is 9hrs 220/4.45 =49.43km/hr. Am I right? |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 6:34pm On Apr 20, 2018 |
Eben331: |
Re: UI 2018/2019 Admission Thread by Eben331: 6:36pm On Apr 20, 2018 |
Hardebaryor:You are correct |
Re: UI 2018/2019 Admission Thread by majormofor(m): 6:49pm On Apr 20, 2018 |
add this number to join ui WhatsApp group +234 708 135 3772 |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 6:52pm On Apr 20, 2018 |
Hardebaryor:oops tanx |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 6:53pm On Apr 20, 2018 |
Eben331:am i correct for the 3answers |
Re: UI 2018/2019 Admission Thread by Eben331: 6:53pm On Apr 20, 2018 |
Gracy3535:All is wrong. |
Re: UI 2018/2019 Admission Thread by Eben331: 6:56pm On Apr 20, 2018 |
Gracy3535:Hint: First find vo(image of objective lens) nd ur new u will be vo, then find ve which is the final image. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 7:37pm On Apr 20, 2018 |
Eben331:i got 30m/s. Pls about dat oscillation wat z d formular u use |
Re: UI 2018/2019 Admission Thread by Hardebaryor(m): 7:44pm On Apr 20, 2018 |
Eben331:1. K.E= mv²/2. P.E=Mgh But P.E=K.E. Hence K.E=mgh Loss in K.E = mg(H-h) = 1×9.8(5-1) =9.8×4 =39.2J Not really sure of this answer 2. Landa(wavelength)= h/mv v=h/landa×velocity v=6.6×10^–34/9.4×10^–31× 1.3×10^–10 v=5.4×10^6m/s 3. Hmm.. I no know am |
Re: UI 2018/2019 Admission Thread by dolapo74: 8:46pm On Apr 20, 2018 |
Eben331:Please ,where did get this questions from? |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 9:26pm On Apr 20, 2018 |
Eben331:...OK bro...only back to solve ur ques |
Re: UI 2018/2019 Admission Thread by Eben331: 9:31pm On Apr 20, 2018 |
Damayogenius18:If you leave us like dat next time, you will be sued...lol. Welcome back. You haven't show us the corrections to ur questions. |
Re: UI 2018/2019 Admission Thread by Eben331: 9:34pm On Apr 20, 2018 |
Gracy3535:I first used h=l(1-costita) and later use v=_/2gh I dnt knw weda it is correct. Can u show how u got 30m/s? |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 9:35pm On Apr 20, 2018 |
Damayogenius18:when u r through wit them come and collect ur cane |
Re: UI 2018/2019 Admission Thread by Eben331: 9:35pm On Apr 20, 2018 |
Hardebaryor:big ups to u bro. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 9:37pm On Apr 20, 2018 |
Eben331:dat ansa was 4 the hint u gave me |
Re: UI 2018/2019 Admission Thread by Eben331: 9:37pm On Apr 20, 2018 |
Gracy3535:That's true. He needs it. Lol |
Re: UI 2018/2019 Admission Thread by Eben331: 9:40pm On Apr 20, 2018 |
Gracy3535:but image distance is supposed to be in cm or m, you mistake ve for velocity. The ans is not correct ooo |
Re: UI 2018/2019 Admission Thread by Hardebaryor(m): 9:42pm On Apr 20, 2018 |
Eben331:Help me with number 3 please |
Re: UI 2018/2019 Admission Thread by Eben331: 9:42pm On Apr 20, 2018 |
dolapo74:is dat important? |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 9:43pm On Apr 20, 2018 |
Eben331:sori jare i mix up d questions value i ll do it again nt nw |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 9:44pm On Apr 20, 2018 |
Eben331:yes o vry important |
Re: UI 2018/2019 Admission Thread by Eben331: 9:45pm On Apr 20, 2018 |
Hardebaryor:Let others try it |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 9:46pm On Apr 20, 2018 |
Eben331:...1..we can calculate it in many....easiest way...1/2mvi^2- 1/2mvf^2....vi=√2gh..√2 *10*5....vi= 10ms^-1. Vf=√2 *1*10.. Vf=4.47.....1/2m(vi^2-vf^2).... 0.5 * 1(100-22)..=0.5 * 1 * 78...=39J...another method...mghinitiall=mghfinal +energy lost...energy lost = mghinitial - mghfinal... Mg(hinitial- hfinal)... 1 * 10(5-1)...=10 *4= 40J...got 39j base or rounding up in first method...I use g= 10 for convenience...should be= 9.81 |
Re: UI 2018/2019 Admission Thread by Eben331: 9:46pm On Apr 20, 2018 |
Gracy3535:Alright. |
Re: UI 2018/2019 Admission Thread by Eben331: 9:54pm On Apr 20, 2018 |
Damayogenius18:you are right bro but u didn't use the parameter given, u were given 9.8m/s2 and nt 10m/s2. You av to be conscious of instruction. UI won't give their parameters in whole number. |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 9:59pm On Apr 20, 2018 |
Guys pls ve been trying to understand hybrization of orbital but it not going any simple defination of it. |
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