kingphilip:

As simple as this

[15]+[9]+[3!]=30



Op give this answer n thank me later

the full question stated factorial shouldnt be used

Here's your answer:

9.15+7.13+3.5+1.11+9.11 =30.0

No answer cos anything you add,would give you an even number,meanwhile,the options provided are odd numbers.

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.

Cc lalasticlala

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.

Cc lalasticlala

since na braket dey dere
my own go bi like this
(5+1) + (9) + (15) = 30

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.

Cc lalasticlala

An odd number of odd numbers
cannot sum to an even number....

Why u dey worry pesin brain for notin?

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.

Cc lalasticlala

Simply: [3] + [7] + [9] + [11] = 30

(15)+(15)+()=30
simple and short.....am not told to use three numbers for this question.

Answer to this is :
(11-1) +(13-3)+(15-5)=30

GBAM!!!!!

1. No instructions that subtractions/additions can not be done between the integers.

2. The question considers using only the integers listed. So long as they are in brackets

3. I am absolutely right!

Given that we can repeat numbers then, (13+13)+(1)+(3)

There are a couple of simple ways to solve this without breaking the rules:

1. Sum numbers [i]within [/i]the brackets first - e.g. [1+3]+[11]+[15]=30, or

2. Leave a bracket blank as the rules didn't say you must fill ALL the brackets - e.g. [ ]+[15]+[15]=30

pkjag:
It's simple base addition let's use base ₉:
So 9₉+9₉+9₉=30
Those who have done computer science or electrical engineering will get it, for those who don't, we operate using base₁₀, so for base₉ let's all calculations such as 4+4=8 are the same as base₁₀, but when it comes to calculations like
9+9= 20, it's just like base₂ where
1₂+1₂=10.

You see in base₉ the number 9 is the last number, so there's no 10, so when you add the last numbers together you get 20 for arithmetic convenience, how? well in base₉ there are 10 numbers: 0,1,2,3,4,5,6,7,8,9 so it'd expected that if you add the tenth number to itself it should give the twentieth number then if you add again it should give the thirtieth number.

In other words,
3 + 3 + 3=30 base 3
5 + 5 + 5=30 base 5
7 + 7 + 7=30 base 7
Rubbish!!!

(11) + (13) + (3!) = 30
Remember
3! = 3 × 2 × 1 = 6

op solve it yourself

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.

[(1+3)]+[11]+[15]

Nobody can solve this, there is no way in the world that you can get an even number from summing up 3 odd numbers.

[9] + [15] +[3!] = 30.

The ! means Factorial.

ganiyheart:
(5+5)+(5+5)+(5+5)=30

this is the real deal

[15]+[7]+[9-1]=30

Dafan:
7,13,15

Bro I hail o add 7, 13 and 15 na ur own 30? Scholar

After some serious brain racking, i resulted to challenge OP's question programmatically...

I built an algorithm that combines the given list of numbers in every possible way and compute the sum of the combination,
in one sentence...OP's question has no solution!! It defies the very laws of mathematics, there is no way you can add an odd number of odd numbers to produce an even number!!
C'ne pas possible!

3! is not included

OkunrinMeta:
You should first forget about repeating numbers, you will never get an answer that way.
There is no answer. You can never get an even number by adding three odd/ prime numbers. If you come up with an answer, i will hit my head against a wall.

1 is not a Prime Number.

KillerBeauty:
[15]+[5]+[11]=31

Throw the 1 away it rounds up to 30
Simple

babe na d op u dey vex 4 abi d question?

[8] + [10] + [12] = 30

[15]+[13]+[7]= 30

[5+5]+[5+5]+[5+5] = 30

15+ 9 +3! =30


3 factorial

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.

All these numbers are odd! And there's no way the addition of 3 odd numbers will give you 30 which is an even number! No way; it is not possible.

pkjag:
It's simple base addition let's use base ₉:
So 9₉+9₉+9₉=30
Those who have done computer science or electrical engineering will get it, for those who don't, we operate using base₁₀, so for base₉ let's all calculations such as 4+4=8 are the same as base₁₀, but when it comes to calculations like
9+9= 20, it's just like base₂ where
1₂+1₂=10.

You see in base₉ the number 9 is the last number, so there's no 10, so when you add the last numbers together you get 20 for arithmetic convenience, how? well in base₉ there are 10 numbers: 0,1,2,3,4,5,6,7,8,9 so it'd expected that if you add the tenth number to itself it should give the twentieth number then if you add again it should give the thirtieth number.

Oga, you are not solving the problem given by the OP.

Normal human beings understand that base 10 is implied here. Na only geeks, computer engineers, book worms, and their likes, wey dey make life complicated dey go from one base to the other.

[color=#000099][/color]

1 + 5 + 11 + 13 = 30

emmyrichie:
[ ] + [ ] + [ ] = 30

Fill the boxes using

(1, 3, 5, 7, 9, 11, 13, 15)

You can also repeat the nos.