₦airaland Forum

Pes13:
Scromatan, you composed that thing yourself.

I saw it on VC's page

scromatan:
UNIVERSITY OF IBADAN
2018/2019 POST-UTME RESULTS AND PROCESSING OF ADMISSIONS
You will recall that the Post-UTME Screening for the 2018/2019 Admission Exercise at the University of Ibadan held on Friday 14th September and Saturday 15th September, 2018. The conduct of the screening has been adjudged to be quite outstanding by all the parties concerned including the candidates themselves, their parents and guardians.
A total of 17,956 candidates sat for the screening. Out of these, 11,730 scored 50% and above, this representing 65.3% of the total number of candidates. For the avoidance of doubt, only those candidates who scored 50% and above are eligible for consideration for admission.
The highest score at the Post-UTME screening was by Anyanwu Favour Chinazaekpere who obtained 90%, and is seeking admission into Communication and Language Arts. Other high scorers at the Post UTME include four candidates who scored 89% and five candidates who scored 88%.

Table 1: Name and performance of top scorers at the UI Post-UTME for 2018/2019

Name Post-UTME Score (%)
Anyanwu Favour Chinazaekpere 90
Chineke Ugochukwu Romanus 89
Ifejika Vincent Ikechukwu 89
Ogunjimi Deborah Temitope 89
Olaniran Oluwamayomikun Eunice 89
Adebayo Akinkunmi Emmanuel 88
Onakoya Precious Olubusayo 88
Adeleye Oreoluwa Boluwatife 88
Abraham Faith Ifeoluwapo 88
Matthew Shalom Olaoluwa 88

The aggregate score for each candidate has since been computed and same communicated to the candidates on their admission portals.
The next stage is for meetings of the Faculty Admissions Committee to be convened to select candidates for admission by setting the cut-off marks from the aggregate scores. The criteria for these include Merit, Catchment and Educationally-Less-Developed States. The meetings will hold from Wednesday, 26th September till Friday, 28th September, 2018. The list of admitted candidates will be published soon after.

While we appreciate the anxiety by the candidates and their parents and guardians, we strongly appeal to all our stakeholders to exercise a little more patience while the decisions of the various Admissions Committees would be communicated as soon as possible.

Thank you and God bless.

Idowu Olayinka
Vice-Chancellor
University of Ibadan
Ibadan
Wednesday, 25 September 2018

You go fear p.ume marks!!!

Pes13:
If senate meeting holds today, it will be out tomorrow. It depends on when they decide to have a sitting.

Been hearing cutoff for medicine and surgery is likely to be 78. . How true is this?

Eben331, how was your exam?

Can you post questions you remember?

freshsteph:
F-fr=ma

U=a/g

0.02=a/10

a=0.2

F-(0.02×150)=15(0.2)

F=3 +3

F=6N

no option

The answer is 2.94N..

Frictional is equal force required to push it since the block isn't accelerating

F- UR
F - 0.02 x 9.8x 15
F - 2.94N

Oluwatobex:
Pls folk, where is 'DLC Lect T' located

I'm also having my exam on Saturday, DLC

Eben331:
Pes13, Nltaliban, Ajet001 and other stallites, please this is the time we need you most now. Help us out with the venues of the examination. Thanks in advance.

What date, time and venue are you writing?

Eben331:
An object gives a real image, magnified four times at 120cm from the second principal focus. Find the focal length of the lens (a) 30cm (b) 40cm (c) 60cm (d) 80cm PLS SHOW UR WORKINGS!!

60cm.. If it's correct, I'll drop solution..

Post with solutions..

No guts no glory

1. Calculate the volume of hydrogen that would be liberated by dissolving 2.40g of calcium in water at 27C and 100kNm^2

Ca + 2H2O --- Ca(OH)2 + H2..

2. Iron is produced from its pretty according to the equation :

2Fe2O3 + 3CO --- 4Fe + 3CO2
Calculate the percentage yield, if 500 tonnes of the one produced 145 tonnes of iron..

3. Glycine, an amino acid, has one nitrogen atom per molecule. If the percentage by mass of Nitrogen in glycine is 18.7%. Calculate the relative molecular mass of the amino acid

4. Why is Hydrogen fluoride a liquid at room temperature, unlike hydrogen chloride

5. Orbitals with the same energy are called what?

6. When Cao is heated to a very high temperature, it emits a light termed?

7. All the following properties are true of solids Except
A. cannot be compressed
B. Does not evaporate
C. Has a definite weight
D. Has a definite shape
E. Has a definite volume

8. Calculate the volume of CO2 released when 30dm^3 of air was passed over an excess of red hot coke. (All gas volumes measured at the same temperature and pressure. Air is about 20% oxygen by volume)

9. What is the colour of bromothyl blue in acidic solution

10. What is the general formula of a double salt?

SammieDollyP:
Thanks bro, I do know.
But having 82 this year might even be risky.
Lautech cut off this year for MBBS is 73% Also Uniben is 77%

UI is likely to rise far above the usual, And, this' my Fear.

Does Uniben release her cut off mark??
Besides, you can not predict these things until after p.ume

SammieDollyP:
Not too encouraging tho' 252.
Least XPected it.

Nice one..
Hit 80+ for your p.ume. . You can do it..

SammieDollyP:
I love the activities here, I'm Sammie by nick, and New here.
An aspirant also of UI, Hope to gain and learn together with my seniors here.
I Rep Medics
Thanks.

Your jamb score?

freshsteph:
almost sire......try again

66.7N

freshsteph:
yeah I've done that....



the cost of electricity that liberated 1g of Magnesium is #5, find the cost of electricity that would liberate 10g of Aluminium....

6.67 Naira?

Dellybanky:
astic movement is (a) Response to light stimulus (b) Non-directorial (c) Directorial (d) Phototropic (e) Response to internal stimulusHow many nuclei is found in the Pollen lube after fertilization? (a) 2 (b) 3 (c)5 (d) 6 (e) 7Which of the following is NOT associated with excretion in mammals (a) Glomeruliis^U^lIi^ (c) Faeces (d) Carbondioxide (e) Bowman's capsule — \f ^ X wSpirogyra reproduce vegetatively by (a) Spore Production (b) Fragments Adi? fc) Multiple fissionpfe. \ \ \(d) Budding (e) Binary fission v:; « \ ’In which of the following plants is swollen shoot disease comirj^h21(4)^roundnul (b) Cocoa (c) Corn (d)^fotton (e) Rubber ' V.Which of the following organisms lacks flagellum? (a) Euglena (b) Paracemecium (c)Chlamydomonas (d) BacteriaWhich of these is NOT a type of soil? (a) Sand (b) Grary^^J^m (d) Clay (e) Sandyloamr\Plants that grow in an area that is neither too Granite (c) Loam (d) Clay (e) Sandy"\ \ v 3loamIn mendelian inheritance, discontinuous ehai^clers are controlled by the (a) Centromeres (b) Alleles (c) Chromosomes (d) Chromatids {a).‘Chiasmat

Please, re-format these questions

Eben331:
Pls guys, I need solution to this question. This question weak me.

The answers

Pes13:
until after putme, anything can happen, I knew some of my mate who scored 300+ but couldn't score more than 65%, though he made it while I knew a department mate who scored 268, and still made it.

There was even someone who entered with 218, I saw it with my eyes, I wasn't told.

why am I telling u this? , focus on putme, your jamb score alone can't help you or determine your chance.

Alright thanks

Eben331:
Someone should pls solve these.

1. C6H12O6 + 12O2 -- 6CO2 + 6H2O

Molar mass of the carbohydrate = 180g

Using first principle..

180g --- 264g
180000-- y

y = 180000 x 264/ 180

y - 264kg

2. still on it

3. Volume = 50cm^3
1cm^3 - 1g
T1 -- 293K
T2 -- 307K

H = Mc * change in theta
= 50 x 4.2 x (307 - 293)
= 2940J

Find the amount of Hcl that will liberate 2940J

Molar concentration = Amount/Volume

2 = a/ 0.05
a = 0.1

Therefore. .

0.1 mole liberate 2940J of energy
1 mole will liberate

1 x 2940/ 0.1

-- 29400J x 2
58800j or so
... I'm not sure about this one, will check later..

4. From the second law of electrolysis...

m/M x c = m/M xc

0.16/64 x 2 = m/32 x 4

5 x 10^-3 = 4m/32

4m = 0.16
m = 0.04

Therefore. . 32g---- 22.4
--------- 0.04 --- p

22.4 x 0.04/32 = p
p -- 0.028dm^3

Pes13:
Gud day everyone, greeting to everyone,.

Let me be biased, special greetings to all MBBS aspirants.

By now everyone should be almost ready for the battle ahead.

To all mbbs, remember you are fighting a battle at the ratio of 1 applicant versus 100 applicants.

During my aspiring days, a total of 146 student were admitted in my class while over 11,000 choose UI MBBS from jamb.

so, get your battle axe ready, prepare for war, the warfront is deadly.

Even nairalanders will not pity you, they are ready to strike you into physiology and biochemistry department, if you don't strike them first. Fight with all within you.

But, remember, you need God in this race. The race Is not for the swift. Read, pray, and spank 90% in prime.

i

What do you think the cutoff will be this year based on jamb score alone. . Thinking about it scares the bat shit outta me.

Besides, what are the other inclusions in the use of english part from comprehension, synonyms and antonyms?

Eben331:
You can delete ur mail now from ur earlier post...I am on facebook but not on WhatsApp for now. I will send my facebook username to u through email.

Alright bro

Eben331:
Give me ur email. We need to talk. I am unable to pm u via Nairaland, I don't knw the reason.

....

Rursh:
UI 2017 POST UTME-PHYSICS QUESTIONS
***As micro implies 10-6, femto implies what? (a)10-15 (b)10-12 (c)10-21 (d) 10-18

***An inventor makes a clock using a thin brass rod and a heavy mass as a pendulum. What
happens during a very cold weather? (a) The pendulum would shorten and the clock gain time
(b) The pendulum would lengthen and the clock gain time (c) The pendulum would shorten and
clock lose time (d) The pendulum would lengthen and the clock lose time

***A ladder of length 3m weighs 200N and has its centre of gravity 120cm from its bottom. A 50N
weight is attached to its top. Calculate the amount of work required to raise the ladder from a
horizontal position on the ground to a vertical position. (a) 390J (b) 240J (c) 150J (d) 750J

***Complete the following statement: Today, the standard unit of time is defined in terms of (a) the
electromagnetic waves emitted by cesium atoms (b) the motion of the moon around the earth
(c) the average solar day (d) the speed of light

***A force, 10N drags a mass 10kg in a horizontal table with an acceleration of 0.2ms-2
. What is the
coefficient of friction between the moving mass and the table if the acceleration due to gravity is
10ms-2
(a) 0.02 (b) 0.08 (c) 0.80 (d) 0.20

The question is from College physics. .

Workdone = 3 * 50 + 1.2 * 200

= 150 + 240
= 390J

Workdone required to lift the ladder through its length plus workdone required to raise it through its center of gravity

The last question is also patterned after Newtonian law calculations in college physics. .

Net Force = Ma

Applied F - Frictional force= Ma

10 - Fr= 10 * 0.2

Fr = 8N

U = Frictional force/Mg
U= 8/100

U = 0.08

Eben331:
length l=?, g=10m/s^2, f=2s^-1 or 2Hz, pie=3.14.... f=1/2pie*_/g/l....2=1/(2*3.14)*_/10/l....2=1/6.28*_/10/l....cross multiply...2*6.28=_/10/l....12.56=_/10/l....spuare both sides.... 12.56^2=10/l....l=10/12.56^2.... l=10/157.7536....l=0.0633m N.B: where _/ means square root. I am not sure whether the answer is correct or not.

0.063m is very correct

Rursh:
UI 2017 POST UTME-PHYSICS QUESTIONS
***As micro implies 10-6, femto implies what? (a)10-15 (b)10-12 (c)10-21 (d) 10-18

***An inventor makes a clock using a thin brass rod and a heavy mass as a pendulum. What
happens during a very cold weather? (a) The pendulum would shorten and the clock gain time
(b) The pendulum would lengthen and the clock gain time (c) The pendulum would shorten and
clock lose time (d) The pendulum would lengthen and the clock lose time

***A ladder of length 3m weighs 200N and has its centre of gravity 120cm from its bottom. A 50N
weight is attached to its top. Calculate the amount of work required to raise the ladder from a
horizontal position on the ground to a vertical position. (a) 390J (b) 240J (c) 150J (d) 750J

***Complete the following statement: Today, the standard unit of time is defined in terms of (a) the
electromagnetic waves emitted by cesium atoms (b) the motion of the moon around the earth
(c) the average solar day (d) the speed of light

***A force, 10N drags a mass 10kg in a horizontal table with an acceleration of 0.2ms-2
. What is the
coefficient of friction between the moving mass and the table if the acceleration due to gravity is
10ms-2
(a) 0.02 (b) 0.08 (c) 0.80 (d) 0.20

1. 10^-15
2. A
3. 390Joules
4. A
5. 0.08

Gracy3535:
Dat 20& is 20%. The answer z 69dm^3 i dnt knw hw to get it

Equation of reaction
4P + 5O2 --- 2P2O5
Using first principle. .
5 x 22.4dm3 of O2 ---- 284 of P2O5 y --- 35g
Cross multiply..
35 x 5 x 22.4= 284y
3920 = 284y
y = 13.80dm3
Since oxygen contains 20cm3 by 100cm3 of air
20 --- 100 13800 --- x
20x = 1380000
x = 69dm3 or 69000cm3

DrBESTJC:
Please bosses in the house,I need help with these questions. Explain your answers please...

BIOLOGY.

1) Epiphytic habitat can best be described as....?
A) arboreal
B) estuarine
C) aquatic
D) terrestrial

2) Which of the following is likely to encourage inbreeding in plants....?
A) Dioecious.
B) Protandrous
C) Monoecious
D) Hermaphrodite

3) A green snake in a green grass is able to escape notice from predators because of its...?
A) Disruptive colouration
B) Counter shading
C) Warning coloration
D) Cryptic Colouration

4) The organ located within the duodenal loop in the mammal is the..?
A) Liver
B) gall bladder
C) pancreas
D) spleen

5) A person that is obese must avoid meals containing...?
A) magarine and butter
B) rice and yam
C) carrot and oranges
D) beef and beans

6) The addition of lime to clayed soil serves to...?
A) prevent water-logging
B) aid water retention
C) improve capillary action
D) close up the texture

7) A caterpillar and an aphid living in different parts of the same plant can be said to .....?
A) be in similar micro habitats
B) occupy the same ecological niche
C) be in different habitats
D) occupy different ecological niches

8 ) Rodents gnaw on food with their ..?
A) chisel-like front teeth
B) molar teeth
C) strong jaws
D) flat-ridged teeth

9) The most common characteristic of the fungal hyphae is the possession of...?
A) cell-like partitions formed by cross-walls
B) cell-like compartments with one nucleus each.
C) cell walls that are both rigid and chitinous
D) a multicellular mycelium in the substrate.

10) In the root vascular system, the stele is directly surrounded by the ..?
A) parenchyma
B) endodermis
C) pericyle
D) cortex

11) Secondary succession is much faster than primary succession because..?
A) soil is already present
B) species competition is increased
C) pioneer colonizers are more in number
D) secondary series require less nutrients

1. Arboreal. . They 'live' on trees

2. Hermophrodite. . Monoecious flowers are not capable of self pollination

3. Cryptic colouration

4. Pancreas. .

5. Fatty foods cause obesity. . Magarine and butter

6. Prevents water logging. . Clayey soils are known for their soil water rententivity. . Adding of slake lime, Caco3 or gypsum helps loosen up the texture thereby reducing water logging

7. Occupy different ecological niches

8. Chisel like front teeth. .

9. C

10. Pericycle. . I'm not well versed in supporting tissues in plant...

11. Soil is already present. . From my soil science knowledge, primary succession is mostly slow due to weathering process of parent materials. . Believe me bro, weathering is a slow process..

Adolak:
This is wrong. The question is to find mass. Not mass conc. Then you used the H conc instead of OH concentration as it is NaOH.
I got 0.0202g though. Don't know if I'm correct

Ph + Poh = 14
Poh = 14 - 10.5
= 3.5
Poh = -(log10OH)
3.5 = -LogOH
OH = Antilog -3.5
= Antilog 0.5 x Antilog -4.0 = 3.162 x 10^ -4
Since concentration = 3.16x 10 ^-4 Mass is unknown Molar mass = 40g Volume = 0.8dm3 C = n/v
Where the terms take their usual meaning.
3.16x 10^-4 x 0.8 = amount amount = 2.528 x 10^-4
Amount = mass/molar mass
mass = amount x molar mass
= 2.528 x 10^-4 x 40g
mass = 101.12 x 10 ^-4
= 0.0101g..

Eben331:
A boy observes a cricket ball move up and down past a window 5m high. If the total time of the ball in sight is 3s. Find the height above the window that the ball rises. PLS SHOW YOUR WORKINGS!!

Maximum height = 1/2 x g x t^2

= 1/2 x 10 x 1.5 x 1.5

= 11.25

Maximum height - Height of the window

11.25 - 5

= 6.25m above the window

Eben331:
(1) The magnification of a diverging mirror is 2/5, if the radius of curvature is 20cm, find the distance between the object and the image. (a) 21cm (b) 35cm (c) 16.7cm (d) 49cm (e) none of the above. (2) Calculate the radius of curvature of a convex mirror given that the distance between the mirror and object is 15cm, and the distance between the mirror and image is 10cm. (a) 60cm (b) 45cm (c) 15cm (d) 30cm (e) none of the above. (3) An incident ray of light is deviated through 150', calculate the glancing angle. (a) 90' (b) 95' (c) 75' (d) 30' (e) none of the above. (n.b: where ' means degree)

1. M = v/f - 1

2/5 + 1 = v/10

5v = 70

v = 14m

M= v/u

2/5 = 14/u

70 = 2u
u = 35

Distance between the image and object equals V + U

35 + 14

= 49cm

3. Glancing angle is the angle the incident makes with the reflecting surface. .

D = 2g

150 = 2g
g = 75cm

I didnt bother solving number 2 though.

Eben331:
R=300 ohms, V=240v, t=300s, initial temperature T1=20^oC, final temperature T2=100^oC (since it is at boiling point), heat capacity of vessel C=200J/K, specific heat capacity of water c=4200J/kg/K, mass of water in the vessel m=? >>> Note that both the water and vessel have the same initial and final temperature >>> Heat gained by water + heat gained by vessel = Heat lost by coil >>> mc(T2-T1) + C(T2-T1) = V^2t/R >>> m*4200(100-20) + 200(100-20) = (240^2*300)/30 >>> m*4200*80 + 200*80 = 57600*10 >>> m*336000 + 16000 = 576000 >>> m*336000 = 576000-16000 >>> m*336000 = 560000 >>> m=560000/336000 >>> m=1.667kg >>> m=1.67kg (approx)

What about the mass of the vessel?

Eben331:
(1) If 21g of alcohol of density 0.7g/cm^3 is mixed with 10g of water, what would be the density of the resulting mixture? (a) 780g/cm^3 (b) 0.78g/cm^3 (c) 30g/cm^3 (d) 10g/cm^3 (2) For a particle having an x coordinate varies in time according to the expression x=4t-2t^2, the instantaneous velocity of the particle at t=2.5secs is (a) 12m/s (b) 6m/s (c) 0m/s (d) 10m/s PLS SHOW UR WORKINGS!!

Differential function

x = 4t - 2t^2

v = dx/dt = 4 - 4t

At time = 2.5s

4 - 4 x2.5

4 - 10

= -6m/s