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Please Help. Show Full Work by Mike4S: 3:05pm On Mar 02, 2019 |
110 members of a sports club play at least one of
the games, football, basketball and volleyball. If 20
play football and basketball only,15 play football
and basketball only, 26 play basketball and
volleyball only,x play all the three games, 2x each
play only one game, how many play basketball
altogether |
Re: Please Help. Show Full Work by Nobody: 3:26pm On Mar 02, 2019 |
Mike4S:How much.. |
Re: Please Help. Show Full Work by Nobody: 5:47pm On Mar 02, 2019 |
Mike4S:you wrote two different values for football and basket ball players. what about number of football and volleyball players I guess you wanted to write 20 people played basketball and football only while 15 people played volleyball and football if I am correct check the picture below to see the solution to the question |
Re: Please Help. Show Full Work by Nobody: 5:59pm On Mar 02, 2019 |
Mike4S:the answer is below you can send me a WhatsApp message on so that in case you have any such question to solve l can be of aid to you
|
Re: Please Help. Show Full Work by Mike4S: 8:14pm On Mar 02, 2019 |
matex97:Thanks for the solved Mathematics I've saved your number for subsequent ones |
Re: Please Help. Show Full Work by Nobody: 8:46pm On Mar 02, 2019 |
Mike4S:OK you can send me a message now so I can save yours |
Re: Please Help. Show Full Work by Akomitipoju(m): 4:47pm On Oct 01, 2019 |
This question is in the New General Mathematics textbook SS1 by MF Macrae et al. Exerxise 8d No13... The answer to it is 52 and not 67. I also got 67 and I am confused... how will I tell my student the answer at the back is not correct? |
Re: Please Help. Show Full Work by Mike4S: 5:59pm On Oct 01, 2019 |
Akomitipoju:Rather it's NGM authors that made mistake. The answer is 67 everywhere. SOLUTION: Let the Sports Club be denoted by U, . F = Football . B = Basketball . V = Volleyball . n(U) = 110 . n(FnBnC') = 20 . n(FnVnB') = 15 . n(BnVnF') = 26 . n(FnBnV) = x . n(FnB'nV') = n(F'nBnV') = (F'nB'nV) = 2x . Note: B', F' and V' denote the complements of the various sets(clubs). . n(U) = n(FuBuV) + n(FuBuV)' . In this case, n(FuBuV)' is empty. . 110 = 2x + 20 + x + 15 + 2x + 26 + 2x . 110 = 61 + 7x . 49 = 7x . x = 7 . n(B) = 20 + 26 + x + 2x . n(B) = 20 + 26 + 3x . n(B) = 20 + 26 + 21 . n(B) = 67 . 67 members play Basketball altogether. 2 Likes |
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