Mbahchiboy: OGAMI ABEG SHOW UR WORKINGS

3^(x+1)=5^(x^2-1)

Preciousguyx:

Anybody that tells u 1kg of iron and 1kg of sand weighs the same didnt reason b4 saying it or is probably ashame d of not being able to prove it. . . .lalalalala*singing*

dat formula can be proven
. . . . .view the link to get the ansa. . . .to the problem oyibo don argue am b4.
[url]http://www.google.com/gwt/x?hl=en&u=http://wiki.answers.com/Q/What_is_heavier_1kg_iron_or_1kg_feather&q=upthrust+in+air+with+1kg+of+object&sa=X&ei=Adw2UqWVHsjRhAfG_4GgDg&ved=0CCcQFjAD [/url]

znt it d same oyiboz dah said it was http://www.mmo-champion.com/threads/1185935-A-Ton-of-Iron-and-a-Ton-of-Feathers
http://in.answers.yahoo.com/question/index?qid=20120504225021AA8Cz55............

lemme quote wah sum said in d 2nd website
"To answer this question, we need to understand the difference between weight and mass.
Weight of an object is the force of gravity on that object while mass is the quantity of matter in that object.
The acceleration due to gravity has a constant value which is 10m/s^2 aprox. which is the same throughout the earth if not for the air friction occuring on falling bodies.
That brings us back to Galileo expriment where he displaced a stone and a feather from the same height at the same time; it was observed that the stone reached the ground ahead of the feather in the open air. The same expriment was carried out again this time but through a vaccum; since there was no air friction that will reduce the motion of the falling feather in the vaccum and the two object are attracted equally towards the earth, the both object reached ground at the same time.
If the same expriment is repeated for the iron and feather as in your question, it will be observed that in open air the iron will fall faster than the feather because of air friction on the falling feather but if in a vaccum they will fall at same speed and reach ground at the same time because there was no air friction and they are attracted equally towards the earth.
With those assertion, I hold it that the feather and iron will have same weight. That means they will have the same heaviness.
To further expantiate on what I have written above, remeber the formular, W = mg where W, m and g are Weight, mass and acceleration due to gravity respectively. Weight is force which has it unit in newton, N.
Considering the above, since both the iron and feather 1kg mass have equally and the gravity which is 10m/s^2 is acting on them equally, their weight will be given as:
Iron- W = 1*10 = 10N
Feather- W = 1*10 = 10N.
With this you can see that they have equal heaviness."
by anoda guy "Whenever you are talking of heaviness you are mentioning about its weight.
Now since both the substances are having equal masses if you measure the weight of the two substances under same acceleration due to gravity it is going to have the same weight i.e. mass x gravity. Which if measured on earth will have a acceleration of 9.8 m/s^2.
Thus if the two substances are measured under equal gravity they will show the same heaviness".......xo wats d argument abt......d fin abt sum pipu z dat dey dont lyk researchin.....dey jes c an ansa nd conclude dat daz d ansa.....smh

just collected my waec original result!dint knw it'd b easy

Mbahchiboy: HEHE.
O BOB WATIN DAT ONE MEAN NA

U say make we find 'x'
I find am 4u na witout any quadratic equation.
Hahaha
#guru's lodge

wat have u guys turned dis thread into? *headingtowards jamboffice

Mickey7: just collected my waec original result!dint knw it'd b easy

from waec office or sch

Mbahchiboy: A QUESTION 4 D GURUZ LODGE..#
find x if 3^(x+1)=5^(x^2-1)..
@ least dis one go commot una mind 4 mass and upthrust way una dy yarn..

(x+1)log3=(x^2-1)log5.
(x^2-1)/(x+1)=log3/log5
RECALL=x^2-1=(x+1)(x-1)
(x-1)(x+1)/(x+1)=log3/log5
(x-1)=log3/log5.
x=(log3/log5)+1
OR
(x-1)log5=log3,
xlog5-log5=log3
x=(log5+log3)/log5..
am not with a calculator so i cant give d exact answer of x..

Mickey7: just collected my waec original result!dint knw it'd b easy

How much bwo?

Eng. Tino:

3^(x+1)=5^(x^2-1)

(x+1)log3=(x^2-1)log5
log5/log3=(x+1))/(x^2-1)
3/2=(x+1)/(x^2-1)
3(x^2-1)=2(x+1)
3x^2-3=2x+2
3x^2-2x-5=0......use quadratic formula to solve it n u av -1 0r 1.7

.

Asakel:
U say make we find 'x'
I find am 4u na witout any quadratic equation.
Hahaha
#guru's lodge

hahahahaha
o bob u are 100% correct

Asakel:
How much bwo?

my school@odizeey...was asked to pay 500naira

Mickey7: my school@odizeey...was asked to pay 500naira

i thought as mich cos waec office is closed till october

Mr Calculus: brb how did u get 3/2 from log5/log3??

create a thread already! Create a thread for ur stu.pid argument!!!!!

Mr Calculus: (x+1)log3=(x^2-1)log5.
(x^2-1)/(x+1)=log3/log5
RECALL=x^2-1=(x+1)(x-1)
(x-1)(x+1)/(x+1)=log3/log5
(x-1)=log3/log5.
x=(log3/log5)+1
OR
(x-1)log5=log3,
xlog5-log5=log3
x=(log5+log3)/log5..
am not with a calculator so i cant give d exact answer of x..

U wont nid Ă calc..4rm log3=log5(x-1),,3=5(x-1)
3+5=5x,,x=8/5 or1.6

nw @ d jamb office 2800 for both e-facility cards nd printing

odizeey: i thought as mich cos waec office is closed till october

nna,biko,what are u saying?who told u dat waec office is closed?biko,i collected ma original gce cert. at waec office last wk wednesdayoooooo.

.

Wow! wow!! wow!!! Honestly I'm impressed with the future engineers in this thread. It's not really going to be easy in Uniben but with what I've seen here, I believe we can challenge in all levels.
Eng Tino, Calculus, Sir Tunec, Micellaneous and the rest of u guys.........una too much. Infact u guys are genius.
.........I rep chemical engin.....

Mickey7: nw @ d jamb office 2800 for both e-facility cards nd printing

Guy no let them slap u na one k per card making a total of 2000

Ayam_Kay: ayaf begin to fear o!!!!!! Chai see mathematicians! Eng. Faculty go hawt die!

#team_eng.
#team_chem_eng.
#guru'slodge


*quickly grabs K.A Stroud's eng. Maths*

No be small thing ooo. Engineering guys are not smilling and I believe they won't take it easy in Uniben ooo.

Osasu99:
Guy no let them slap u na one k per card making a total of 2000

dnt mind dem...only officials are allowed to pass tru d gate

See....wat are d requirmnts for clearance?

Osasu99:
Guy no let them slap u na one k per card making a total of 2000

mtchew dnt mind dem d gateman wudnt let me in.had to pay to an official

Osasu99:
Guy no let them slap u na one k per card making a total of 2000

hw much is d printing

Mickey7: hw much is d printing

jst 200

lavosier:
U wont nid Ă calc..4rm log3=log5(x-1),,3=5(x-1)
3+5=5x,,x=8/5 or1.6

mathematically wrng. U cant cancel log 4rm both side or else ure changing the equation...
Log3^2=log 9.... Dat means 2log3=log9. If we cancel log 4rm both side 2*3 wuld nt give u 9. Xo bro datz wrng.

Sir-Tunechi:

mathematically wrng. U cant cancel log 4rm both side or else ure changing the equation...
Log3^2=log 9.... Dat means 2log3=log9. If we cancel log 4rm both side 2*3 wuld nt give u 9. Xo bro datz wrng.

Dats diff..nw luk @ it dis way..log3=log5(x-3) (divide tru by log 3)=1=log5(x-3)/log3..dis equal log base3 5(x-3)=1 convert 2 indices..5(X-3)=3^1=5x-15=3 so derefore our 5x=18..x=1.6...u can Ơ̴̴͡.̮Ơ̴̴̴͡ is dsame..nd evn ƌ example u gave..log3^2 =log9..cancel log directly..3^2=9...

Mickey7: create a thread already! Create a thread for ur stu.pid argument!!!!!

DIS IS NO ARGUEMENT BUT I THINK D GUY Z KINDA CORRECT CAUSE HAVE LOOKED INTO HIS SOLVING