Write a java program that is capable of calculating the length of a triangle using cosine rule

hint1:let the lenghts be L1,L2, and L3

hint2L1)^2 = (L2)^2 (L3)^2 - 2(L2L3cosL)
thanks in advance,awaiting ur solutions.

Guys just dey view dey commot...smh

Emyemyberry: Write a java program that is capable of calculating the length of a triangle using cosine rule

hint1:let the lenghts be L1,L2, and L3

hint2L1)^2 = (L2)^2 (L3)^2 - 2(L2L3cosL)
thanks in advance,awaiting ur solutions.

pls provide the fomular in plain text??

mj:

pls provide the fomular in plain text??

here

Emyemyberry: here

Ahem, the guy said in plain text! Not picture! I'm wilin to help

Olyboy16:
Ahem, the guy said in plain text! Not picture! I'm wilin to help

sori,bt i dnt undstnd wot you mean by plain inbtw,isn't my 1st post in plain?,pls xplahn.

Olyboy16:
Ahem, the guy said in plain text! Not picture! I'm wilin to help

sori,bt i dnt undstnd wot you mean by plain text inbtw,isn't my 1st post in plain?,pls xplahn.

Emyemyberry: sori,bt i dnt undstnd wot you mean by plain text inbtw,isn't my 1st post in plain?,pls xplahn.

Owkay, write the formular out in ur post..u get dat?

Oh, the cosine rule. Owkay.

 
public class cosine{
 public int cosine(){
   double a,b,c;
    c=Math.sqrt((a**2+b**2) - ((2*a*b)*Math.cos(c)));
    return c;
 }

} 

you'r welcome

//Try this

import java.util.Scanner;
public class CosineTriangle
{
public static void main (string[]args)
{
//author Speed23
//Program to calculate length of triangle using cosine rule

/* Not Tested. But should work */

Scanner user_input = new Scanner(System.in);

float l1,l2,l3,ans;
System.out.print("Enter your l1";
l1=user_input.next()f;
System.out.print("Enter your l2";
l2=user_input.next()f;
System.out.print("Enter your l3";
l3=user_input.next()f;

// Applying formular

ans= ((l1^2+l2^2-l3^2)/2*l1*l2) - cos(l1)

System.out.println("Answer is = "+ans);

}
}

The first problem I had with your programme was how to calculate the cosine of a an angle in degree which I have solved

Math.cos((Math. PI)/angle)

Now before I speak about the programme, let agree that cosine rule is

C sq = A sq + B sq +2ABcosangle

where C is certainly the hypotenuse
A or B opposite or adjacent respectively
and angle is the angle between the adjacent and opposite, i.e. facing the hypotenuse
If you write a programme that calculates the lenght of a side using the formulae you will have a logical error because the programme wil be looking for hypotenuse always, when you could actually be looking for opposite or adjacent!
For the programme to work,
The programme would have to ask you which of the sides is being looked for either hypotenuse, adjacent or opposite
after which it accepts value, computes and displays the result
What I've done is the algorithm design, which is the first step in programming
After this you commence coding

Call me on 08090642393, let me know that is in it for me

sealteam66: The first problem I had with your programme was how to calculate the cosine of a an angle in degree which I have solved

Math.cos((Math. PI)/angle)

Now before I speak about the programme, let agree that cosine rule is

C sq = A sq + B sq +2ABcosangle

where C is certainly the hypotenuse
A or B opposite or adjacent respectively
and angle is the angle between the adjacent and opposite, i.e. facing the hypotenuse
If you write a programme that calculates the lenght of a side using the formulae you will have a logical error because the programme wil be looking for hypotenuse always, when you could actually be looking for opposite or adjacent!
For the programme to work,
The programme would have to ask you which of the sides is being looked for either hypotenuse, adjacent or opposite
after which it accepts value, computes and displays the result
What I've done is the algorithm design, which is the first step in programming
After this you commence coding

Call me on 08090642393, let me know that is in it for me

wat the?? Call u? For few lines of codes?? This is cwious!! Wish i had my computer here.
You dont need to know wich part of d triangle to solve! Its cosine rule for God's sake. It was designed to solve sides of an isoceles triangle!! Na wa 4 u o. Nd u dey form boss

This should work perfectly.


import java.util.Scanner;
public class CosineAssignment
{
//L1^2=L2^2+L32-2L2L3cosL


public static void main(String[] args)
{
double l1, l2, angle;

Scanner in=new Scanner(System.in);

System.out.println("Supply The First Length:";
l1=in.nextDouble();

System.out.println("Supply The Second Length:";
l2=in.nextDouble();

System.out.println("Please Supply The Angle";
angle=in.nextDouble();

double l1sq=squares(l1); //squaring The First Length
double l2sq=squares(l2); //squaring The Second Length

double cos_angle=Math.cos(Math.toRadians(angle)); //getting the cosine of the angle

double cs=l1sq+l2sq;

double csv=(2*l1*l2*cos_angle);

double ans=Math.sqrt(cs-csv);

System.out.println("The Length is: "+ans);
}


private static double squares(double fig){
return fig*fig; //this is just to square the lengths.
}
}

Hope i am not late??

Olyboy16: Oh, the cosine rule. Owkay.

 
public class cosine{
 public int cosine(){
   double a,b,c;
    c=Math.sqrt((a**2+b**2) - (2*a*b*Math.cos(c)));
    return c;
 }

} 

you'r welcome

Your cosine would return a wrong value.

sealteam66: The first problem I had with your programme was how to calculate the cosine of a an angle in degree which I have solved

Math.cos((Math. PI)/angle)

Now before I speak about the programme, let agree that cosine rule is

C sq = A sq + B sq +2ABcosangle

where C is certainly the hypotenuse
A or B opposite or adjacent respectively
and angle is the angle between the adjacent and opposite, i.e. facing the hypotenuse
If you write a programme that calculates the lenght of a side using the formulae you will have a logical error because the programme wil be looking for hypotenuse always, when you could actually be looking for opposite or adjacent!
For the programme to work,
The programme would have to ask you which of the sides is being looked for either hypotenuse, adjacent or opposite
after which it accepts value, computes and displays the result
What I've done is the algorithm design, which is the first step in programming
After this you commence coding

Call me on 08090642393, let me know that is in it for me

its definitely not about hypothenuse its just about you finding the length facing the angle. basically, its represented as:
The lengths a,b and c
The angles are A,B and C
so 2 sides and an angle are give and u are asked to get the length of the last side.
most times the unknown side always have its angle known or computed somehow
so the Formula actually is:
to find length c

c=SQRT(a*2b*2+2abcosC)

so thats the right formula. The Cases were misleading tho!!

LordRahl001:
Your cosine would return a wrong value.

No it wont, check my codes very well.

Olyboy16:
No it wont, check my codes very well.

I figured u'd say that but in java, Math.cos() expects d variable in radians but u r supply diff nomenclature here!! Try it out and c d output. Coz 60 shud give u 0.5 but Math.cos() will give u another thing entirely. Cheers,

LordRahl001: I figured u'd say that but in java, Math.cos() expects d variable in radians but u r supply diff nomenclature here!! Try it out and c d output. Coz 60 shud give u 0.5 but Math.cos() will give u another thing entirely. Cheers,

Thanks. I'm much of a consumer based softwares guy in java..thanks

Olyboy16:
Thanks. I'm much of a consumer based softwares guy in java..thanks

you are welcome sir!!!

LordRahl001: This should work perfectly.


import java.util.Scanner;
public class CosineAssignment
{
//L1^2=L2^2+L32-2L2L3cosL


public static void main(String[] args)
{
double l1, l2, angle;

Scanner in=new Scanner(System.in);

System.out.println("Supply The First Length:";
l1=in.nextDouble();

System.out.println("Supply The Second Length:";
l2=in.nextDouble();

System.out.println("Please Supply The Angle";
angle=in.nextDouble();

double l1sq=squares(l1); //squaring The First Length
double l2sq=squares(l2); //squaring The Second Length

double cos_angle=Math.cos(Math.toRadians(angle)); //getting the cosine of the angle

double cs=l1sq+l2sq;

double csv=(2*l1*l2*cos_angle);

double ans=Math.sqrt(cs-csv);

System.out.println("The Length is: "+ans);
}


private static double squares(double fig){
return fig*fig; //this is just to square the lengths.
}
}

Hope i am not late??

omg,thanks alot boss,more grace to you

Special thanks to olyboy16 , intellab , lordRahl001

Emyemyberry: omg,thanks alot boss,more grace to you

u are welcome boss!!! God bless you too.

LordRahl001:
u are welcome boss!!! God bless you too.

Emyemyberry I acted like a dick head, i believe you have resolved the issue, If you still want the program, I can write it for you, absolutely FREE!

sealteam66:

Emyemyberry I acted like a dick head, i believe you have resolved the issue, If you still want the program, I can write it for you, absolutely FREE!

thanks man for the concern,hope you can do smthing wt the "if statement" for the question

sealteam66: The first problem I had with your programme was how to calculate the cosine of a an angle in degree which I have solved

Math.cos((Math. PI)/angle)

Now before I speak about the programme, let agree that cosine rule is

C sq = A sq + B sq +2ABcosangle

where C is certainly the hypotenuse
A or B opposite or adjacent respectively
and angle is the angle between the adjacent and opposite, i.e. facing the hypotenuse
If you write a programme that calculates the lenght of a side using the formulae you will have a logical error because the programme wil be looking for hypotenuse always, when you could actually be looking for opposite or adjacent!
For the programme to work,
The programme would have to ask you which of the sides is being looked for either hypotenuse, adjacent or opposite
after which it accepts value, computes and displays the result
What I've done is the algorithm design, which is the first step in programming
After this you commence coding

Call me on 08090642393, let me know that is in it for me

Hypotenuse?? Na right angled triangle??

Emyemyberry: thanks man for the concern,hope you can do smthing wt the "if statement" for the question

Elaborate on the if statement