Hello Ladies and gentlemen

It another math Brainstorm/challenge time

#600 credit is to giving out

Solve this simple questions only


1. An urn contains 4 white 6 black and 8 red balls . If 3 balls are drawn one by one without replacement, find the probability of getting all white balls.
A) 5/204
B) 1/204
C) 13/204
D) No answer

Solve get-- #200



2. 24x^2+25x−47/ax−2 =−8x−3−(53/ax--2)

is true for all values of x≠2/a

where a is a constant.
What is the value of a?

A) -16
B) -3
C) 3
D) 16

Solve get = #300


3. Given: log8(5) = b. Express log4(10) in terms of b.

Solve get= #100

Click here to get your card.---https://www.talkpalsforum.com/index.php?topic=34.0

1. The probability of drawing a white ball first = 4/18 = 2/9
When the first white ball is drawn, the total ball left is 17 while 3 of it is white.
The PR of the second drawn ball is 3/17
While the third drawn white is 2/16 =1/8 since the ball is not replaced.
Hence, the required probability = 2/9 x 3/17 x 1/8= 1/204 = B

Eyinjuoluwanimi:
Hello Ladies and gentlemen

It another math Brainstorm/challenge time

#600 credit is to giving out

Solve this simple questions only


1. An urn contains 4 white 6 black and 8 red balls . If 3 balls are drawn one by one without replacement, find the probability of getting all white balls.
A) 5/204
B) 1/204
C) 13/204
D) No answer

Solve get-- #200



2. 24x^2+25x−47/ax−2 =−8x−3−(53/ax--2)

is true for all values of x≠2/a

where a is a constant.
What is the value of a?

A) -16
B) -3
C) 3
D) 16

Solve get = #300


3. Given: log8(5) = b. Express log4(10) in terms of b.

Solve get= #100

Click here to get your card.---https://www.talkpalsforum.com/index.php?topic=34.0

No.2 Answer
multiply (−8x−3) and (ax−2) using FOIL.
24x2+25x−47=−8ax2−3ax+16x+6−53
Then, reduce on the right side of the equation
24x2+25x−47=−8ax2−3ax+16x−47
Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
so answer is -3

.

No.3 answer


log 5=b using the base change rule log 5= log 5/ log 8 log 8 can be solved: log 8=x 4 =8 2 =2 2x=3 x=3/2 Therefore we can write: log 5= log 5/(3/2)=b log 5=(3/2)b [1] To make log 5 into log 10 we can use the product rule: log 2+ log 5=log (2x5)= log 10 So by adding log 2 on both sides of equation [1] we can write log 2+ log 5= log 2+ ( 3/2)b log 10= log 2+ ( 3/2)b But log 2 can be solved: log 2=x 4 =2 2 =2 2x=1 x=1/2 Therefore we can conclude that log 10=1/2+ ( 3/2)b log 10=(1+3b)/2

..

Thanks everybody kudos to you guys

Eyinjuoluwanimi:
Thanks everybody kudos to you guys

my card !?

Eyinjuoluwanimi:
Hello Ladies and gentlemen

It another math Brainstorm/challenge time

#600 credit is to giving out

Solve this simple questions only


1. An urn contains 4 white 6 black and 8 red balls . If 3 balls are drawn one by one without replacement, find the probability of getting all white balls.
A) 5/204
B) 1/204
C) 13/204
D) No answer

Solve get-- #200



2. 24x^2+25x−47/ax−2 =−8x−3−(53/ax--2)

is true for all values of x≠2/a

where a is a constant.
What is the value of a?

A) -16
B) -3
C) 3
D) 16

Solve get = #300


3. Given: log8(5) = b. Express log4(10) in terms of b.

Solve get= #100

Click here to get your card.---https://www.talkpalsforum.com/index.php?topic=34.0

The last time i did something like this I was not rewarded..even when the op promised a reward
I dont know if I should try this

1) Let A, B, C be the events of getting a white ball in first, second and third draw respectively, then Required probability = PA∩B∩C = PA PBA PCA∩B Now, P(A) = Probability of drawing a white ball in first draw = 4/18 = 2/9 When a white ball is drawn in the first draw there are 17 balls left in the urn, out of which 3 are white ∴PBA=317 Since the ball drawn is not replaced, therefore after drawing a white ball in the second draw there are 16 balls left in the urn, out of which 2 are white. ∴PCA∩B =216=18 Hence the required probability = 29×317×18=1204...

1) 1/204 B

2) 24x2+ 25x − 47 divided by ax − 2 is equal to −8x −3 with remainder −53, it is true that (−8x − 3)(ax − 2) − 53 = 24x2 + 25x −47. (This can be seen by multiplying each side of the given equation by ax − 2). This can be rewritten as −8ax2+ 16x − 3ax = 24x2+ 25x − 47. Since the coefficients of the x2 -term have to be equal on both sides of the equation, −8a = 24, or a = −3. the answer is -3

l3) log 5=b using the base change rule log 5= log 5/ log 8 log 8 can be solved: log 8=x 4 =8 2 =2 2x=3 x=3/2 Therefore we can write: log 5= log 5/(3/2)=b log 5=(3/2)b [1] To make log 5 into log 10 we can use the product rule: log 2+ log 5=log (2x5)= log 10 So by adding log 2 on both sides of equation [1] we can write log 2+ log 5= log 2+ ( 3/2)b log 10= log 2+ ( 3/2)b But log 2 can be solved: log 2=x 4 =2 2 =2 2x=1 x=1/2 Therefore we can conclude that log 10=1/2+ ( 3/2)b log 10=(1+3b)/2

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Loris576:

The last time i did something like this I was not rewarded..even when the op promised a reward
I dont know if I should try this

if it coming from that link oo. You can only be rewarded if you post your answer there..

You can check to verified someone don't chop the reward