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The resistance Rt of a substance at temperature t°c which is measured by a Mercury thermometer is
Rt=Ro/1+∆t^2
where Ro is the resistance of the substance at 0°c and ∆=5.0×10^-5, calculate the resistance of the substance at 100°c and 80°c,if the Resistance of the substance is used as a thermometric property for a resistance thermometer, what will the resistance thermometer read when a Mercury thermometer reads 100°c and 80°c ? comment on your answer.

please l really need someone to help me solve the calculation,l have exhausted every knowledge l have and they gave this assignment to my sister studying in polytechnic.

I almost run mad trying to calculate that shit
Bloodclattt!!

First you are to calculate what Ro is by setting Rt to Zero so as to know the resistance at t = 0 degress celsius that is if it is not a contant for every material. Once you have determined the value of Ro; do your calculation for Rt when t=80 and t = 100.

Try it out... If it still proves difficult, let me know

emillysmigael:
First you are to calculate what Ro is by setting Rt to Zero so as to know the resistance at t = 0 degress celsius that is if it is not a contant for every material. Once you have determined the value of Ro; do your calculation for Rt when t=80 and t = 100.

Try it out... If it still proves difficult, let me know

Person say make u solve something for am u come complicate the issue come tell am say may him solve? Typical of our naija teachers.

oocyte:
The resistance Rt of a substance at temperature t°c which is measured by a Mercury thermometer is
Rt=Ro/1+∆t^2
where Ro is the resistance of the substance at 0°c and ∆=5.0×10^-5, calculate the resistance of the substance at 100°c and 80°c,if the Resistance of the substance is used as a thermometric property for a resistance thermometer, what will the resistance thermometer read when a Mercury thermometer reads 100°c and 80°c ? comment on your answer.

please l really need someone to help me solve the calculation,l have exhausted every knowledge l have and they gave this assignment to my sister studying in polytechnic.

be like shorthand for my face

ArewaOduduwaBia:
Person say make u solve something for am u come complicate the issue come tell am say may him solve? Typical of our naija teachers.

It is better to know the process to take than for me to provide just the answer. Exam still come and he/she will have to provide the workings.

That year wey my brain dey hot for physics, all these na look and solve...
That year shaa
.

oocyte:
The resistance Rt of a substance at temperature t°c which is measured by a Mercury thermometer is
Rt=Ro/1+∆t^2
where Ro is the resistance of the substance at 0°c and ∆=5.0×10^-5, calculate the resistance of the substance at 100°c and 80°c,if the Resistance of the substance is used as a thermometric property for a resistance thermometer, what will the resistance thermometer read when a Mercury thermometer reads 100°c and 80°c ? comment on your answer.

please l really need someone to help me solve the calculation,l have exhausted every knowledge l have and they gave this assignment to my sister studying in polytechnic.

go through this first,i will complete it later.......busy for now

NDSMELODY:
go through this first,i will complete it later.......busy for now

you are teaching that guy to be dubbing ba? @emillysmigael has done the right thing

sinkhole:
you are teaching that guy to be dubbing ba? @emillysmigael has done the right thing

i think it is an assigment he need help

.

oocyte:
The resistance Rt of a substance at temperature t°c which is measured by a Mercury thermometer is
Rt=Ro/1+∆t^2
where Ro is the resistance of the substance at 0°c and ∆=5.0×10^-5, calculate the resistance of the substance at 100°c and 80°c,if the Resistance of the substance is used as a thermometric property for a resistance thermometer, what will the resistance thermometer read when a Mercury thermometer reads 100°c and 80°c ? comment on your answer.

please l really need someone to help me solve the calculation,l have exhausted every knowledge l have and they gave this assignment to my sister studying in polytechnic.

remaining part NOTE s,i unit is ohm and not degre celcius as written in the solution i made a mistake.......for the comment aspect u input those values in the formular provided to get temperature reading said "as resistance increases,temperature............. And as resistance decreases,temperature........."

Well... Some people sha...

oocyte:
The resistance Rt of a substance at temperature t°c which is measured by a Mercury thermometer is
Rt=Ro/1+∆t^2
where Ro is the resistance of the substance at 0°c and ∆=5.0×10^-5, calculate the resistance of the substance at 100°c and 80°c,if the Resistance of the substance is used as a thermometric property for a resistance thermometer, what will the resistance thermometer read when a Mercury thermometer reads 100°c and 80°c ? comment on your answer.

please l really need someone to help me solve the calculation,l have exhausted every knowledge l have and they gave this assignment to my sister studying in polytechnic.

As a science student, it's been ages I touched physics or math — I only know how to calculate money now. I'm more into practical now, not theories. Sorry I couldn't help.

Ekemeze:
see as thread dry. if it were to be about nude, BBN, thread would've been upto 10pages by now

lol especially any trend with laycon

ArewaOduduwaBia:
Person say make u solve something for am u come complicate the issue come tell am say may him solve? Typical of our naija teachers.

Don't mind her, if they owe her salary now she will start complaining.

Uyi168:
That year wey my brain dey hot for physics, all these na look and solve...
That year shaa
.

lol

NDSMELODY:
remaining part NOTE s,i unit is ohm and not degre celcius as written in the solution i made a mistake.......for the comment aspect u input those values in the formular provided to get temperature reading said "as resistance increases,temperature............. And as resistance decreases,temperature........."

Thanks for the help.

we can't do without Google

What we don't understand is that these people are setting past questions for us. Any assignments given to me my junior ones, I don't have any problem if I am with a phone.

If I can't find the right answer, I will surely find examples.