joseboy199:
hw wil pressure affect it

t.boy007:
A
REASON:Rate of diffusion is inversely proportional to the relative molecular mass....i.e the more the relative molecula mass,the less its rate of diffusion...therefore from the question,argon has the highest RMM,it will definately have lesser rate of diffusion

t.boy007:
but argon has the highest RMM from the given option A-D.....well,may be you explain

mayorall:

nice...its the process used in production of soap...

t.boy007:
but argon has the highest RMM from the given option A-D.....well,may be you explain

mayorall:

Remember Chlorine is diatomic....Cl2

t.boy007:
but you did not state may be it's chlorine atom=cl ore chlorine molecule=cl2 in the question

t.boy007:
increase in pressure favours the forward reaction while reduction in pressure favours the backward reaction

joseboy199:
Even though i knw it is nt everybody dat knws it...dat was y i said u shud av gvn d parameters..cuz jamb diz days is diff 4rm 19th century....op av nt offended u wit my comment sha

joseboy199:
u are correct cuz argon has d highest rmm...increasin rate of diffusion is argon,chlorine,oxygen and nitrogen

mayorall:

At a free or uncombined state, Chlorine, Oxygen, Nitrogen etc exist as diatomic...

t.boy007:
Which of the following has effect on equilibrium costant?
a)pressure
b)temperature
c)concentration
d)catalyst
e)all of the above except catalyst

mayorall:

Hmmm...Only temperature has effect on equilibrium constant.......

mayorall:

Nope..Chlorine is diatomic

joseboy199:
u ryt... a kind of mistake..it actualy,cl2,argon,o2,n2

t.boy007:
well,that's his own answer,any other answer contrary

mayorall: Which of the following alters equilibrium position in a reaction
A.catalyst,temperature,pressure
B.temperature,surface area,catalyst
C.temperature,concentration, pressure
d.catalyst,surface area,pressure...

joseboy199:
C is d correct answer...

mayorall: Whats the percentage composition of oxygen in K2Cr2O7?
Cr =52
k = 39
0 = 16

A.14.20
B.26.53
C.38.09
D.35.37

mayorall:




moles = no of particles/6.02 * 10^23

2 = particles/6.02 * 10^23
particles = 2 * 6.02 * 10^23

particles = 12.04 * 10^23

or 1.204 * 10^23

Give options next time please...

mayorall:

Boss you are confused...option A is electrolytic and you saying the reaction is electrochemical....Option B is one of the uses of electrolysis....remember not all answers in the past questions are correct...

mayorall: Whats the percentage composition of oxygen in K2Cr2O7?
Cr =52
k = 39
0 = 16

A.14.20
B.26.53
C.38.09
D.35.37

mayorall: Whats the percentage composition of oxygen in K2Cr2O7?
Cr =52
k = 39
0 = 16

A.14.20
B.26.53
C.38.09
D.35.37

buzyguy: WOW,av missd alot!when A+B Reacts to giv AB As the product,the ethalpy chang z -540kj with activatn energy (Ea) 142kj.The energy for the dissociation of product AB in kj is?(a)146 (b)-540 (c)682 (d)398

joseboy199:
MM of K2Cr2O7=39*2+52*2+16*7=78+104+112=294
MM OF 02 IN K2CR2O7=112
%O2=112/294*100
ANS=38.095