SirdimayG:
Hello guys. Have been using my new school physics. I feel like reading another physics textbook to advance my knowledge of different definition and formulas. If you are to recommend,[b][/b] which textbook will you implote me to buy-well explained textbook tho.

Can you access PDF files on your phone?
If yes, I'd recommend Physics 11 and 12 by Mcgrawhill Hill. Thats what I use but it's quite lengthy and Jamb is by the corner.

Optimist1998:

Can you access PDF files on your phone?
If yes, I'd recommend Physics 11 and 12 by Mcgrawhill Hill. Thats what I use but it's quite lengthy and Jamb is by the corner.

pls send it to my email.
Oluchikris@yahoo.com

Optimist1998:

B-pisces

the correct answer is aphid

jupitre:

the correct answer is aphid

Yeah Donpre corrected that
Thanks by the way

kristian98:

pls send it to my email.
Oluchikris@yahoo.com

Optimist1998:

ok thanks. Do u still remember the download link?

kristian98:

Four cells with osmotic potential equivalent to that of 3% salt solution were immersed respectively in solutions
of different concentrations labeled as follows: I = 4% salt solution; II = 6% salt solution III = 1% salt solution;
IV = 10% salt solution; V = 5% salt solution. Which of the solutions will cause an increase in osmotic
pressure within the cell?

What the ?!
At first I thought it was a physics question...
I'm going with III

kristian98:
Pls show workings for the first question on electricity

forgive my handwriting... I hope you get it

Optimist1998:

What the?!
At first I thought it was a physics question...
I'm going with III

lol. Its biology. Ok i see.

[quote author=IemFava post=55178176]4768[/quote
God bless .
It is PV/T1=16p2v2/t2

Optimist1998:

What the ?!
At first I thought it was a physics question...
I'm going with III

it biology na.... 1% would be correct.

A hypotonic solution would cause inflow of water into the cell hence increasing its osmotic pressure

kristian98:

lol. Its biology. So why did u pick 1%. Why not 10% since it has more concentration and would lead to a high osmotic pressure.
Remember osmosis is from a region of lower conc. to higher conc.

Osmotic pressure = pressure as a result of Water
To paraphrase the question
Which of the following cells will be turgid/hard due to the water entering it?

That's how I arrived at III
Phew it took me time tho

Donpre:

it biology na.... 1% would be correct.

A hypotonic solution would cause inflow of water into the cell hence increasing its osmotic pressure

I was already calcuating
It was looking like a question on cells/batteries/EMF

Optimist1998:
I was already calcuating It was looking like a question on cells/batteries/EMF

LMAO. This made my day

kristian98:

i feel this question is wrong. Pls where did u get it from.
*speed of sound is faster at 30 degrees
*sound waves can be reflected
*option B is also correct
i think u made a typo. The question is supposed to be "which of these is NOT correct about sound waves"

None of the options is right about light so even though I change the question to NOT....... We'll have four correct options.


I don't know if the mistake is from the past question or Jamb itself.

Optimist1998:
I was already calcuating It was looking like a question on cells/batteries/EMF

hehehe.... someone either likes physics too much or fears it.

Pressue
In the fig above if the atmospheric pressure is 760mm, the pressure of the chamber G is
A. 660mm
B. 690mm
C. 830mm
D. 860mm

Unanswered for days

kristian98:
0.16g of methane when burnt raises the temperature of 100g of water by 40°C. What is the of combustion of methane when if the heat capacity of water is 4.2 Jg-1°C-1?

(CH4 = 16)

H= mc@
H=100x4.2x40
=168000

If 16g of methane liberated 168000 of heat
0.16g will liberate 168000x0. 16/16
=1680

Optimist1998:

H= mc@
H=100x4.2x40
=168000

If 16g of methane liberated 168000 of heat
0.16g will liberate 168000x0. 16/16
=1680

sorry mister its 168....

Q = Mc0
= 0.1*4200*40(I converted to kg)
= 16800

mole ratio = 0.16/16 = 0.01

0.01*16800 = 168

Optimist1998:

H= mc@
H=100x4.2x40
=168000

If 16g of methane liberated 168000 of heat
0.16g will liberate 168000x0. 16/16
=1680

Edit:
wait oh lemme cross check my work

ok thats what i was even looking at. these guys chose 1680 and i dont know where they got it from. 168 is not in the option sef

Donpre:
sorry mister its 168....
Q = Mc0 = 0.1*4200*40(I converted to kg) = 16800
mole ratio = 0.16/16 = 0.01
0.01*16800 = 168

But all the units are in grams..... any need to convert to Kg?

Optimist1998:

But all the units are in grams.....
any need to convert to Kg?

even though.
your multiplication has a flaw. 100 x 4.2 x 40 =1680 and not 16800
you would still arrive at 168

Optimist1998:

But all the units are in grams.....
any need to convert to Kg?

just a rule of mine... "Never solve physics is grams or chemistry in kilograms". I hate it when S.I unit f**ks up my work

kristian98:

even though.
your multiplication has a flaw. 100 x 4.2 x 40 =1680 and not 16800
you would still arrive at 168

past questions are mostly stupid... another rule of mine.

you sure the values are correct? maybe a typo somewhere or the question is just wrong

Donpre:

just a rule of mine... "Never solve physics is grams or chemistry in kilograms". I hate it when S.I unit f**ks up my work

you have to be flexible o. There are times when you convert, you end up not getting the correct answer

Donpre:

past questions are mostly stupid... another rule of mine.

you sure the values are correct? maybe a typo somewhere or the question is just wrong

lol. don't be a full cup bro. in every senseless thing, there is a sense.
there are times i think they made the most stupid mistakes. i end up discovering how 100% right they are. BE FLEXIBLE

kristian98:

even though.
your multiplication has a flaw. 100 x 4.2 x 40 =1680 and not 16800
you would still arrive at 168

The calculation should go this way instead


0.16g liberated 16800 of heat
16g will liberate 16800x16/0.16
=1680000
which is 1680KJ/mol


I think this is more appropriate

Lenz's law is a law of conservation of

a. energy b. Momentum c. electric current d. Electric charge

If two charge plates are maintained at a potential difference of 3kV, the work done in taking a charge of 600uC across the field is

a. 9.0j b. 0.8j c. 18.0j d. 1.8j

Donpre:
Lenz's law is a law of conservation of

a. energy b. Momentum c. electric current d. Electric charge

A

If two charge plates are maintained at a potential difference of 3kV, the work done in taking a charge of 600uC across the field is
a. 9.0j b. 0.8j c. 18.0j d. 1.8j

D

Optimist1998:
Unanswered for days

C - 830

Donpre:
C - 830

correct