₦airaland Forum

For example, if 10 assignments were added to the list, with the name
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
The iteration technique will get data in the following order:
Compare: 1 and 2, 1 and 3, 1 and 4, 1 and 5, 1 and 6, 1 and 7, 1 and 8, 1 and 9, 1 and 10
Compare: 2 and 3, 2 and 4, 2 and 5, 2 and 6, 2 and 7, 2 and 8, 2 and 9, 2 and 10
Compare: 3 and 4, 3 and 5, 3 and 6, 3 and 7, 3 and 8, 3 and 9, 3 and 10
Compare: 4 and 5, 4 and 6, 4 and 7, 4 and 8, 4 and 9, 4 and 10
Compare: 5 and 6, 5 and 7, 5 and 8, 5 and 9, 5 and 10
Compare: 6 and 7, 6 and 8, 6 and 9, 6 and 10
Compare: 7 and 8, 7 and 9, 7 and 10
Compare: 8 and 9, 8 and 10
Compare: 9 and 10

An array and a loop is all you need.

As tr3y aptly stated, you simply need to loop it.

Assuming your data structure is an array or even array-like, the algorithm would then be as follows:

For each [element] 1 - 10
    Take each [subsequent element] until 10
        Compare [element] with [subsequent element]
    Finish/Close loop
Finish/Close loop

<pre>
<code>
//JAVA
for(int i = 0; i < arr.length; i++){

int firstNum = arr[i];
for(int j = i+1; j < arr.length; j++){

int secondNum = arr[j];

if(secondNum==firstNum){
//do stuff
}
}

}


//PHP

for($i = 0; $i < count($arr); $i++){

$firstNum == $arr[$i];
for($j = $i+1; $j < count($arr); $j++){
$secondNum = $arr[$j];
if($secondNum == $firstNum){
//do stuff
}
}
}

//C#

for(int i = 0; i < arr.Length; i++){

for(int j = i+1 ; j < arr.Length; j++){

if(arr[i] == arr[j]){
//do stuff
}

}

}




//Javascript

for(var i = 0; i < arr.length; i++){


for(var j = i+1; j < arr.length; j++){

if(arr[i]===arr[j]){
//do stuff
}

}

}


</code>
</pre>

Hopefully, you speak one of these langauges. All you need do now is copy and paste.

cheghoon01:
For example, if 10 assignments were added to the list, with the name
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
The iteration technique will get data in the following order:
Compare: 1 and 2, 1 and 3, 1 and 4, 1 and 5, 1 and 6, 1 and 7, 1 and 8, 1 and 9, 1 and 10
Compare: 2 and 3, 2 and 4, 2 and 5, 2 and 6, 2 and 7, 2 and 8, 2 and 9, 2 and 10
Compare: 3 and 4, 3 and 5, 3 and 6, 3 and 7, 3 and 8, 3 and 9, 3 and 10
Compare: 4 and 5, 4 and 6, 4 and 7, 4 and 8, 4 and 9, 4 and 10
Compare: 5 and 6, 5 and 7, 5 and 8, 5 and 9, 5 and 10
Compare: 6 and 7, 6 and 8, 6 and 9, 6 and 10
Compare: 7 and 8, 7 and 9, 7 and 10
Compare: 8 and 9, 8 and 10
Compare: 9 and 10

A[] = {1,2,3......10};
for (i=1 to 10; i++)
{
for (j = i to 10; j++)
{
compare(A[i] and A[j]);
}

}