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Hardest Maths Question by Rasulullah: 2:21pm On Nov 09, 2010
Hey guys this question was given in question 1,essay part, 2009 FINAL COWBELL NASSMAC COMPETITION LAGOS, please we seriously need help on it.(the numbers after the letters are powers)
x+y+z=1
x2+y2+z2=34
x3+y3+z3=97

Re: Hardest Maths Question by Rasulullah: 3:24pm On Nov 09, 2010
A
Re: Hardest Maths Question by EMMYD01(m): 8:56pm On Nov 09, 2010
Raise to power what,is it power 2. I mean d numbers attached to alphabets
Re: Hardest Maths Question by ccollins(m): 9:01pm On Nov 09, 2010
Xd
Re: Hardest Maths Question by Nobody: 9:43pm On Nov 09, 2010
^^ answer it now, mr UNN
Re: Hardest Maths Question by Nobody: 9:45pm On Nov 09, 2010
@op, what is the question or what are we to do? Are we to find the value of the variables?
Re: Hardest Maths Question by Rasulullah: 9:35am On Nov 10, 2010
You are required to find x, y, z
Re: Hardest Maths Question by Nobody: 2:50pm On Nov 10, 2010
Will simultaneous equation or matrix solve the question?
Re: Hardest Maths Question by bforce(m): 3:01pm On Nov 10, 2010
nither simultaenous nor matrix can, i fink it has to do with smtn higher
Re: Hardest Maths Question by Rasulullah: 3:32pm On Nov 10, 2010
Matrix wil not solve it because all d coefficients are zero
Re: Hardest Maths Question by EMMYD01(m): 3:49pm On Nov 10, 2010
I'll get back here in d evening cos presently am in d vehicle 4rm ibadan to lag. When i get home,i'll try it
Re: Hardest Maths Question by Rasulullah: 3:55pm On Nov 10, 2010
Safe journey
Re: Hardest Maths Question by Rasulullah: 5:21pm On Nov 10, 2010
I think it wil not b solve using substitution method, rather using coeffitients does not come here
Re: Hardest Maths Question by segunanis: 12:37pm On Nov 11, 2010
Complex solutions

Complex solutions
Re: Hardest Maths Question by Nobody: 12:35am On Nov 12, 2010
No mathematician in the house?
Re: Hardest Maths Question by Odirah(m): 12:39am On Nov 12, 2010
D question wil be solved using a subtitution method,its a simultaneous equation with 3 variables.
Re: Hardest Maths Question by bforce(m): 6:35am On Nov 12, 2010
if u re gonna use substitution its gona be very complex nd out of control cos i tried it, anyway still du wat u cn cos i really wnt tu know the answer
Re: Hardest Maths Question by abioila(m): 7:42am On Nov 12, 2010
Hold on guys.i tink i shuld b able to solve it.
Re: Hardest Maths Question by EMMYD01(m): 8:09am On Nov 12, 2010
Guys,i don't think d question is right because its a simultaneous linear equation with three unknowns and the step i took is take a pair of d equation and eliminate one of d variables and later take another pair ,then bring together what u got 4rm d first and second pairing and then solve it like simultaneous equation. Then finally substitute these values in one of d origina equation to obtain d third value. But i've been solving other question like this but in this one now the varibles are giving me zero. Mayb its not correct.
Re: Hardest Maths Question by Rasulullah: 8:58am On Nov 12, 2010
D question is 100% correct
Re: Hardest Maths Question by Seun(m): 8:59am On Nov 12, 2010
The 3rd equation is probably wrong.
Re: Hardest Maths Question by Rasulullah: 9:00am On Nov 12, 2010
I wonder why dey gave us dat question last year, at 14 yrs
Re: Hardest Maths Question by Rasulullah: 9:06am On Nov 12, 2010
I hv d answers, but my problems are d steps and solutions, I GOT D ANSWER FROM MICROSOFT MATHS, but i think it uses graphical method with 3d, I NEED UR PERMISSIONS TO PASTE D ANSWER, but help me take to a lecturer or prof
Re: Hardest Maths Question by abioila(m): 9:06am On Nov 12, 2010
Mehn dis work na die.but am vry sure its GUSSIAN rule that one can use 2 solve it,i.e makn one of d variables subjet of formla in one of d 3 equations nd pairn 2 of d oda 3 equations,substn d value of the changd subject of formla in those equatns then solvin simultaneously.afta dat replace d values of the variables in any of d 3 initial equatns to get ur answa.but as pa dis work d fuda u go d more complicatd d solutn.and dis was d first tin i did today on d bed,now am avn serious headache.
Re: Hardest Maths Question by Nobody: 9:18am On Nov 12, 2010
Oga maths oo
Re: Hardest Maths Question by Tunsbobo(m): 9:41am On Nov 12, 2010
Omo, i tried using 3X3 matrix, but my answer wasn't correct! I don't know how to answer this question, i also tried substitution method but the question just became more complex.
Re: Hardest Maths Question by abioila(m): 10:59am On Nov 12, 2010
U cant use matrix because 4rm what I noe u can only use matrix to solve linear simultaneous equatns but dis one is not linear.
Re: Hardest Maths Question by Semitexy: 11:10am On Nov 12, 2010
dont provide the answer yet because to every pro there is always a solution
Re: Hardest Maths Question by Nobody: 12:07pm On Nov 12, 2010
@topic im almost there
Re: Hardest Maths Question by Rasulullah: 1:08pm On Nov 12, 2010
[h3]I am alwayz saying dis, MATRIX wil not solve dis because d coefficients are all d same(=1) [/h3]

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Re: Hardest Maths Question by Ymodulus: 3:56pm On Nov 12, 2010
Mehn dis work na die.but am vry sure its GUSSIAN rule that one can use 2 solve it,i.e makn one of d variables subjet of formla in one of d 3 equations nd pairn 2 of d oda 3 equations,substn d value of the changd subject of formla in those equatns then solvin simultaneously.afta dat replace d values of the variables in any of d 3 initial equatns to get your answa.but as pa dis work d fuda u go d more complicatd d solutn.and dis was d first tin i did today on d bed,now am avn serious headache.
stories work am guy
Re: Hardest Maths Question by Nobody: 4:54pm On Nov 12, 2010
^ why are you looking for trouble here and there?

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