Gracy3535:
Calculate the volume of air required to produce 35g of phosphorus (v) oxide during the combustion of an excess of phosphorus.[O=16,P=31.All gas volumes measured at the same temperature & pressure.Air is about 20& oxygen by volume]

Seamione:
Calculus, trigonometry, coordinate geometry, sequence and series, surds, polynomials, permutation and combination and word problems. But generally, just work on time management and calculator independence

Eben331:
The answer is pericycle not cortex. You can make your findings right.

Gracy3535:
Calculate the volume of air required to produce 35g of phosphorus (v) oxide during the combustion of n excess of phosphorus.[O=16,P=31.All gas volumes measured at the same temperature & pressure.Air is about 20& oxygen by volume]

overcomer90:
The intensity of light falling on the film in a camera depend on the i. brightness of the object. ii. diameter of the aperture stop. iii. speed of the shutter. Which of the statements is/are correct/

A. i, ii and iii
B. i and ii only
C. i and ii only
D. ii and iii only
E. iii only

Eben331:
2.76dm^3 or 2760cm^3. Is it correct?

IFEOLUWAKRIZ:


Says who

Sha rule has it that one should not cook in one's room..We have kitchenette where you can cook with ur stove but since I resumed, I have not seen anybody using any fucking kitchenette.. We cook with hotplates in our various rooms..


Not all the time person go fee get kerosene to power em stove na so hotplates are indispensable in a situation like this.

Gracy3535:
Dat 20& is 20%. The answer z 69dm^3 i dnt knw hw to get it

Rursh:
UI 2017 POST UTME-PHYSICS QUESTIONS
***As micro implies 10-6, femto implies what? (a)10-15 (b)10-12 (c)10-21 (d) 10-18

***An inventor makes a clock using a thin brass rod and a heavy mass as a pendulum. What
happens during a very cold weather? (a) The pendulum would shorten and the clock gain time
(b) The pendulum would lengthen and the clock gain time (c) The pendulum would shorten and
clock lose time (d) The pendulum would lengthen and the clock lose time

***A ladder of length 3m weighs 200N and has its centre of gravity 120cm from its bottom. A 50N
weight is attached to its top. Calculate the amount of work required to raise the ladder from a
horizontal position on the ground to a vertical position. (a) 390J (b) 240J (c) 150J (d) 750J

***Complete the following statement: Today, the standard unit of time is defined in terms of (a) the
electromagnetic waves emitted by cesium atoms (b) the motion of the moon around the earth
(c) the average solar day (d) the speed of light

***A force, 10N drags a mass 10kg in a horizontal table with an acceleration of 0.2ms-2
. What is the
coefficient of friction between the moving mass and the table if the acceleration due to gravity is
10ms-2
(a) 0.02 (b) 0.08 (c) 0.80 (d) 0.20

Eben331:
length l=?, g=10m/s^2, f=2s^-1 or 2Hz, pie=3.14.... f=1/2pie*_/g/l....2=1/(2*3.14)*_/10/l....2=1/6.28*_/10/l....cross multiply...2*6.28=_/10/l....12.56=_/10/l....spuare both sides.... 12.56^2=10/l....l=10/12.56^2.... l=10/157.7536....l=0.0633m N.B: where _/ means square root. I am not sure whether the answer is correct or not.

Timil:
Is hotplates allowed in U.I?

Gracy3535:
I need help on this The first stable product formed during photosynthesis is_____(a)starch (b)lipids(c)glucose(d)oxgyen

TeflonBlixx:

Equation of reaction
4P + 5O2 --- 2P2O5
Using first principle. .
5 x 22.4dm3 of O2 ---- 284 of P2O5 y --- 35g
Cross multiply..
35 x 5 x 22.4= 284y
3920 = 284y
y = 13.80dm3
Since oxygen contains 20cm3 by 100cm3 of air
20 --- 100 13800 --- x
20x = 1380000
x = 69dm3 or 69000cm3

TeflonBlixx:


1. 10^-15
2. A
3. 390Joules
4. A
5. 0.08

TeflonBlixx:


1. 10^-15
2. A
3. 390Joules
4. A
5. 0.08

IFEOLUWAKRIZ:


NO





But in Indy and Zik we still use hotplates.
Porters normally go about checking our rooms once in every blue moon..Even when I was staying at Tedder,they were using hotplates.Don't know if they still use it now though.

Eben331:
Boss, can you pls show the workings to these questions and explanations where necessary?

Eben331:
Which of the following has the highest degree of hardness? (A) rain water (B) lake water (C) borehole water (D) river water PLS EXPLANATIONS WILL BE NEEDED!!

Timil:
How many people stays in a room in U.I?

Rursh:
UI 2017 POST UTME-PHYSICS QUESTIONS
***As micro implies 10-6, femto implies what? (a)10-15 (b)10-12 (c)10-21 (d) 10-18

***An inventor makes a clock using a thin brass rod and a heavy mass as a pendulum. What
happens during a very cold weather? (a) The pendulum would shorten and the clock gain time
(b) The pendulum would lengthen and the clock gain time (c) The pendulum would shorten and
clock lose time (d) The pendulum would lengthen and the clock lose time

***A ladder of length 3m weighs 200N and has its centre of gravity 120cm from its bottom. A 50N
weight is attached to its top. Calculate the amount of work required to raise the ladder from a
horizontal position on the ground to a vertical position. (a) 390J (b) 240J (c) 150J (d) 750J

***Complete the following statement: Today, the standard unit of time is defined in terms of (a) the
electromagnetic waves emitted by cesium atoms (b) the motion of the moon around the earth
(c) the average solar day (d) the speed of light

***A force, 10N drags a mass 10kg in a horizontal table with an acceleration of 0.2ms-2
. What is the
coefficient of friction between the moving mass and the table if the acceleration due to gravity is
10ms-2
(a) 0.02 (b) 0.08 (c) 0.80 (d) 0.20

TeflonBlixx:


The question is from College physics. .

Workdone = 3 * 50 + 1.2 * 200

= 150 + 240
= 390J

Workdone required to lift the ladder through its length plus workdone required to raise it through its center of gravity

The last question is also patterned after Newtonian law calculations in college physics. .

Net Force = Ma

Applied F - Frictional force= Ma

10 - Fr= 10 * 0.2

Fr = 8N

U = Frictional force/Mg
U= 8/100

U = 0.08

TeflonBlixx:


0.063m is very correct

micskales:
LET me explain the two calculations. firstly imagine a ladder 3m long laid down flat. Its weight 200N which is effective is 1.2m away from its bottom when u want to raise this ladder u have to raise it at the 1.2m i.e at the centre G. Now when u raise there, the force 200N has moved a distance of 1.2m so, W=f*s =240j.......but another force of 50N is acting at the top end, so if that also is raised vertically a distance of 3m has been moved by the force so..w =f*s =150J. Now total work =390j


*** F-fr=ma
10-fr=10*0.2
fr=10-2, =8
But Coeff.fr = fr/mg
=8/100 =0.08
fr = frictional force
mg =normal reaction i.e mass * gravity

Becalina:
Hello, please has the post utme date been released?

TeflonBlixx:

Equation of reaction
4P + 5O2 --- 2P2O5
Using first principle. .
5 x 22.4dm3 of O2 ---- 284 of P2O5 y --- 35g
Cross multiply..
35 x 5 x 22.4= 284y
3920 = 284y
y = 13.80dm3
Since oxygen contains 20cm3 by 100cm3 of air
20 --- 100 13800 --- x
20x = 1380000
x = 69dm3 or 69000cm3