GenBuhari:
5/6

APCLyingBastard:


Provide reasons

Nova1988:
Op you that knows it now are you richer than dangote is this helping you in anyway of your life. You see this is the reason why so many people are poor, instead of you to go and learn a high income skill that will help you in your life you are here calling people olodo because you can solve stupid math that they cannot solve. Please tell me where that math has taken you in life but I'm not surprised because it's not your fault, I blame school for all the useless youth we have in this country, so op instead of you to come here and tell us to solve stupid math please use your time to go and Learn a high income skill like copywriting, email marketing, SEO, Internet marketing etc and come and thank me later because this math you know will not take you anywhere.


PEACE

APCLyingBastard:
IQ tests need to be mandatory to post here. So I am kicking it off with this very rudimentary test.

Provide reasons for your answer.

See pic below for test.

Rexmy:

Firstly, since the first ball you selected is gold, then you are likely to have selected from either of 2 boxes.
Secondly, since you are thinking of selecting another gold ball, then your concern is on 1 box i.e. box with
Hence, the Pr(selecting another gold ball) = number of box with /total number of boxes = 1/3

APCLyingBastard:
wrong

APCLyingBastard:
Test 2

Level 2

You pass this and I will follow you.

Enoch07:

okay, when I post pls call sars, or efcc for me you hear

BabaRamota1980:


God knock you back to Mars where you came from. Yeye

Rexmy:

Well another way to it is that since it can either be the box with or GS, that means at the initial stage there are 3 G balls and 1 S ball that could be selected. Since selection is without replacement and a G ball had been selected, then there are 2 possible G balls left to be selected after initial selection i.e. 2 G balls and 1 S ball are left after initial selection. As such,
Pr(selecting G ball again) = number of G balls left ÷ number of total balls left
= 2/3

GenBuhari:
Its 1/2 its Simply 1/3+1/6. I mistakenly multiplied by 2/3 when it wasn't necessary

Otutu1:
It is a 50% probability

FisifunKododada:

Here is my explanation for test 1 assuming randomized boxes after 1st gold pick. Answer = 1/3 :


1. You start with one state. Lets call this state the /GS/SS state.

2. After picking a gold ball (P = 2/3), you now have two possible states: (1) /S/SS state OR (2) G/GS/SS state. The (1) is the state if the gold ball was picked from the GS box. And the (2) state is if the gold ball was picked from the box.

3. Assuming we are only interested in what happens after the 1st gold ball was picked. Then the probability of picking a second gold ball from the same box = (a) the prob. of picking from the same box in the /S/SS state + (a) the prob. of picking from the same box in the G/GS/SS state.

(a) = 0 since the same box only have a silver ball in it. (b) = 1/3 since the same box has one gold ball left in it and the prob. of picking that box is still 1/3.

Therefore the answer is: 0 + 1/3 = 1/3

Here is my explanation for test 2 answer 3/4 :


this is simply the probability of 25% been the answer (2/4) plus the probability of the correct answer if 25% is not the answer (1/4). Put in another way, basically, if 25% is NOT the answer then 3 of the options are wrong so that means the probability of getting right is 1/4. But if 25% is the answer then only 2 of the options are wrong, that means the probability of getting right is 2/4. The sum gives you 3/4.

Waiting for Test 3.

APCLyingBastard:



Let me put you out of your pathetic ignorance and misery.

let me provide the LOGIC behind the answer which is 1/2 or 50%.

You have 6 balls , 3 gold and 3 silver arranged in 3 boxes with 2 gold, 2 silver and one of either in separate boxes.

You draw a gold ball.

The question that was asked is what is the probability of you drawing a second ball from the same box?

That means you drew from either the box with 2 gold balls or the one with a single gold and silver ball.
Now you have only 3 balls left in two boxes where you had gold balls
The chances of you having drawn a gold ball from the box with either 2 gold balls or a single gold ball is inconsequential as the main question is the follow-up event of drawing a second ball.
Hence, you are left with deciding if your first draw was from either the box with 2 gold balls or the one with a single gold and a single silver ball.
The probability that you will pick a gold ball is 50% because if you drew from the first box with 2 gold balls , it would have been 100% but then again you might have drawn from the second box with a single gold ball and a silver ball.
So you are either going to pick a Gold ball (if you selected from the first box) or a silver ball (if your first draw was from the second).

FisifunKododada:
Here is my explanation for test 1 assuming randomized boxes after 1st gold pick. Answer = 1/3 :

1. You start with one state. Lets call this state the /GS/SS state.

2. After picking a gold ball (P = 2/3), you now have two possible states: (1) /S/SS state OR (2) G/GS/SS state. The (1) is the state if the gold ball was picked from the GS box. And the (2) state is if the gold ball was picked from the box.

3. Assuming we are only interested in what happens after the 1st gold ball was picked. Then the probability of picking a second gold ball from the same box = (a) the prob. of picking from the same box in the /S/SS state + (a) the prob. of picking from the same box in the G/GS/SS state.

(a) = 0 since the same box only have a silver ball in it. (b) = 1/3 since the same box has one gold ball left in it and the prob. of picking that box is still 1/3.

Therefore the answer is: 0 + 1/3 = 1/3

Here is my explanation for test 2 answer 3/4 :


this is simply the probability of 25% been the answer (2/4) plus the probability of the correct answer if 25% is not the answer (1/4). Put in another way, basically, if 25% is NOT the answer then 3 of the options are wrong so that means the probability of getting right is 1/4. But if 25% is the answer then only 2 of the options are wrong, that means the probability of getting right is 2/4. The sum gives you 3/4.

Waiting for Test 3.

APCLyingBastard:
Test 2

Level 2

You pass this and I will follow you.

APCLyingBastard:
IQ tests need to be mandatory to post here. So I am kicking it off with this very rudimentary test.

Provide reasons for your answer.

See pic below for test.

femi4:
1/4 =25% Don't follow me

DesChyko:
I would say[b] 1/9.[/b]
I'm looking beyond the balls to focus on the box instead.
Choose same box twice.
The reason for me doing this is that the question is really centered on the box. By eliminating two boxes from the question, it's quite obvious their balls don't count.