₦airaland Forum

Homguy:
hello friends,
please, how can I solve this puzzle?
I want to break a string with several letters and no spaces into a list. what method can I call on it?
for example:
card = 'AGDTDGATDGATDGATGDTGADGATDGATDGTAGATDGATDGATDGADTGADGTADGTAGDTADGTA'
how can I break this into a list with strings of 3 chars each? A list like ['AGD', 'TDG', 'ATD'...].


What I have done;
I have used the split() method but it does not work nor give the desired result, as it requires a delimiter and there's no sort of delimiter in this random code.
cc;
Snwokenk
Darivie04
dragnet

Modified:
So this is how i got the result i wanted using string indexing and reiteration as advised earlier.

hay = 'SAYPAYLAYKAYTAY'
n=3
print([hay[item:item +n] for item in range(0, len(hay), n)])
Result: ['SAY','PAY','LAY','KAY','TAY']

Homguy:
hello friends,
please, how can I solve this puzzle?
I want to break a string with several letters and no spaces into a list. what method can I call on it?
for example:
card = 'AGDTDGATDGATDGATGDTGADGATDGATDGTAGATDGATDGATDGADTGADGTADGTAGDTADGTA'
how can I break this into a list with strings of 3 chars each? A list like ['AGD', 'TDG', 'ATD'...].


What I have done;
I have used the split() method but it does not work nor give the desired result, as it requires a delimiter and there's no sort of delimiter in this random code.
cc;
Snwokenk
Darivie04
dragnet

x = 0
while x < len(card):
print card[x:x+3]
x = x+3

Edit*
list = []
count = 0
while count < len(card):
n = card[count:count+3]
list.append(n)
count+=3

Homguy:
Modified:
So this is how i got the result i wanted using string indexing and reiteration as advised earlier.

hay = 'SAYPAYLAYKAYTAY'
n=3
print([hay[item:item +n] for item in range(0, len(hay), n)])
Result: ['SAY','PAY','LAY','KAY','TAY']

This is great! haven't been on Nairaland for a while. my apologies