I geh some question o my bosses here 1)do ui offer any extramural class 2)I had 239 in utme and I apply 4 linguistic wot my chance uf gaining admission 3)if dere is any watsap group kindly add me. 09065124104 4)I nid ui p.utme past question pls o help me. promise20471@gmail.com

moubba:
http://bc.vc/59LNA5m

Click the link to join UI Aspirants WhatsApp Group

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Hipprocrates:
Add me too pes13, my contact is 08024326975. Thanks in anticipation.

Ntaliban, come and add this, my WhatsApp couldn't read his contact from my phone.

Quote me if you see this, so I could delete his number.

guys any idea how I can be very good in maths

2018/2019. Here we go again.

#MBBS fam.
God will surely do it.

This is going to be Short and Precise
If u know you need Info and Help with Your U.I Admission.... contact 09076966813 on WhatsApp...
NB: Be Responsible while u chat up**

ISISs:
2018/2019. Here we go again. #MBBS fam. God will surely do it.

Boss.
How are you treating UNN because I know UNN can't treat you.

CHEMISTRY

In a nuclear fusion process,four protons each of mass Mp, were fused to produce a nucleus X of mass Mx. Which of the following equations is CORRECT?......
(A) 4Mp > Mx
(B) 4Mp = Mx
(C) 4Mp < Mx
(D) Mp = Mx

CHEMISTRY.


1: If 4g of a radioactive material of half-life 10 days is spilled on a laboratory floor, how long would it take to disintegrate 3.5g of the material?
(A) One and 1/4 days.
(B) Eight and 3/4 days.
(C) 30 days.
(D) 80 days.

2: If 1.20 * 10^5 atoms of a radioactive nuclide decays such that only 1.50 * 10^4 remained after 81 days.The half-life of the radioactive nuclide is....
(A) 21 days
(B) 27 days
(C) 54 days
(D) 81 days


Abeg how do I solve questions like these without calculator


Oga Pes13, Damayogenius18,......and other bosses here help out please....

DrBESTJC:
CHEMISTRY

In a nuclear fusion process,four protons each of mass Mp, were fused to produce a nucleus X of mass Mx. Which of the following equations is CORRECT?......
(A) 4Mp > Mx
(B) 4Mp = Mx
(C) 4Mp < Mx
(D) Mp = Mx

C

DrBESTJC:
CHEMISTRY.


1: If 4g of a radioactive material of half-life 10 days is spilled on a laboratory floor, how long would it take to disintegrate 3.5g of the material?
(A) One and 1/4 days.
(B) Eight and 3/4 days.
(C) 30 days.
(D) 80 days.

2: If 1.20 * 10^5 atoms of a radioactive nuclide decays such that only 1.50 * 10^4 remained after 81 days.The half-life of the radioactive nuclide is....
(A) 21 days
(B) 27 days
(C) 54 days
(D) 81 days


Abeg how do I solve questions like these without calculator


Oga Pes13, Damayogenius18,......and other bosses here help out please....

(1) C (2) B

DrBESTJC:
CHEMISTRY

In a nuclear fusion process,four protons each of mass Mp, were fused to produce a nucleus X of mass Mx. Which of the following equations is CORRECT?......
(A) 4Mp > Mx
(B) 4Mp = Mx
(C) 4Mp < Mx
(D) Mp = Mx

...answer should be A.....4mp> MX...when different masses are added,energy is released...E= mc^2...some of the mass of the added proton is converted to energy...the energy is called binding energy.....normally,we know that all nuclei have lesser mass than the sum of individual nucleus that form them...

Ok

DrBESTJC:
CHEMISTRY.


1: If 4g of a radioactive material of half-life 10 days is spilled on a laboratory floor, how long would it take to disintegrate 3.5g of the material?
(A) One and 1/4 days.
(B) Eight and 3/4 days.
(C) 30 days.
(D) 80 days.

2: If 1.20 * 10^5 atoms of a radioactive nuclide decays such that only 1.50 * 10^4 remained after 81 days.The half-life of the radioactive nuclide is....
(A) 21 days
(B) 27 days
(C) 54 days
(D) 81 days


Abeg how do I solve questions like these without calculator


Oga Pes13, Damayogenius18,......and other bosses here help out please....

.....for no 1...you can do it did way without calculator....
N/No = 1/2 ^n ...where n= half-life/timtaken to disintegrate...I.e
n = t/(t 1/2)...N= number of nuclei dat has disintegrated...No= Number of nuclei originally present....in this question, No=4g while N = 4 - 3.5 = 0.5...be careful here...a lot of ppl make sis mistake...3.5g is the no that has disintegrated while 0.5g is no remaining....so we have
0.5/4 = 1/2^n...0.5= 1/2..so we can say
(1/2 * 1/4)= 1/2^n
1/8 =1/2^n..now we use index form
2^-3 = (2^-1)n...2 on each side cancel remaining the powers..so
-3 = -n...so...n= 3.....
But remember that n = t/(t 1/2)= 10 days...so
t = t 1/2 * n...= 3 * 10days
= 30 days.....
U can do the second question dis way too....but der are some complicates one u cant do dis way
But I dont think UI can set dat in post utme
It is very simple and easy to do dis way...the reason it is too long is because am explaining.....
Hope u found it useful...

Eben331:
C

....bro, how r u...long time..

Damayogenius18:
....bro, how r u...long time..

I am cool. U? longtime bro, visit often. Pls check ur mail.

Damayogenius18:
.....for no 1...you can do it did way without calculator....
N/No = 1/2 ^n ...where n= half-life/timtaken to disintegrate...I.e
n =( t1/2)/t....N= number of nuclei dat has disintegrated...No= Number of nuclei originally present....in this question, No=4g while N = 4 - 3.5 = 0.5...be careful here...a lot of ppl make sis mistake...3.5g is the no that has disintegrated while 0.5g is no remaining....so we have
0.5/4 = 1/2^n...0.5= 1/2..so we can say
(1/2 * 1/4)= 1/2^n
1/8 =1/2^n..now we use index form
2^-3 = (2^-1)n...2 on each side cancel remaining the powers..so
-3 = -n...so...n= 3.....
But remember that n = (t1/2) /t...t = 10 days...so
T1/2 = t * n...= 3 * 10days
= 30 days.....

since n=(t1/2)/t where t1/2=half-life, t=time to disintegrate. if n=3 and we were askd to find t and not t1/2, then it should be: 3=10/t t=10/3 Correct yourself there. I knw it might be a slip of mind. No offence meant bro.

Damayogenius18:
.....for no 1...you can do it did way without calculator....
N/No = 1/2 ^n ...where n= half-life/timtaken to disintegrate...I.e
n =( t1/2)/t....N= number of nuclei dat has disintegrated...No= Number of nuclei originally present....in this question, No=4g while N = 4 - 3.5 = 0.5...be careful here...a lot of ppl make sis mistake...3.5g is the no that has disintegrated while 0.5g is no remaining....so we have
0.5/4 = 1/2^n...0.5= 1/2..so we can say
(1/2 * 1/4)= 1/2^n
1/8 =1/2^n..now we use index form
2^-3 = (2^-1)n...2 on each side cancel remaining the powers..so
-3 = -n...so...n= 3.....
But remember that n = (t1/2) /t...t = 10 days...so
T1/2 = t * n...= 3 * 10days
= 30 days.....
U can do the second question dis way too....but der are some complicates one u cant do dis way
But I dont think UI can set dat in post utme
It is very simple and easy to do dis way...the reason it is too long is because am explaining.....
Hope u found it useful...

Yesss!.......I've got it.......Thanks a lot.

My answer to number 2 is B(27 days)

Damayogenius18:
...answer should be A.....4mp> MX...when different masses are added,energy is released...E= mc^2...some of the mass of the added proton is converted to energy...the energy is called binding energy.....normally,we know that all nuclei have lesser mass than the sum of individual nucleus that form them...

Very Correct.....

.

boyejo124:




oga Pes13
pls which course would you recommend for an Average student(65%)to study? my preference are
Medical laboratory science
Dentistry
Agricultural economics.
I scored 30* in jamb,and am very good in Biology,good in chemistry, and fair in physics.
I like health related course,but one that can put food on one's table in Nigeria's economy.
but I learnt UI has increased its tuition fee of medical students, which is giving me second thought of medical school (college of medicine as a whole)
that's why I chosed Agric economics.but I want to change to any of the above.
advice also needed from oda bosses and readers,I really need advice before i go for change of course on Monday.
damayogenius18
Eben331
yusman14
hardebaryor
dannyboii1
samsonyte
& others

jst lyk everyone have said go for the course u ave passion for, u knw the future u can't picture u can't feature in it, why dont u start to imagine the kind of lyf want to live in future becos urimagination>determination>desperation>success, everything still revolve around passion becos if u dnt imagine it, u can never have passion for it.

hi pls I'm new here,I'm Joe by name,an aspirant of ui.
I'm aspiring to study mbbs,pls I got some past questions and answers here with me in pdf format,but I'm ain't satisfied with the Bleep,so pls if you are having ui past questions too in PDF format, whatapp me for us to exchange questions and answer dat I bought online.09030109240.

Hy am nw on watsapp shuld i send my number

Damayogenius18:
....bro, how r u...long time..

Eben331:
since n=(t1/2)/t where t1/2=half-life, t=time to disintegrate. if n=3 and we were askd to find t and not t1/2, then it should be: 3=10/t t=10/3 Correct yourself there. I knw it might be a slip of mind. No offence meant bro.

....yea...n = t/(t1/2)...

Gracy3535:
Hy am nw on watsapp shuld i send my number

....OK...send it....

Damayogenius18:
....OK...send it....

08094258273 pls edit wen u ve seen it

CHEMISTRY.

Two radioactive elements P and Q initially have the same mass.If their half-lives are 10 and 5 years, the ratio of their masses(ie. P:Q) after 20 years is.....
(A) 4:1
(B) 2:1
(C) 1:2
(D) 1:4


This question is somehow ambiguous to me.Please,I need explanations to the right answer.

Gracy3535:
08094258273 pls edit wen u ve seen it

..u can modify it and delete it

Damayogenius18, pls check ur mail.

DrBESTJC:
CHEMISTRY.

Two radioactive elements P and Q initially have the same mass.If their half-lives are 10 and 5 years, the ratio of their masses(ie. P:Q) after 20 years is.....
(A) 4:1
(B) 2:1
(C) 1:2
(D) 1:4


This question is somehow ambiguous to me.Please,I need explanations to the right answer.

(A) 4:1 The bosses should explain.

DrBESTJC:
CHEMISTRY.

Two radioactive elements P and Q initially have the same mass.If their half-lives are 10 and 5 years, the ratio of their masses(ie. P:Q) after 20 years is.....
(A) 4:1
(B) 2:1
(C) 1:2
(D) 1:4


This question is somehow ambiguous to me.Please,I need explanations to the right answer.

..OK bro...the nuclei has d same mass but there half life is different..N/No = 1/2 (t/t1/2)...No is constant for both...
Np/No= 1/2^ 20/10..= {1/2}^ 2..Np/No= 1/4...Nq /No..= {1/2}^20/5...= {1/2}^4....Nq/No =1/16...
No cancel cos its d same for both....so
Np/Nq = {1/4 } ÷{1/16}...open d bracket..
Np/Nq= 1/4 × 16/1...
Np/Nq = 4/1 or 4 : 1....you can use this formula for any radioactive calculation..you just need to understand d question..