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Snepco Past Questions - Education (3) - Nairaland

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Nnpc/snepco Past Questions / Nnpc/snepco Past Questions / NNPC/SNEPCO Scholarship Past Questions 2000 - 2019 PDF (2) (3) (4)

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Re: Snepco Past Questions by ivumar: 1:31pm On Oct 14
NisforNicky:


Pls help with this.......


I need the workings
Question about the athlete not clear. Pls resend
Re: Snepco Past Questions by NisforNicky: 1:36pm On Oct 14
ivumar:


The question on angle of elevation is, I think incorrect. Or what do you guys think... because I don't get how angle of elevation can be greater than 90 degrees.


thank you.

angles are meant to be in degrees not metres
Re: Snepco Past Questions by NisforNicky: 1:50pm On Oct 14
femi4:
None of the options
Group with 12 teachers is rank 11
Percentile = 100R/N = 1100/12 = 92
how did you rank the group pls?
Re: Snepco Past Questions by NisforNicky: 1:51pm On Oct 14
ivumar:

Question about the athlete not clear. Pls resend

alright

Nairaland's algorithm overcompressed the already faulty pic
Re: Snepco Past Questions by mete3: 2:39pm On Oct 14
Hey Boss. Pls check ur mail
ivumar:
Question about the athlete not clear. Pls resend
Re: Snepco Past Questions by ivumar: 2:54pm On Oct 14
mete3:
Hey Boss.
Pls check ur mail


Replied bro
Re: Snepco Past Questions by SPLENDID25(m): 3:40pm On Oct 14
NisforNicky:

More
the percentile placement for the group with 12 teachers is 20%
Re: Snepco Past Questions by SPLENDID25(m): 3:40pm On Oct 14
NisforNicky:

More
the percentile placement for the group with 12 teachers is 20%
Re: Snepco Past Questions by NisforNicky: 3:49pm On Oct 14
SPLENDID25:
the percentile placement for the group with 12 teachers is 20%

no no pls

this is not correct

P = 100 x n/N

= 100 x 11/12


= ~92%
Re: Snepco Past Questions by SPLENDID25(m): 3:56pm On Oct 14
NisforNicky:

no no pls
this is not correct
P = 100 x n/N
= 100 x 11/12 = 92.11%
my bad! misunderstood the question
Re: Snepco Past Questions by SPLENDID25(m): 3:58pm On Oct 14
NisforNicky:

no no pls
this is not correct
P = 100 x n/N
= 100 x 11/12 = 92.11%
my bad! misunderstood the question
Re: Snepco Past Questions by NisforNicky: 4:11pm On Oct 14
SPLENDID25:
my bad! misunderstood the question

pls can you find the interquartile range

cc ivumar femi4
Re: Snepco Past Questions by NisforNicky: 4:35pm On Oct 14
in one month, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107


cc ivumar

1 Like

Re: Snepco Past Questions by ivumar: 4:48pm On Oct 14
NisforNicky:
in one month, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107


cc ivumar

Please check again. What is in the option for (D). Is it really 107?
Re: Snepco Past Questions by NisforNicky: 4:51pm On Oct 14
ivumar:

Please check again. What is in the option for (D). Is it really 107?
looks like 112 or 107
pic not clear at all on dat part
Re: Snepco Past Questions by Tobilyn77: 5:02pm On Oct 14
NisforNicky:
in one month, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107



cc ivumar
The answer should be A
Re: Snepco Past Questions by ivumar: 5:06pm On Oct 14
Tobilyn77:

The answer should be A
Reasons being?
Re: Snepco Past Questions by ivumar: 5:10pm On Oct 14
NisforNicky:


looks like 112 or 107

pic not clear at all on dat part
I got 152, so I was confused.
Had to download the image and zoom... and it actually looked like 152.

2 Likes

Re: Snepco Past Questions by NisforNicky: 5:12pm On Oct 14
ivumar:
I got 152, so I was confused. Had to download the image and zoom... and it actually looked like 152.
you are correct
I enhanced d image and the middle one looked like 5 or 8

pls show workings
Re: Snepco Past Questions by NisforNicky: 5:12pm On Oct 14
Tobilyn77:
The answer should be A
show workings pls
Re: Snepco Past Questions by ivumar: 5:22pm On Oct 14
NisforNicky:
in one week, an athlete trained by running from 2:30AM to 4:00am for 6days and from 2:00PM to 4.30pm for 4 days. If his average spd was 8km/h, how many km did the athlete run that week?

A. 200
B. 160
C. 170
D. 107


cc ivumar

2:30AM - 4:00AM is 1.5 hrs. The athlete did this particular set of run for 6 days, i.e, In that week, he ran 6 x 1.5 hrs = 9 hrs in the morning.

2:00PM - 4.30pm is 2.5 hrs. The athlete did this particular set of run for 4 days, i.e, In that week, he ran 4 x 2.5 hrs = 10 hrs in the evening

Therefore, the total number of hrs the athlete ran that week is 9 + 10 = 19 hrs.
According to the question, average speed is 8km/hr

Now, the question is asking for the total distance traveled in that week in kilometres. So lets solve
Distance = speed x time
therefore, Distance = 8 x 19 = 152km

1 Like

Re: Snepco Past Questions by Tobilyn77: 5:25pm On Oct 14
[quote author=NisforNicky post=94939564]

Sorry. I mixed it up
Re: Snepco Past Questions by NisforNicky: 5:26pm On Oct 14
Tobilyn77:
the athlete ran for 1 hours 30 minutes for 6 days in the morning.
Total hours ran. (6*1.5hours) = 9 hours .
In the evenings. He ran for (1hour 30mins For 4 days.( 4*1.5) = 6 hours.
(9+6) = 15 hours total.
Speed = distance/time.
8km/hr = x/15
X= 15*8
X= 120km.

im confused walahi

oga how does this translate to A. 200 now



modified: oh, i see where the mistake is

the second one should be 2hrs 30mins not 1hr 30mins

good attempt bro
tobilyn77
Re: Snepco Past Questions by NisforNicky: 5:33pm On Oct 14
ivumar:


2:30AM - 4:00AM is 1.5 hrs. The athlete did this particular set of run for 6 days, i.e, In that week, he ran 6 x 1.5 hrs = 9 hrs in the morning.

2:00PM - 4.30pm is 2.5 hrs. The athlete did this particular set of run for 4 days, i.e, In that week, he ran 4 x 2.5 hrs = 10 hrs in the evening

Therefore, the total number of hrs the athlete ran that week is 9 + 10 = 19 hrs.
According to the question, average speed is 8km/hr

Now, the question is asking for the total distance traveled in that week in kilometres. So lets solve
Distance = speed x time
therefore, Distance = 8 x 19 = 152km




ivumar thanx so much

Pls I still need help with the interpercentile sumtin

Don't know what you do in ur personal lyf but u can comfortably take math tutoring gigs

lolz I dn type ur name too much sotey my keyboard don save am dey suggest am up-and-down

grin

1 Like

Re: Snepco Past Questions by SPLENDID25(m): 5:44pm On Oct 14
NisforNicky:

pls can you find the interquartile range
cc ivumar femi4
2
Re: Snepco Past Questions by NisforNicky: 5:45pm On Oct 14
SPLENDID25:
2
I got 7
pls show workings
Re: Snepco Past Questions by NisforNicky: 5:48pm On Oct 14
Tobilyn77:

it's cool

pls help solve more
Re: Snepco Past Questions by ennydammy11(m): 6:00pm On Oct 14
NisforNicky:


no no pls

this is not correct

P = 100 x n/N

= 100 x 11/12


= ~92%

Please, how did u get 11?
Re: Snepco Past Questions by NisforNicky: 6:05pm On Oct 14
ennydammy11:


Please, how did u get 11?

list all the data in order from smallest to largest

then look for where 12 is on the row (11th term in this case)

that is the rank/p0sition (n) of 12.

the big N is the total no. of terms

1 Like

Re: Snepco Past Questions by SPLENDID25(m): 6:06pm On Oct 14
NisforNicky:


I got 7

pls show workings
i used this to calculate mean, and median.

2 Likes

Re: Snepco Past Questions by ivumar: 7:46pm On Oct 14
NisforNicky:


ivumar thanx so much

Pls I still need help with the interpercentile sumtin

Don't know what you do in ur personal lyf but u can comfortably take math tutoring gigs

lolz I dn type ur name too much sotey my keyboard don save am dey suggest am up-and-down

grin

Lolzzz... Thanks bro

As regarding the questions on percentile, median, inter-quartile and their likes,,,,, I think the table given is not representing the right information.
Check up SPLENDID25's last message. I think he put forth a reasonable assumption as regarding the table.
The 2nd row should represent the frequency of the values given in the 1st row.. I'm sure(not 100%) it was a mistake from them.

1 Like

Re: Snepco Past Questions by ivumar: 7:49pm On Oct 14
SPLENDID25:
i used this to calculate mean, and median.
Nice...
You assumed the lower row to be that of frequency, right?

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