Q3. The man's age 4yrs ago was 448÷5= 89.6.
His current age is 89.6+4=93.6.
Since he is 5 times older that his son 4yrs ago. The son's age was 89.6÷5= 17.92. Therefore, his current age is 17.92+4= 21.92.
The man's current age = 95 yrs 6 days
The son's current age = 21yrs 92days

Xflint:
7b) solution

Log(x² + 4) = 2 + log^x - log²⁰
log(x² + 4) = log¹⁰⁰ + log^x - log²⁰
log(x² + 4) = log (100 X x/20)

Now, you cross multiply
given you 20(x² + 4) = 100 X x
20x² + 80 = 100x

now divid by 20
[strike]20[/strike]x²/[strike]20[/strike] - [strike]100[/strike]x/[strike]20[/strike] + 80/[strike]20[/strike] = 0

x² - 5x + 4 = 0
x² - 4x - x + 4 = 0
(x² - 4x)(x + 4)
x(x - 4) -1(x - 4)
(x - 1)(x - 4)
x = 1 or 4

the strike is not working here just check
http://forum.mathsboard.com/t594-solve-this-neco-past-questions-2016-2017#1517

I admire you...wish I could do what you just did.

TamedWolf90:

I admire you...wish I could do what you just did.

Thanks, i just use it to keep myself busy. And besides i am beginning to forget some of the maths them

Laive:
Too many critics, so I had to remove the thread. All the same, I HAVE LEARNT THE RIGHT WAY OF DOING IT. Thanks!

Four years ago; son's age=x-4, father's age=5x-4. Now, product of their ages four years ago= (5x-4)(x-4)=448. Expnsion of the bracket gives:5x^2-24x+16=448 and this equals 5x^2-24x-432=0. Now following the a x c formula to expand b,a=5,c=-432,b=-24, a x c=5 x -432 =-2160. Look for two numbers such that when u multiply u get -2160 n wen u add u get -24, the two numbers are -60 and 36. Now d equation above becomes: 5x^2-60x+36x-432=0, when u group and find the common factor, u get 5x(x-12) + 36(x-12)=0, (5x+36)(x-1

Elxandre:
disgraceful!

artful doger,na ya answer be dis?

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.

Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

. My dear recommend new maths teachers for your school...students of the school are so suffering

Laive:
Too many critics, so I had to remove the thread. All the same, I HAVE LEARNT THE RIGHT WAY OF DOING IT. Thanks!

I can help you. Let son's present age= x and father's present age=5x. Four years ago; son's age=x-4, father's age=5x-4. Now, product of their ages four years ago= (5x-4)(x-4)=448. Expnsion of the bracket gives:5x^2-24x+16=448 and this equals 5x^2-24x-432=0. Now following the a x c formula to expand b,a=5,c=-432,b=-24, a x c=5 x -432 =-2160. Look for two numbers such that when u multiply u get -2160 n wen u add u get -24, the two numbers are -60 and 36. Now d equation above becomes: 5x^2-60x+36x-432=0, when u group and find the common factor, u get 5x(x-12) + 36(x-12)=0,then (5x+36)(x-12)=0, 5x+36=0 or x-12=0, x=-7.2 or 12, since age cannot b negative, therefore x=12, so son's prese nt age=x=12 and father's age=5x=60.

Please I need a maths tutor for myself... 08182676459, dats my number. Am in Abuja.

canymix:
. My dear recommend new maths teachers for your school...students of the school are so suffering

Am telling you bro! It didn't take me up to an hour to trash all the neco theory questions for my students in SS 2! Any maths teacher who can't solve those questions is not fit to be called a maths teacher! By the way, make una employ better maths teachers for that una school oh! I won't mind porting to that school if the pay is worthwhile! Cc Wealthgang

Laive:
Too many critics, so I had to remove the thread. All the same, I HAVE LEARNT THE RIGHT WAY OF DOING IT. Thanks!

I can help you. Let son's present age= x and father's present age=5x. Four years ago; son's age=x-4, father's age=5x-4. Now, product of their ages four years ago= (5x-4)(x-4)=448. Expnsion of the bracket gives:5x^2-24x+16=448 and this equals 5x^2-24x-432=0. Now following the a x c formula to expand b,a=5,c=-432,b=-24, a x c=5 x -432 =-2160. Look for two numbers such that when u multiply u get -2160 n wen u add u get -24, the two numbers are -60 and 36. Now d equation above becomes: 5x^2-60x+36x-432=0, when u group and find the common factor, u get 5x(x-12) + 36(x-12)=0,then (5x+36)(x-12)=0, 5x+36=0 or x-12=0, x=-7.2 or 12, since age cannot b negative, therefore x=12, so son's prese nt age=x=12 and father's age=5x=60.

Iceberg3:


artful doger,na ya answer be dis?

solved two Before abandoning the task.
Too busy to post them on NL.

These things are basic stuff.
Suppose I couldn't even solve them, I'm not a math teacher

Are you alk writing in TONGUE?

Common confusion. If you say 5 times OLDER THAN, you expect x-y = 5y therefore x = 6y
If you mean 5 times AS OLD As, then x = 5y
Where x and y are the ages of father and son respectively. Math teachers should learn to state questions correctly.


Annakrutitskaya
Senior Member
Russian
Hello!

I would be grateful for the help - I am confused with underlined explanation. (from Gmat sentence correction)

Right: The man is FIVE TIMES AS OLD AS his grandson.
Wrong: The man is FIVE TIMES OLDER THAN his grandson.

The first sentence means that the mans age = 5 x his grandsons age. In the second example, the author is technically saying that the man is six times as old as his grandson. This meaning is unlikely; the author probably meant “five times as old.”

Why 'five times older than' equals 'six times as old as'?

Thank you!


Annakrutitskaya, Aug 15, 2014 #1

Horlawale1:
Last week a first class holder in mathematics is still looking and crying for job on this forum.

And some ppl are still looking for a guru to come solve some abstract disturbing Mathematics.

Money making on my mind.

You wouldn't have a say if not for the stupidity of the Nigerian society were celebrities are celebrated above scholars and thereby making a mockery of them(scholars).

[color=#006600][/color] The sons age is 12..... Dads age is 60

It is unfortunate that the so-called mathematicians don't reason deeply anymore. You are the only one that pointed that error out and I appreciate you for it. Thank you

RaggedyAnn:
Common confusion. If you say 5 times OLDER THAN, you expect x-y = 5y therefore x = 6y
If you mean 5 times AS OLD As, then x = 5y
Where x and y are the ages of father and son respectively. Math teachers should learn to state questions correctly.


Annakrutitskaya
Senior Member
Russian
Hello!

I would be grateful for the help - I am confused with underlined explanation. (from Gmat sentence correction)

Right: The man is FIVE TIMES AS OLD AS his grandson.
Wrong: The man is FIVE TIMES OLDER THAN his grandson.

The first sentence means that the mans age = 5 x his grandsons age. In the second example, the author is technically saying that the man is six times as old as his grandson. This meaning is unlikely; the author probably meant “five times as old.”

Why 'five times older than' equals 'six times as old as'?

Thank you!


Annakrutitskaya, Aug 15, 2014 #1

Joice21:
I can help you. Let son's present age= x and father's present age=5x. Four years ago; son's age=x-4, father's age=5x-4. Now, product of their ages four years ago= (5x-4)(x-4)=448. Expnsion of the bracket gives:5x^2-24x+16=448 and this equals 5x^2-24x-432=0. Now following the a x c formula to expand b,a=5,c=-432,b=-24, a x c=5 x -432 =-2160. Look for two numbers such that when u multiply u get -2160 n wen u add u get -24, the two numbers are -60 and 36. Now d equation above becomes: 5x^2-60x+36x-432=0, when u group and find the common factor, u get 5x(x-12) + 36(x-12)=0,then (5x+36)(x-12)=0, 5x+36=0 or x-12=0, x=-7.2 or 12, since age cannot b negative, therefore x=12, so son's prese nt age=x=12 and father's age=5x=60.

Thanks Joice21. I can't afford to do Maths without people like you. But my main wahala is: "finding a number that when u multiply... and when u add...". All the same, thanks...

famagusta:
Please I need a maths tutor for myself... 08182676459, dats my number. Am in Abuja.

You can join the forum
@http://forum.mathsboard.com/

Mypeople2:
3) The father is 60 years old while the son is 12years

you are totally wrong! Who was your mathematics teacher? He/she did not try at all.

Check it out

oohgdtjb vb

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.

Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

Q3.

Present ages are: Son = 12 years
Man = 60 years


Q. 7a

n = 0



Im coming.....

Xflint:
7b) solution

Log(x² + 4) = 2 + log^x - log²⁰
log(x² + 4) = log¹⁰⁰ + log^x - log²⁰
log(x² + 4) = log (100 X x)
                              20

Now, you cross multiply
given you 20(x² + 4) = 100 X x
20x² + 80 = 100x

now divid by 20
20x² - 100x + 80 = 0
20         20      20


x² - 5x + 4 = 0
x² - 4x - x + 4 = 0
(x² - 4x)(x + 4)
x(x - 4) -1(x - 4)
(x - 1)(x - 4)
x = 1 or 4

the strike is not working here just check
http://forum.mathsboard.com/t594-solve-this-neco-past-questions-2016-2017#1517
[s][/s]

I like your solution. I could only fully remember the quadratic almighty formular.... you really dissected these problems. I love maths so much. This is my best post and these NECO questions are easy enough. Any maths teacher that cannot solve this is not worthy of being called a maths teacher. QED

Wealthgang:
Check Out The Recent NECO Math Questions Some School Teachers Couldn't Solve


Same order they appeared in d question paper.

Q3) A man is 5 times older than his son. Four yrs ago, d product of their ages was 448. Find their present ages.

Q7a) Find d value of n if
3²ⁿ⁺¹ - 4(3ⁿ⁺¹) + 9 = 0

7b) Solve d eqn:
log(x²+4) = 2 + logx - log20

Q9a) A two-digit number is such that its tens digit is greater than its unit digit by 5. If d number is 14 less than 3 times d product of its digits, find d number.

Let's see how many Nairalanders can give it a shot. Anyone who answers correctly will get a reward.

Cc: Xflint, Boyoski09, truth12, themall, Danosaur007, Jerrypolo, 8BitGee, integritylady, Laive, lilmonarch

Those days where men where boys i can trash these in minutes but now i'm all rusty. Nice one by d way and as for the teacher should not be teaching maths. Find another subject like irk/crk or even yoruba trust me he/she will perform better

Q3: Son is 12 yrs, The Father is 60 yrs Q7a: n= 1 or 0 Q7b: x= 1 or 4 Q9a: The number is 94

BLoomfrancs:


Guy you no dey shame to post this rubbish here. People are talking about building robots that can fight in battles like ground soldiers you are here posting nonsense.

Smh! Then post pictures of d robots u've built or

Nely77:

you are totally wrong! Who was your mathematics teacher? He/she did not try at all.

Mr. Totally Wrong, what's the answer pls?

laperson:
It is unfortunate that the so-called mathematicians don't reason deeply anymore. You are the only one that pointed that error out and I appreciate you for it. Thank you

Thank God I have people that reason like I do. I think those examiners were even oblivious of this subtle error. I started my workings the same way this sister pointed but lost interest as the problem became rather more complicated. The moment you as a Mathematician start getting more complicated results which are not reasonable you retrace your steps.

RaggedyAnn:
Common confusion. If you say 5 times OLDER THAN, you expect x-y = 5y therefore x = 6y
If you mean 5 times AS OLD As, then x = 5y
Where x and y are the ages of father and son respectively. Math teachers should learn to state questions correctly.


Annakrutitskaya
Senior Member
Russian
Hello!

I would be grateful for the help - I am confused with underlined explanation. (from Gmat sentence correction)

Right: The man is FIVE TIMES AS OLD AS his grandson.
Wrong: The man is FIVE TIMES OLDER THAN his grandson.

The first sentence means that the mans age = 5 x his grandsons age. In the second example, the author is technically saying that the man is six times as old as his grandson. This meaning is unlikely; the author probably meant “five times as old.”

Why 'five times older than' equals 'six times as old as'?

Thank you!


Annakrutitskaya, Aug 15, 2014 #1

God bless you, my sister!

Phi001:

Mr. Totally Wrong, what's the answer pls?

Go to school if you have not been to school. If you had been to school, then go back there and learn because you have learnt nothing since you cannot solve basic math's.

but tbh, when I think of what I solve as maths here in uni, I am reminded that 'maths' in secondary school is painfully easy!!!!

Laive:
I HAVE LEARNT THE RIGHT WAY OF DOING IT.

U've accmplished d most important thing which is to LEARN. Forget critics