₦airaland Forum

I factory reset my receiver and the Nashare option disappeared. please how can I restore it?

davodyguy:
Yiu need to buy IPTV account first

How do I go about please

Greetings to you all.
I have SKY-SATS ULTRA 9900 HD PRO MAX FTA receiver and it has IPTV function, please how can I enjoy their service?

sundaylinus:
I need a help fellows, the attached image is a sample of my data to be analyse. I tried worked on weighted mean score which the score is outside right of the table, please help me check if i am on point. And what other statistical analysis could sweet this kind of data?

please help me gurus in the forum, I can even pay for this.

donPhill:
try Anova or chisquare analysis

please put me through am not good in statistics

I need a help fellows, the attached image is a sample of my data to be analyse. I tried worked on weighted mean score which the score is outside right of the table, please help me check if i am on point. And what other statistical analysis could sweet this kind of data?

SegaWarrior:
Not all Nigcomsat Channels are showing in this frequency.
eg, NTA LIBERTY, MBC2, MBC ACTION not showing etc. but TVC NEWS, MBC MAX is showing, please any solution to make all Channels appear.? thanks

But these are almost same channels I'm getting on 12520 h 29500 on nilesat 28°E

Is SONYPIX on free to air?

i am a total novice on this final year project things. please i need help. my topic is "pasture poisonous plants and their effects".

benny1620:
Lets use

E(x) = m =Np

known that 1= q+p

P(boy) =P(girl) =1/2

1/2 =p =q

N=500

n=5

by binomial distribution

P(X=r) = nCr*q^(n-r) * p^r

a) P(X=r=2) =5C2*(1/2)⁵ = 10/32

we would expect (500)(10/32) =5000/32 … finish up

b) P(r>1) =p(2) +p(3)+p(4) +p(5) = .... finish up then multiply your answer by 500

c) p(r <2) = p(0) +p(1) ..... similar as former




hope you get...

pls. Benny put more light, this topic was introduced to us by this assignment and we are to submit it on 20th pls.

pls help with this...
Out of 500 families with 5 children each, how many would you expect to have:
(a)exactly 2 boys
(b)more than 1 boy
(c)less than 2 boys
roundup ur answer tothe nearest whole number.

this is where i always gets my maths probs sol. But this one is out of maths. please no insult, Pls
any android guru may help
me out, my phamtom A+,
when i dail a number to
make call, the screen just go blank and the call is still
going. Pls help to fix it

Pls. any android guru may help
me out, my phamtom A+,
when i dail a number to
make call, the screen just go blank and the call still
go. Pls help to fix it

help me with this once again. Sove By quadratic equation. If α and β are the roots of equation 3x²+5x-8=0. Find the value of α^4-ß^4

dejt4u: do it dis way,
α⁴-ß⁴ = (α²)²-(ß²)² = (α²-ß²)(α²+ß²)...diff. Of 2 squares;

simplifying further,
(α-ß)(α+ß)((α+ß)²-2αß)..

You can continue from there..
Note that: (α-ß) = (α²+ß²-2αß)^1/2 = ((α+ß)²-4αß)^1/2

dejt4u: do it dis way,
α⁴-ß⁴ = (α²)²-(ß²)² = (α²-ß²)(α²+ß²)...diff. Of 2 squares;

simplifying further,
(α-ß)(α+ß)((α+ß)²-2αß)..

You can continue from there..
Note that: (α-ß) = (α²+ß²-2αß)^1/2 = ((α+ß)²-4αß)^1/2

dejt4u: do it dis way,
α⁴-ß⁴ = (α²)²-(ß²)² = (α²-ß²)(α²+ß²)...diff. Of 2 squares;

simplifying further,
(α-ß)(α+ß)((α+ß)²-2αß)..

You can continue from there..
Note that: (α-ß) = (α²+ß²-2αß)^1/2 = ((α+ß)²-4αß)^1/2

thanks bro. But am confuse i dnt have idear on this, its an assigment pls put more light

please help
me with this:
If α and β are the roots of
equation 3x²+5x-8=0
Find the value of α^4-ß^4

any mathematics guru in da house may please help me with this:
If α and β are the roots of equation 3x²+5x-8=0
Find the value of α^4-ß^4