Fynestboi:

did i see u in 2go room 2day(UI)

Fynestboi: i cnt enta their coz nA LAGOS na im i put so it nt me

ok i saw same name there

pls how can i comment on a post...is it by quoting it?

@ mr.calculus latest question
1st we calculate the tym takn to rich d max hight
v=u-gt[since tis motion against gra.]
v=0,u=20
0=20-10t
t=2s
dere4 the total taken 4 flght(T)=2t=4
dere4 we find the tym wen the velocity of d 2nd stone=10m/s
sincev=u-gt
10=20-10t
t=1s
.'. d 2nd stone was @1s and the 1st stone was @2+1=3sec
1st stone=3s
2nd stone=1s

soloskino: pls how can i comment on a post...is it by quoting it?

...yep bro

Ai-bi-ke:
...yep bro

alright

gud morning everyone, plz i need ur help here.
A small oil drop falls with a terminal velocity of 3*10^-4m/s through air, calculate the radius of the drop, and what is the new terminal velocity for an oil drop of half it's radius.
(viscocity of air=1.8*10^-5N/SIN^2, density of oil=900kgm^-3, g=10m/s^2, ignore density of air)
plz, "WORKINGS/SOLUTION" will be gr8ly appreciated.

johnpaul1101: gud morning everyone, plz i need ur help here.
A small oil drop falls with a terminal velocity of 3*10^-4m/s through air, calculate the radius of the drop, and what is the new terminal velocity for an oil drop of half it's radius.
(viscocity of air=1.8*10^-5N/SIN^2, density of oil=900kgm^-3, g=10m/s^2, ignore density of air)
plz, "WORKINGS/SOLUTION" will be gr8ly appreciated.

4/3#(r^3)(rho)g =6#rUV
WHERE rho = density of oil,#=pie,u=viscosity of air,v=terminal velocity
making r subject of relation
r=sqrt[(9*1.8*10^-5 *10^-4)/(2*900*10)]
r=2.12 * 10^-6 m
PART B
if the radius halved r=2.12*10^-6/2 =1.06 *10^-8m
v=[4/3*r^2 *rho*g/(6u)] =1.25 * 10^-4 m/s

emmyeuler1: 4/3#(r^3)(rho)g =6#rUV
WHERE rho = density of oil,#=pie,u=viscosity of air,v=terminal velocity
making r subject of relation
r=sqrt[(9*1.8*10^-5 *10^-4)/(2*900*10)]
r=2.12 * 10^-6 m
PART B
if the radius halved r=2.12*10^-6/2 =1.06 *10^-8m
v=[4/3*r^2 *rho*g/(6u)] =1.25 * 10^-4 m/s

thanks a lot.....plz can i get ur number, or u can reach me @ 08137456323

Solve the exponential equation: 3^x + 4^x = 5^x

d citizen:
Solve the exponential equation: 3^x + 4^x = 5^x

....bro,do u think x could b solved for in dis equation?,cos at d end of d calculation 'x' wil be eliminated...

d citizen:
Solve the exponential equation: 3^x + 4^x = 5^x

D ANS IS 2....it can b solved usin g.method
NOTE:DIS IS NOT A MATHS THREAD

d citizen:
Solve the exponential equation: 3^x + 4^x = 5^x

guy....this is not a maths thread....go to maths thread!!

goodday everyone. Plz i saw this question on this thread but couldnt find a response.
A lift of weight 30kN moves upward through a height of 20m, if 25% of the workdone on the lift is used in overcoming friction, calculate the workdone.

johnpaul1101: goodday everyone. Plz i saw this question on this thread but couldnt find a response.
A lift of weight 30kN moves upward through a height of 20m, if 25% of the workdone on the lift is used in overcoming friction, calculate the workdone.

..usin total workdone =workdone against friction+work input,F=30kN=30*1000
W=25/100*W+(F*d)
W=W/4+(30000*20)
W=8*10^5J or
W=800KJ

goodday everyone, plz someone should help me solve this:
a piece of metal of mass 50g heated to 100degree celcius is dropped into 200g of water @ 14degree celcius in copper calorimeter weighing 80g and raises the temperature to 70degrees celcius. What is the heat capacity of the piece of metal?(specific heat capacity=0.4J/gK)

johnpaul1101: goodday everyone, plz someone should help me solve this:
a piece of metal of mass 50g heated to 100degree celcius is dropped into 200g of water @ 14degree celcius in copper calorimeter weighing 80g and raises the temperature to 70degrees celcius. What is the heat capacity of the piece of metal?(specific heat capacity=0.4J/gK)

,..incomplete question...what abt SHC/HC of d calorimeter can?

It's like this place have been abadoned for a long peroid of time o.

Am in

Odilop: Am in

k let's start, what is allotrophy.

Karleb: k let's start, what is allotrophy.

a subtance that has two or more forms in same state
I.E havin same chemical property but different physical prop (diamond and graphite)
What is enantiotropy?

A subtance without echo is called ___?

pls. does anyone know of any tutorial or schools around Agege,Alimosho,Egbeda,Ijaiye in Lagos that offers weekend lectures for utme..... pls, I need reply as soon as possible.

[b][/b]

Odilop: a subtance that has two or more forms in same state
I.E havin same chemical property but different physical prop (diamond and graphite)
What is enantiotropy?

enantiotrophy is the relation of crystal forms of same substance in which one form is stable above the transition point temperature and the other is below it so that the form can change reversily into each other.

The acid dissociation constant of phenol is approximately 10^-10 mol dm-3. Calculate the pH of a 0.01moldm-3 solution of phenol.

Odilop: The acid dissociation constant of phenol is approximately 10^-10 mol dm-3. Calculate the pH of a 0.01moldm-3 solution of phenol.

Odilop: A subtance without echo is called ___?

how can a substance be without echo.. i need more light on this ur question.

ChocolateBarbie:

y u dey vex.