Please help a beginner

Question 1. Write a function that takes three integers as arguments and returns the product of
the largest two.

#include<iostream>
int maxmul(int a, int b, int c)
{
}
int main()
{
cout << maxmul(1,2,3) << endl;
cout << maxmul(3,1,2) << endl; cout << maxmul(3,2,1) << endl;
}

Question 2. Write a function, inc, that increases the value of variable x by 1.0;

#include<iostream>
int main()
{
float x=10.0;
cout << inc(x) << endl;
}

Question 3. Write a function that calculates and returns the average value of an array of
doubles. The length of the array is provided as a second argument, n.

double average_array(double data[], int n)
{
}

Question 4. Write a function to subtract the average value of the entire array from each array
element. You may make use of the average_array function from the first question.

void subtract_average(double data[], int n)
{
}

Question 5. Write a function to calculate the average value of a 100 by 100 array of ints.
Return the average as a double.

question 6. Write a program to dynamically allocate a n by m array of doubles. Both n and m
should be read from the console. All elements of the array should be initialized to zero. All
memory should be freed before the program exits.


Question 7. The function trap() numerically integrates exp(x^2) in the interval x=[a,b]. n is the number of points to evaluate the function at. Add comments to the function and format it using C++ standards.

#include<cmath>
float exp_mx2(int x)
{return(exp(x*x));}
float trap(float a, float b, int n) { float h = (ba)/(n1); float value = 0.5*( f(a)+
f(b)); for(int k=2; k < n; k++){value+=f( a + h*(k1)); } value*=h;return(value); }

solution 1

#include <iostream>
using namespace std;
int main ( )
{
int maximum (int a, inb,intc)
{
int a =1;
int b=2;
int b=3;
product =inta*intb
cout <<product<< endl;
return 0
}

solution2

#include <iostream>
using namespace std;
int main ( )
{
int x=10 ;
++x;
for (inti=0;i <10;++i);
cout <<++x<<endl;
return 0;
}

solution 3
#include <iostream>
Using namespace std;
int main ( )
{
double data [] = {a,b} ;
cout <<"Enter two numbers :add\n";
cin>>a>>b;
average =(a+b)*2
cout <<average<< endl;
return 0 ;
}

solution 5

#include <iostream>

Using namespace std;
int main ( )
{
int array [] ={100,100} ;
// calculate the Average
int sum =0 ;
for (inti=0;i <numbers.length; i++) ;
double average =sum /numbers.length;
cout <<average <<endl ;
return 0 ;
}

solution 6


#include <iostream>
Using namespace std;
int main ( )
{
array double [] = {m,n} =0
cin>>m>>n;
std:cout <<array double << std ::endl;
delete [] array ;
return 0 ;
}

solution 7 is pending TheTrapezoidal Rule

Otuabaroku:

@Op, I think this is an assignment given to you to do. It makes sense for you to make an attempt. When people see your effort, then you can be helped. In that way,you learn more from the assignment.

I was able to come about this for number 1
int maxmul(int a, int b, int c)

{
int min;
min = a;
if b<min min = b;
if c<min min = c;
return a*b*c/min;
}

Question 2
double inc(double x)
{
return x+1.0;

proxy20:
solution 7 is pending
TheTrapezoidal Rule

I am very grateful thank you alot!............Please teach me! I really want to learn!!

proxy20:
solution 7 is pending
TheTrapezoidal Rule

As regards your solutions, can i present the first like this?

#include<iostream>
int maxmul(int a, int b, int c)
{
}
int main()
{

int a =1;
int b=2;
int b=3;
product =inta*intb

cout <<product<< endl;
return 0
}
cout << maxmul(1,2,3) << endl;
cout << maxmul(3,1,2) << endl; cout << maxmul(3,2,1) << endl;
}

check Google or your math textbook. is it a school assignment.

You can convert this bunch of programs to a native android app using Android ndk and studio
or eclipse with adt bundle ,sdk and ndk to cool apps . NDK is for native apps development in c/c++ . create the java class , and c/c++ class and android Xml and build.

Otuabaroku:



@Iyalodeofcanada let me put you through to number 1 and 5, with that you can try the rest.

Question 1. Write a function that takes three integers as arguments and returns the product of
the largest two.

Here you are required to find the largest two of the three numbers entered by the user. In my solution, I have decided to store the data entered by the user in array and subsequently sort them in ascending order. With this sorting, I now know that the last two are the largest two of the three numbers entered by the user; hence, simply multiplying the two, will give me the answer.Here is code blow.

#include <iostream>
using namespace std;

int ProductOfLargestTwo(int a,int b,int c)
{
	//store the user input with array
	int userInput[3] = {a,b,c};

	//sort the array in ascending order
	for (int i = 0; i < 3; i++)
	{
             int compare = i+1;
	     if (compare < 3 && userInput[i]> userInput[compare] )
	    {
			int temp = userInput[i];
			userInput[i] = userInput[compare];
			userInput[compare] = temp;
	    }
	}
	
	//returns the product of the largest two
	return userInput[1] * userInput[2];
}

int main()
{
      cout<<"the product of the largest two is :"<<ProductOfLargestTwo(20,2,140)<<endl;
      getchar();
      return 0;
}

Thank you for this but your code seems too advanced for a baby programmer like me(I started this class one week ago). I have been googling each line all day. The truth is it is an assignment due tommorow. It is not as if i am been lazy but right now i just have to deliver and i am looking for the simplest way to go about this later i can now read up and catch up on array declarations and all that. Still working on it though thanks alot


#include <iostream>
using namespace std;
int maxmul(int a, int b, int c)
{

int min;
int a = 1;
int b = 2;
int c = 3;
}

int main()

if b < min min = b;
if c < min min = c;

{
cout << maxmul(1,2,3) << endl;
cout << maxmul(3,1,2) << endl; cout << maxmul(3,2,1) << endl;
}

return a*b*c/min;

Which compiler are u using?

I decided to implement a few of these using clojure.
I like clojure, because it's a lisp that runs on java. by being a lisp, you can develop functional programs that are very small, easy to test and fast. the code below took about 5 minutes to write.

(defn q1 [args]
  (let [max_arg (apply max args)
        next_max_arg (apply max (remove #(= % max_arg) args))
        ]
      (* next_max_arg max_arg)))

(defn q2 [arg]
  (inc arg))

(defn q3 [arr]
  (/ (reduce #(+ %1 %2) arr) (count arr)))

(defn q4 [arr]
  (let [avg (/ (reduce #(+ %1 %2) arr) (count arr))]
    (map #(- %1 avg) arr)))


(println (q1 [2 3 1 10 5 7]))
(println (q2 7.0))
(println (q3 [1 2 3 4 5 6 7 8 9 10]))
(println (q4 [1 2 3 4 5 6 7 8 9 10]))

Results

70
8.0
11/2
(-9/2 -7/2 -5/2 -3/2 -1/2 1/2 3/2 5/2 7/2 9/2)

Visual studio c++ 2011.

proxy20:
Which compiler are u using?