Oyind17:
You did. Wear them and take a selfie

Well, I want Nike Jordan

jo997:



<b> pressure </b> hence there is continuous flow then I see no need of using the word pressure to answer the question. moreover the tanks are at different elevations with openings are varied heights, so the naturally the water will be force out through the openings.

haibe:
haba they cant fill at the same time exactly. One must fill up first

3moses:

not being a science student...u should be vast in reasoning (not an insult pls)...3 & 4 are at d base...3 fil up to d level of where d link pipe enters 4 and stops there, 3 remains dt level til 4 meet it and both fils to d brim at same time.

haibe:
dude you be olodo (no offence), tank 4 fills up first.. a primary school pupil will understand this.. not in the mood for typing, i would showed u a thorough analysis. But read through this thread from page 1, several people have given the correct logic.

Mrtolotolo:


Lolzzz..

The guy is right and you are wrong..
simple video on youtube will help you with the answer.

haibe:
actually the purpose of that post was to give him a taste of the insult he gave to me.. he thought he is wise.

vodutive:


ehhm please explain exactly how you accomplished that?

1) he clearly stated no "insult"

2) you are wrong

3) he is wise..because he is right

DEXTROVERT:
Tank 1 Will Be The First To Be Full To The BRIM

FIZIK:
Cannot say based on the information given.

How fast is the tap running?
How fast are the tanks losing water?
what level is full and how long does it have to hold water at that level?

If the tap runs faster that the outlets it would be 1 hitting the brim first followed by 2.
If not and assuming all outlets have equal capacity then 3 and 4 would progress simultaneously.

3moses:
most nairalanders are olodos....
3 & 4 filled to d brim at d same time...
this is called law of equal proportion...

femi4:
I don't do copy and paste. That video is incorrect.

Tank 3 will overflow before 4.

By applying Bernoulli's equation, we
can actually calculate the water level (head) difference of the two tanks to be:

h = (Q / A)^2 / (2 * g)

Where Q is the flow rate between the tanks and
A is the cross sectional area of the connector.

Say we have a A = 1.6 square inches (about the size of a quarter), and that Q = 20 gallons per minute.The water level in tank 3 will be 3 inches higher than in tank 4. Also, if you account for friction losses, this height difference will actually be even greater.

tk4rd:
The size or cross-sectional area of the connector have nothing to do in this case.. This is not a case of "closed pipe hydraulics" neither is it a case of "pipes under pressure"..
All that matters here is "Atmospheric Pressure", "Gravity", and "difference in level between the connectors"..
Since all the tanks are open to the atmosphere, the atmospheric pressure will always ensure to balance the water levels in the tanks once they are above the highest point of the highest interconnecting junction in the whole set up.
Therefore, at the point when Tanks 3 & 4 are full and overflowing, the water in Tank-2 will maintain a level that is equal to the top level of the water in Tanks 3 & 4; and if you observe carefully, this final water level is above the points of interconnections between the tanks.
Even if the water from the tap above stops flowing, the water in Tank-2 will remain stable at the level coinciding with the top of Tanks 3 & 4. Also, the water in Tanks 3 & 4 will remain full and stable without overflowing until the tap above starts flowing again.

tk4rd:
The size or cross-sectional area of the connector have nothing to do in this case.. This is not a case of "closed pipe hydraulics" neither is it a case of "pipes under pressure"..
All that matters here is "Atmospheric Pressure", "Gravity", and "difference in level between the connectors"..
Since all the tanks are open to the atmosphere, the atmospheric pressure will always ensure to balance the water levels in the tanks once they are above the highest point of the highest interconnecting junction in the whole set up.
Therefore, at the point when Tanks 3 & 4 are full and overflowing, the water in Tank-2 will maintain a level that is equal to the top level of the water in Tanks 3 & 4; and if you observe carefully, this final water level is above the points of interconnections between the tanks.
Even if the water from the tap above stops flowing, the water in Tank-2 will remain stable at the level coinciding with the top of Tanks 3 & 4. Also, the water in Tanks 3 & 4 will remain full and stable without overflowing until the tap above starts flowing again.

Spandy:
If the pressure from the water source(tap)is very high, I think tank 1 will be filled up first before any other tank owing to the tiny size of the pipe linking eachother.

Jdesilentkiller:
My problem with this kind of post is that the OP might not even know the real answer.. And he will keep people guessing until he got the answer or got really confused and the thread die because of too much debate by the association of ITKs.. Shalom

Donshemzy1234:
Who move the rubbish to front page

ngmgeek:
How much did they pay you for this question. Tell us first

martineinstein:
fluid mechanics expert.... tank 1 will get filled first

dipopooo:

I knw d ansa bro. I'm not a dullard

tk4rd:
So,, TELL US THE ANSWER.!!

ladyF:
My answer is tank 3.

Tank 1 can't get filled up because it keeps losing water to tank 2.

Tank 2 can't get filled up because it keeps losing water to tank 3.

Tank 3 can only start filling up tank 4 once it gets sufficient volume/pressure to push water up that height to tank 4. So it's going to get filled up before tank 4 does.

Hope ayam not an olodo o. Oya clap for LadyF.

It's LadyF again

dipopooo:

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