₦airaland Forum

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ChikezieU:
Enugu

that's cool. new or fairly used?

ChikezieU:
Good morning house
please how good and reliable is Sony Experia/Ericsson phone's. As phones are becoming expensive now, Sony Experia seems to be more affordable now, for instance Experia AX is 25k.

where?

always wanted to become a mechanical engineer since I began reading written words .....but currently at the verge of becoming an electrical engineer, by His grace.

Xtraordinary2019:
Sell has shortlisted

when please?

codeigniter:
def collatz ():
if number % 2 == 0:
return number // 2
elif number % 2 == 1:
return 3 * number + 1

number = int(input())

while number != 1:
number = collatz ()
print(number)

sorry for d indentation
I have answer dis question b4,

before u ask question use the search bar to see if such question has not been asked before

join www.africonn.com
I hope this helps

Taofeekdboy:
I will give you a hint, the best to use for this practice is recursive function. It calls itself. Please read more on it.

saheedniyi22:
I remember this from automate the boring stuff with Python, I couldn't solve it then let me try it now.

Najdorf:
It hasn't been proved that it works for all positive integers.

What's the problem though? The problem looks straightforward.

stanliwise:
@SPLENDID25
What have you coded so far?. Are you experiencing some issues or what?

I successfully written the program. Thanks to everyone for his or her contributions.

stanliwise:
if it fails to return 1 then it means your loop is infinite.
Try to input value that could make your function return 1

def collatz (number):
	if number % 2 == 0:
		return number // 2
	else:
		return 3 * number + 1
number = int(input())
collatz (number)
print (collatz (number))
while collatz (number) != 1:
	print (collatz (number))

the program above did with 2 as input, but if the returned value isn't 1, it prints the returned value infinitely.

codeigniter:
is that not the problem u want to solve

I mean, using your code. Every input returned 1 and the program terminates. its not supposed to be that way.

stanliwise:
When is your while loop suppose to terminate?

when the returned value equals 1.

stanliwise:
use the input() functionality.
To get integer you can use:
int(input(“input a number”))

Just store it a variable and you can attach it to a while loop to keep calling it.

def collatz (number):
 	if number % 2 == 0:
 		return number // 2
 	else:
 		return 3 * number + 1
 number = int(input())

I used the while loop, followed by invoking the function. all it did was to continue printing the returned value.

codeigniter:
def collatz ():
if number % 2 == 0:
return number // 2
elif number % 2 == 1:
return 3 * number + 1

number = int(input())

while number != 1:
number = collatz ()
print(number)

sorry for d indentation
I have answer dis question b4,

before u ask question use the search bar to see if such question has not been asked before

join www.africonn.com
I hope this helps

Sir, every input returned 1 and the program ends.

Taofeekdboy:
I will give you a hint, the best to use for this practice is recursive function. It calls itself. Please read more on it.

okay I will. thanks

stanliwise:
what language are you using??

Python

Najdorf:
It hasn't been proved that it works for all positive integers.

What's the problem though? The problem looks straightforward.

I need hints on how to go about the problem. I have been thinking, for the past three days now.

stanliwise:
@SPLENDID25
What have you coded so far?. Are you experiencing some issues or what?

I am actually a beginner. its actually a practice problem. I was able to write the function, but unable to write the part that should call the function and ask for an input provided the returned value isn't 1. I need hints from seniors.

Write a function named collatz() that has one parameter named number. If number is even, then collatz() should print number // 2 and return this value. If number is odd, then collatz() should print and return 3 * number + 1. Then write a program that lets the user type in an integer and that keeps calling collatz() on that number until the function returns the value 1. (Amazingly enough, this sequence actually works for any integer—sooner or later, using this sequence, you’ll arrive at 1! Even mathematicians aren’t sure why. Your program is exploring what’s called the Collatz sequence, sometimes called “the simplest impossible math problem.”) Remember to convert the return value from input() to an integer with the int() function; otherwise, it will be a string value. Hint: An integer number is even if number % 2 == 0, and it’s odd if number % 2 == 1.

Loris576:
Seriously ?
Has spdc shortlisted ?

did you apply for snepco? if yes steps and hints please.
Anyone seeing this and has applied can also say something.

mujibson:
4.76 is kinda competitive. Let's hope they've not clandestinely shortlisted those they need.

About the snepco. I've uploaded all my documents and details on scholastica since last year. The only thing I added this year was my 100l Cgpa. Since I've uploaded all the necessary documents earlier, all I just did for Snepco application was clicking the 'Apply button' and I submitted. I don't know much about the procedure.

ok

mujibson:
A friend said he knows someone who is shortlisted. I don't know if it's true though. Just that anything can happen. Shell is the most competitive scholarship scheme.

By the way, what's your CGPA and jamb score? Let's start from that.

my jamb score is 234, and my 100level cgpa is 4.76.
meanwhile, i am finding it difficult applying(i can't find the 'submit' button) for the nnpc/snepco. Hints and brief procedure will be highly appreciated.

has shell spdc shortlisted applicants names for the 2019/2020 that ended February this year scholarship award?

yusman14:
Yeah...

me too please, Valentinefelix6@gmail.com

Maj196:
Methane gas (CH4)

exactly, even corpse can go up on flames.

marveworld is right.
no.2 is 1.2056

??