₦airaland Forum

Many see my shapes as useless because the don't know its usefulness,
Some say why not make robots
But how will I understand robotics without in-depth knowledge on circle
Abeg make we solve.
This one is easy
Try it out

Find the area if the shade portion

Any one

ifada123:
Many see my shapes as useless because the don't know its usefulness,
Some say why not make robots
But how will I understand robotics without in-depth knowledge on circle
Abeg make we solve.
This one is easy
Try it out

answer is 27.39cm²

ifada123:
Any one

A = -119[cos^-¹(5/13)] + 12(6π - 5) ≈ 26.25 unit²

Martinez39:


A = -119[cos^-¹(5/13)] + 12(6π - 5) ≈ 26.25 unit²

You are correct
√√√√√√√√
Let me show full derived solution

Workings here

dejt4u:
answer is 27.39cm²

Maybe you approximated too earlier
If you can show your workings we will appreciate sir

ifada123:
Many see my shapes as useless because the don't know its usefulness,
Some say why not make robots
But how will I understand robotics without in-depth knowledge on circle
Abeg make we solve.
This one is easy
Try it out

You don't need in depth knowledge of a circle to build a robot naw

Darivie04:
You don't need in depth knowledge of a circle to build a robot naw

We are not doing in depth knowledge of maths here, this is basic secondary school maths and you even need more than this to design a robot,
I don't mean to assemble robot,
Go check on what brings about upward and downward movement in mechanical device

(Area of big sector - area of big triangle) + (Area of small sector - area of small triangle)

45.2°/360 *3.142* 12² - 1/2 *144 sin 45.2°

= 56.807 - 51.089
= 5.718sq units

134.74°/360 *3.142*5² - 1/2* 25 sin 134.74°

= 29.3995 - 8.879
= 20.5205sq units

Shaded portion area = 5.718 + 20.5205 = 26.24 sq units