6 cars

5 cars; 8-2-4-10-7

3 cars.. 5,4, and 7

8 & 2. 8 can navigate the space between 11 for 5 to move back, the space created will be enough for the blue car to find it's way out

4 cars
Car 4 tailgates Car 1
Car 7 parks vertically in space vacated by Car 4
car 10 parks vertically in space vacated by car 4
Car 2 parks parallel with cars 8 and 6

Is anybody answer this correctly? If no am ready to proof it out as a dealer
Car 5 and 8 need to move forward, then 2 will parked at the back of 1. Car 6 will follow 8, car 10 will reversed. Car 4 will move forward a bit while car 7 will parked at the back of 4 then car blue is ready to gooooooo.

7 cars will need to move.

Here's the moving order:

5 moves towards 9
2 moves to the other end closer to 1
8 moves closer to 3
6 follows 8
10 moves backwards to stay closer to 12
4 moves towards 2
7 moves in to the position previously occupied by 4

the blue ride can then zoom off

1StopRudeness:


That's not very smart kankan.....
unless car 7 won't mind bashing cars 4 a 10 any how...which kind manoeuvre does he wanna use to get out of its location cos there's technically no space btw 7 and 12.....the car isn't a snake u know...its only easy in theory(anyway the guy said logically not drivingcally)


3 cars gats move

Car 5 makes a curve reverse btw 2 and 10
Car 4 moves closer to the back of car 1
Car 7 follows car 4 bumper to bumper
Blue car is free to cruise

by your logic, how will the blue car manoeuvre between 4 and 10? ...or in your scenario, between 7 and 10? I am waiting!

5,2,8,6,10,4,7

8. 2. 4. 10. 7

sleekyjay:


logically, just two cars need to move. the cars labeled 5 & 7.

5 moves to park vertically between 2 & 10.
7 moves to park horizontally between 1 & 4

then the blue car can get to the other end..

I don’t quite agree with your analysis. The arrow seems to suggest that the car has to follow that straight line trajectory, it cannot deviate from it. If this is correct, then Car 5 moving in between Cars 2 and 10 wouldn’t solve the problem. Notice that the objective is for the blue car to exit the garage, since the exit is at the tip of the arrow. That said, I would suggest that Car 5 draw level with Car 1 by moving further inwards, this makes room for Car 2 to fill up the space between Cars 1 and 4, whilst Cars 10 and 7 queue up behind Car 5. This frees the entire stretch of the arrow and the blue car can make its way. So, four cars in all; Cars 5, 2, 10 and 7.

I would suggest that Car 5 draw level with Car 1 by moving further inwards, this makes room for Car 2 to fill up the space between Cars 1 and 4, whilst Cars 10 and 7 queue up behind Car 5. This frees the entire stretch of the arrow and the blue car can make its way. So, four cars in all; Cars 5, 2, 10 and 7.

effectively without stress is 3 cars, 2,10 n 7
based on d space but if d car has to squeeze thru den its two 2 n 7

4 cars. c4 move close to c1. 7 and 10 move to the space then car2 wil be carefully move parallel to 8 and 6. Just 4 cars; 4,7,10 and 2

If they can only move front or back...8 moves front, 2 moves back, 4 moves front and 10 and 7moves front.

5 cars (You need to move cars 5, 2, 4, 7 and 10 in that sequence and I can drive out my lamborghini.

1StopRudeness:


That's not very smart kankan.....
unless car 7 won't mind bashing cars 4 a 10 any how...which kind manoeuvre does he wanna use to get out of its location cos there's technically no space btw 7 and 12.....the car isn't a snake u know...its only easy in theory(anyway the guy said logically not drivingcally)


3 cars gats move



Car 5 makes a curve reverse btw 2 and 10
Car 4 moves closer to the back of car 1
Car 7 follows car 4 bumper to bumper
Blue car is free to cruise

Asked him pls and to think that some pipo liked his answer

move 8 forward
move 2 backward
move 4 forward
move 10 & 7 forward
if u like u can move 5 but it is not blocking the blue car in anyway from leavivg the pack

Hozier:
What is the lowest number of cars need to be moved for the blue car to make it to the other end.

Give answer with explanation on which cars need to move and to where.


Let's go.

5 move forward for 2 to park as 9
8 and 6 move forward for 10 to reverse
4 move forward for 7 to park as 9
Blue car move out

8.2.5.4.10 nd 7

You have to move cars 5, 8, 2, 4, 6, 10 and 7 for the blue car to get to the other side. SIMPLE.

Hozier:
What is the lowest number of cars need to be moved for the blue car to make it to the other end.

Give answer with explanation on which cars need to move and to where.


Let's go.

3cars 5 4 n 7

Hozier:
What is the lowest number of cars need to be moved for the blue car to make it to the other end.

Give answer with explanation on which cars need to move and to where.


Let's go.

5,2,8,4,7$10

5 cars need to move
8 moves forward, 2 moves backwards, 4 moves forward, 7 parks at the back of 4 and 10 moves sideways.
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www.coloredsupergirls..com

Hozier:
What is the lowest number of cars need to be moved for the blue car to make it to the other end.

Give answer with explanation on which cars need to move and to where.


Let's go.

5,8,2,10,4 and 7

8,2,4,10,7

Without scratch:
5,4&7 only
5 will be packed in b/w 2&10..
4 will close down 1 and 7 will
follow up 4.(1,4,7 in a lane).
The blue will jejely pass through.


With scratches:
The blue car will 007(ly) have a head-on
through 2,10&7 and pass through with few
scratches and no casualty.

ClitoPen:
5 cars...

5,2,4,7,10

Modified: So we don reach fp at last

If you move 2 up, it will block #4 which needs to move two spots to allow 7 and 10.

1. move #8 left
2. move #2 down
3. move #4 left twice
4. move #10 up twice
5. move #7 up

Hozier:
What is the lowest number of cars need to be moved for the blue car to make it to the other end.

Give answer with explanation on which cars need to move and to where.


Let's go

5,2,8,6,10,4,7

5, 4, 7, 10, 8, and 2

7cars, I cn giv u d breakdown

Hozier:
What is the lowest number of cars need to be moved for the blue car to make it to the other end.

Give answer with explanation on which cars need to move and to where.


Let's go.

7