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2k For Anyone Who Can Solve This For Me....mathematicians Food Don Land / Test You IQ , 2k For 5 Winners Fastest Correct Answers Only / Can U Solve This Primary 6 Quantitative Reasoning (2) (3) (4)
Re: 2k For Whoever Can Solve This Asap by Folzye(m): 11:04pm On Aug 09, 2020 |
phenomental40: The correct Answer is 126°.. If you are that good, defend Y the answer could not have been 72° |
Re: 2k For Whoever Can Solve This Asap by Ogabson: 11:57pm On Aug 09, 2020 |
126. To get the answer you have to construct A and C to meet E at the other side of the circle. Apply Angle at a centre= 2 angle at the circumference Then opposite angle of a circle quadrilateral.
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Re: 2k For Whoever Can Solve This Asap by jumper524(m): 12:28am On Aug 10, 2020 |
360-282= 78 Baba I no too know maths but if say I see the options, I for fit guess am. |
Re: 2k For Whoever Can Solve This Asap by phenomental40(m): 4:38am On Aug 10, 2020 |
Ogabson:at least explain how how you got those angles |
Re: 2k For Whoever Can Solve This Asap by phenomental40(m): 4:39am On Aug 10, 2020 |
Folzye:defend a wrong answer! who can |
Re: 2k For Whoever Can Solve This Asap by Folzye(m): 5:26am On Aug 10, 2020 |
Re: 2k For Whoever Can Solve This Asap by femi4: 6:17am On Aug 10, 2020 |
Emary:you are right, you are still brilliant in this pandemic era |
Re: 2k For Whoever Can Solve This Asap by phenomental40(m): 6:41am On Aug 10, 2020 |
Folzye:sorry |
Re: 2k For Whoever Can Solve This Asap by Ogabson: 8:46am On Aug 10, 2020 |
phenomental40:Hope this helps
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Re: 2k For Whoever Can Solve This Asap by Ogabson: 8:47am On Aug 10, 2020 |
phenomental40:
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Re: 2k For Whoever Can Solve This Asap by Karleb(m): 9:04am On Aug 10, 2020 |
Malawian: |
Re: 2k For Whoever Can Solve This Asap by peppo4live: 6:32pm On Aug 10, 2020 |
phenomental40: Hello bros |
Re: 2k For Whoever Can Solve This Asap by peppo4live: 6:52am On Aug 11, 2020 |
phenomental40: Received with thanks. God bless you 1 Like
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Re: 2k For Whoever Can Solve This Asap by phenomental40(m): 7:24am On Aug 11, 2020 |
peppo4live:it nothing , your welcome. 1 Like |
Re: 2k For Whoever Can Solve This Asap by Nobody: 7:45am On Aug 11, 2020 |
peppo4live: This your answer resemble luck. The angle that is subtended, is it the exterior angles or the interior angles? |
Re: 2k For Whoever Can Solve This Asap by peppo4live: 8:41am On Aug 11, 2020 |
Squillaci: Study the theorems of cycle geometry very well. There is nothing like luck... If you manipulate steps in mathematics, people will know... Thanks |
Re: 2k For Whoever Can Solve This Asap by Nobody: 8:53am On Aug 11, 2020 |
peppo4live:I get it. 1 Like |
Re: 2k For Whoever Can Solve This Asap by peppo4live: 1:21pm On Aug 11, 2020 |
Ogabson: You have done well but you should try as much as possible to simplify mathematics and make it attractive for people. Let me use binary operation to fully explain your solution. Question: Find the product of 11 and 10 (Leaving your answer in base two) Solution: 1 1 × 1 0 ------------- 0 0 +1 1 ------------------ 1 1 0 ------------------- Instead of the above solution... This is what you did: You converted the base into base ten 11= 1×2^1 + 1×2^0 = 2 + 1 = 3 base 10 10 = 1×2^1 + 0×2^0 = 2 + 0 = 2 base 10 Therefore, 11 × 10 = 3 × 2 = 6 base 10 Converting base 10 to base 2 6 divided by 2 2 6 2 3 R 0 2 1 R 1 2 0 R 1 Answer 110 base two. I hope this help.... Thanks 1 Like |
Re: 2k For Whoever Can Solve This Asap by joepepsy(m): 11:56pm On Aug 13, 2020 |
Did you sent me an email. Squillaci: |
Re: 2k For Whoever Can Solve This Asap by davooomat(m): 12:34am On Aug 14, 2020 |
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Re: 2k For Whoever Can Solve This Asap by dejt4u(m): 8:22am On Aug 15, 2020 |
Honestly, you don't need pen and paper to solve this question. |
Re: 2k For Whoever Can Solve This Asap by Harbidexy5(m): 2:36pm On Aug 15, 2020 |
I tell you... |
Re: 2k For Whoever Can Solve This Asap by CodeTemplar: 6:29pm On Aug 15, 2020 |
MrShape, I don't have the answer yet but know that AOC is 108°. Still on it.... |
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