Anybody who solves the question below is a genius........

Two cars A and B start from rest at the same time and place , the car A accelerates at 1ms-2 for 10 seconds , while the car B accelerates at 0.4 ms-2 for 30 seconds, find,
(1) the time in which the car B will overtake the car A
(2) the distance at which the overtaking occurs

Ortarico:

My Oga, abeg no vex na only the number 5 me dey interested in:

Let 'x' be the usual time. If the usual rate is 1 unit, then the unusual rate is 5/6. Balanced by the distance:
1*t = (5/6)(t+40)
t = 5t + 200 all over 6
cross multiply:
6t = 5t + 200
6t - 5t = 200
t = 200 mins or 3 hrs 20 mins. . . . . . . . . . .OR

If the ratio of the rates of unusual to usual is 5:6, then the ratio of unusual to usual is 6:5
t = 40
5t = ?
5(40) = 200 mins

:. His unusual time is:
6t = ?
6(40) = 240 mins which oga oladoya got. . . . .

Sorry for joining you late, busy tinz. @rahsywire how did you know I wasn't sleeping?

y won't i? cos i was watchin d way u guys re jacking. *winks*
u re online nw, d@z hw i knw

[quote
author=dr.genius]Anybody who solves the question below is a
genius........

Two cars A and B start from rest at the same time and place , the car A
accelerates at 1ms-2 for 10 seconds , while the car B accelerates at 0.4
ms-2 for 30 seconds, find,
(1) the time in which the car B will overtake the car A
(2) the distance at which the overtaking occurs[/quote]
(1) 20secs (2) 0.1m
pls mark me

cyntybabe: As 4 me I feel u guyz r jst shwin off,well wen d day comes we shall knw d empty boastas nd d real gurus...anyway plz I nid a reply 4rm a studnt of unilag 2 tel me my chances of gaining admissn in2 200l accountin/managemnt wit a lower crdit 4rm anoda skul

As 4 me, I feel Accounting is highly competitive 4 dat ur grade'lower credit'. People wit distinction are still struggling 4 admission. And pls learn how 2 appreciate peoples work.

rashywire:
(1) 20secs (2) 0.1m
pls mark me

sorry u r wrong

dr.genius:
@ oladoya
i think u are wrong now let the rate be x and the normal time be t then we should know that the distance travelled is constant , so therefore let the distance be s , then we have thge following equations
t*x = s
5/6x ( t+ 40) = s

by dividind equation 1 by 2 we have

5/6x(t+ 40) = tx ( divide through by x) we now have

5/6t+ 200/6 = t

t/6 = 200

then t = 200/6 minutes which is equivalent to 3 hours 20 minutes

i think u are right i didnt take the speed distance into consideration but your equation is nebulous or leme say cryptical why dont we have it as...
Let the rate be x
the time be y
and the distance should be d
d=xy...(1)
d/(5x/6)= y+40
sub. D =xy in equ.2
xy/(5x/6)=y+40
den we have
xy/1*6/5x=y+40
6xy/5x=y+40
x cancel x
6y=5y+200
y=200min
in hours we have 200/60 =3hrs 20min.. Thanks for the observation

oladoya: i think u are right i didnt take the speed distance into consideration but your equation is nebulous or leme say cryptical why dont we have it as...
Let the rate be x
the time be y
and the distance should be d
d=xy...(1)
d/(5x/6)= y+40
sub. D =xy in equ.2
xy/(5x/6)=y+40
den we have
xy/1*6/5x=y+40
6xy/5x=y+40
x cancel x
6y=5y+200
y=200min
in hours we have 200/60 =3hrs 20min.. Thanks for the observation

once again i think ir equation is the most nebulous and cryptical , my solution was in a lay mans format......

Thank you

gistwithmontaro: Ok guys, you can giveth a shot
1. What is the capital of vietnam?
2. Which animal has the biggest eyes of any livin creature?
3. What name is given to a dealer licensed to lend money on the security of an item of portable personal property?
4. What is the capital of Ethopia?
5. How many rings on the olympic flag?
6. Where in your body is your patella?
7. Who was the first man in space?
8. If you had pogonophobia, what would you be afraid of
9. Which country grows the most fruit?
10. Which company is owned by Bill Gate
11. What type of acid is used in car batteries

nawaooo

My people una well done o...a peep at this thread reveals young people with one mind, and i really appreciate this. Please help solve this maths question; find the sum of the following progression, 1+x+x^2+x^3..

mastermynd: [color=#550000]
Gud mawning #team lag#
quickly brush ur teeth and have appetizer
Which of the following is not an enclave
country?
A. Gambia
B. Lesotho
C. Vatican City
D. San Marino
2.One of these is not a coastal state?
A. Lagos
B. Port Harcourt
C. Benin
D. warri.
3.The process where a computer provides
computing services to several users
concurrently online is called
A. Time-sharing system
B. Batch system
C. Real-time system
D. Network system
4.The player scored a hat-trick means he
scored
A. a goal
B. two goals
C. three goals
D. fourth goal
5.A person walking 5/6 of his usual rate is
40 minutes late. What is his usual time?
A. 3 hrs 20mins
B. 30 hrs 10 mins
C. 4 hrs
D. 2 hrs 40mins
show no 5 workings,as both carry half mark...
LEEEEGOOOOOOOOOOO

1)a 2)c 3)a 4)c 5)c

gistwithmontaro: Ok guys, you can giveth a shot
1. What is the capital of vietnam?
2. Which animal has the biggest eyes of any livin creature?
3. What name is given to a dealer licensed to lend money on the security of an item of portable personal property?
4. What is the capital of Ethopia?
5. How many rings on the olympic flag?
6. Where in your body is your patella?
7. Who was the first man in space?
8. If you had pogonophobia, what would you be afraid of
9. Which country grows the most fruit?
10. Which company is owned by Bill Gate
11. What type of acid is used in car batteries

1. HANOI 2.GIANT SQUIRD 3.? 4.ADDIS ABABA 5. 5RINGS 6.KNEE JOINT 7.YURI GAGARIN 8. FEAR OF BEARDS 9.CHINA 10. MICROSOFT company 11 lead acid

[quote
author=oyestephen]My people una well done o...a peep at this thread
reveals young people with one mind, and i really appreciate this. Please
help solve this maths question; find the sum of the following
progression, 1+x+x^2+x^3..[/quote]
ans= 1/(1-x)

Hello guys and girls,

Guys Calm down ! Diz room is noisy,and unsettled and disorganised...haba. Some going towards diz side,others towards another. Many of us are turning diz into a competition to which I see as childish. Pls,it will be better if we dnt av more questions for now,lets resolve all diz ones flying about,and dnt forget da main target of the thread...SHARE INFORMATION...#Yours sincerely,Adéyemí

dr.genius:
Anybody who solves the question below is a genius........

Two cars A and B start from rest at the same time and place , the car A accelerates at 1ms-2 for 10 seconds , while the car B accelerates at 0.4 ms-2 for 30 seconds, find,
(1) the time in which the car B will overtake the car A
(2) the distance at which the overtaking occurs

wen I saw d word genius, I was tinkin of seein a question nobody can solve here, I would hav solve it 4 U̶̲̥̅̊, but no need, bcoz is useless as far unilag putme(dis thread) is concern, but if U̶̲̥̅̊ realy need d solution, let's meet sumwere, mayb bbm,skype,fb, by den I will disolve it 4u...infact d question is an example in pure and applied mechanics(mayb U̶̲̥̅̊ no see d question 4 dat textbook sha oo), but is an example there, and more n similar question like dis are also there....if U̶̲̥̅̊ hav see uniben 100L phy question on mechanics b4, U̶̲̥̅̊ will also see dat such questions are much there...kudos U̶̲̥̅̊ have technical question, but I'm vry sure not strange 2 some people here..if U̶̲̥̅̊ preparing 4 unilag putme, face ur work now n 4get question like dis..takia

A

Davefirst:
1. Don't know 2. D 3. D 4. C 5. Don't knw maths at all

1/5

oladoya: DADBC

1/5

rashywire:
k solution 2 no 5, let d usual rate be x, we have
5/6x = x-40, 5x= 6x-240
x=240 den 240/6 = 4
d usual time = 4rs, 1.b 2.d 3.d 4.c 5.c

2/5

cyntybabe: As 4 me I feel u guyz r jst shwin off,well wen d day comes we shall knw d empty boastas nd d real gurus...anyway plz I nid a reply 4rm a studnt of unilag 2 tel me my chances of gaining admissn in2 200l accountin/managemnt wit a lower crdit 4rm anoda skul

u werent invited,,besides if u had prepared well,,,u no go dey carry lower credit about,,,mtcheeeeeeewz

dr.genius:
@ oladoya
i think u are wrong now let the rate be x and the normal time be t then we should know that the distance travelled is constant , so therefore let the distance be s , then we have thge following equations
t*x = s
5/6x ( t+ 40) = s

by dividind equation 1 by 2 we have

5/6x(t+ 40) = tx ( divide through by x) we now have

5/6t+ 200/6 = t

t/6 = 200

then t = 200/6 minutes which is equivalent to 3 hours 20 minutes

speechlessss

yemmytcm: Hello guys and girls,

Guys Calm down ! Diz room is noisy,and unsettled and disorganised...haba. Some going towards diz side,others towards another. Many of us are turning diz into a competition to which I see as childish. Pls,it will be better if we dnt av more questions for now,lets resolve all diz ones flying about,and dnt forget da main target of the thread...SHARE INFORMATION...#Yours sincerely,Adéyemí

Thats true.

hillsnite: 1)a 2)c 3)a 4)c 5)c

4/5

dr.genius:
Anybody who solves the question below is a genius........

Two cars A and B start from rest at the same time and place , the car A accelerates at 1ms-2 for 10 seconds , while the car B accelerates at 0.4 ms-2 for 30 seconds, find,
(1) the time in which the car B will overtake the car A
(2) the distance at which the overtaking occurs

Dis is a quest frm project 2 u'l se d ans there

CORRECTION;
ACACA,,n thought i knew no5 until i was proved wrong by mathematecians,,.. So sum people gat 0 cause already awarded wrong marks,,,
but d beauty is dat i learnt...
Any question pple...

[color=#770077][/color] @ mastermynd correction!!

[quote author=yemmytcm]Hello guys and girls,

Guys Calm down ! Diz room is noisy,and unsettled and disorganised...haba. Some going towards diz side,others towards another. Many of us are turning diz into a competition to which I see as childish. Pls,it will be better if we dnt av more questions for now,lets resolve all diz ones flying about,and dnt forget da main target of the thread...
Well spoken....,

Mr Calculus: Frm my calculatns
gud=9,bad=5 nd fair=7
total no of fishes both gud,bad nd fair=9+7+5=21
no of pair gud fishes in 53=9x21/53=3.566 app=4
no of pair fair fishes in 53=7x21/53=2.77 app=3
no of pair bad fishes in 53=5x21/53=1.98 app=2
-:gud=4,fair=3 nd bad=2

i have seen may guessive soltions to this question, though my solution may be lenghty but its worth it .......
Let
good= x
fair = y, and
bad = z
then, since there are seven days in a week, and the hunter made 53 catches, two 3 variable simultaneous equations can be deduced which are
x+y+z = 7
9x+ 7y + 5z= 53
from these two equations we can arrive at two logical sets and inequalities which are
( x, y, z) = N
( 1<N<5) provided that no element of N ( x,y.z) equals 0

to createe to varible simultaneous equations we replace X for (7 -y-z) in the second equations which will give us
y+2Z = 5, also we can deduce locical sets an dinequalities which now give us the following
(y,z) = A
(1<A<2) provided that no element of A is 0
also by subtitution we have
x-z = 2, this will produce another set inequality which is
( x,z) = B
(1<B<3) prov. That B is not 0
lastly, by subtitution
2x+y= 9; then
(x,y) = C
(1<C<4) prov. That c is not 0

having our three inequalities A, B and C to find the solution we have to find the integers contained in
( A n B n C ) = N = ( x,y,z)
((1<A<2) n ( 1=B<3) n (1<C<4) ) = ( 4, 1, 2) = ( x, y, z)

@ dr genius by the time you finished solving all that in the exam hall about 10 mins + would have gone.....

When the Post UTME form is out! Please tell us in here and also The exam is in batches Morning and Afternoon each day so please try to read, cram and pour out the questions here especially the General Paper and others sha! This was done last year and for SURE lag repeated questions not just 1, not 2, not 3 #Bless

dr.genius:
Anybody who solves the question below is a genius........

Two cars A and B start from rest at the same time and place , the car A accelerates at 1ms-2 for 10 seconds , while the car B accelerates at 0.4 ms-2 for 30 seconds, find,
(1) the time in which the car B will overtake the car A
(2) the distance at which the overtaking occurs

25sec n 5m

yemmytcm: Hello guys and girls,

Guys Calm down ! Diz room is noisy,and unsettled and disorganised...haba. Some going towards diz side,others towards another. Many of us are turning diz into a competition to which I see as childish. Pls,it will be better if we dnt av more questions for now,lets resolve all diz ones flying about,and dnt forget da main target of the thread...SHARE INFORMATION...#Yours sincerely,Adéyemí

i agree with you boss

mastermynd:
u werent invited,,besides if u had prepared well,,,u no go dey carry lower credit about,,,mtcheeeeeeewz

relax bro, that was a bit harsh

Lurve: @ dr genius by the time you finished solving all that in the exam hall about 10 mins + would have gone.....

seconded

rashywire:
ans= 1/(1-x)

thanx workings pls

Lurve: @ dr genius by the time you finished solving all that in the exam hall about 10 mins + would have gone.....

my dear aspirant lurve i solved this question in 30 seconds using the same method, ifu are used to advanced mathematics this is a piece of cake , anyway i did this for explanatory reasons, any reasonable student like u would just test the option,
thank you for your observations and criticism