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## Snepco Past Questions - Education (4) - Nairaland

 Re: Snepco Past Questions by SPLENDID25(m): 9:06pm On Oct 14 ivumar: Nice... You assumed the lower row to be that of frequency, right?yes Sir 1 Like Re: Snepco Past Questions by femi4: 9:31pm On Oct 14 NisforNicky:pls can you find the interquartile rangecc ivumar femi4That table has issue. Not showing frequency row 1 Like Re: Snepco Past Questions by NisforNicky: 12:16am On Oct 15 VerbalCc jpawjpaw thankGod001 Re: Snepco Past Questions by NisforNicky: 12:19am On Oct 15 Morree Re: Snepco Past Questions by jpawjpaw(m): 12:19am On Oct 15 NisforNicky:cc femi4 now, this one below is from the recently concluded SPDC mete3 a man and a woman can do a work for 4 days. x + y = 4 (man = x and woman = y) while the woman alone can do the work for 6 days. y = 6. how long will it take the man to do the work? if x+y = 4 when y = 6 x + 6 = 4 x = 4-6 x = -2 by ignoring the sign, x = 2// so it will take the man 2days to do the work. abeg I stand to be corrected. the question carry weight 1 Like Re: Snepco Past Questions by NisforNicky: 12:21am On Oct 15 good night peopleall the rest are not clear at allgood luck everyone Re: Snepco Past Questions by NisforNicky: 12:22am On Oct 15 jpawjpaw: a man and a woman can do a work for days. x + y = 4 (man = x and woman = y) while the woman alone can do the work for 6 days. y = 6. how long will it take the man to do the work? if x+y = 4 when y = 6 x + 6 = 4 x = 4-6 x = -2 by ignoring the sign, x = 2// so it will take the man 2days to do the work. abeg I stand to be corrected. the question carry weight hmmmm........this is what I did tooivumar femi4 pls confirm Re: Snepco Past Questions by NisforNicky: 12:25am On Oct 15 jpawjpaw: a man and a woman can do a work for days. x + y = 4 (man = x and woman = y) while the woman alone can do the work for 6 days. y = 6. how long will it take the man to do the work? if x+y = 4 when y = 6 x + 6 = 4 x = 4-6 x = -2 by ignoring the sign, x = 2// so it will take the man 2days to do the work. abeg I stand to be corrected. the question carry weight I thinkno need to ignore the sign- shows the man will finish the job 2 days less than the 4 days when they did it together Re: Snepco Past Questions by Xandre: 1:29am On Oct 15 jpawjpaw: a man and a woman can do a work for 4 days. x + y = 4 (man = x and woman = y) while the woman alone can do the work for 6 days. y = 6. how long will it take the man to do the work? if x+y = 4 when y = 6 x + 6 = 4 x = 4-6 x = -2 by ignoring the sign, x = 2// so it will take the man 2days to do the work. abeg I stand to be corrected. the question carry weight Both of them can do it for 4Days, how then can only the man do it for 2Days?It's 12Days Sha...but not in the options 1 Like Re: Snepco Past Questions by femi4: 5:12am On Oct 15 NisforNicky:hmmmm........this is what I did tooivumar femi4 pls confirmCan't you see that laugh emoji at the end of his solutions. As you can see, some of the question were either incorrect or answer missing from the optionsBesides, you can't finish a job working alone in lesser days than the no of days both of them will use to complete same job. 2 Likes Re: Snepco Past Questions by ThankGod001(m): 6:06am On Oct 15 niceNisforNicky:FinallyCc thankGod001 Re: Snepco Past Questions by ThankGod001(m): 6:08am On Oct 15 SPDC when was that?NisforNicky:cc femi4now, this one below is from the recently concluded SPDCmete3 Re: Snepco Past Questions by ivumar: 6:46am On Oct 15 femi4:Can't you see that laugh emoji at the end of his solutions. As you can see, some of the question were either incorrect or answer missing from the optionsBesides, you can't finish a job working alone in lesser days than the no of days both of them will use to complete same job. Can't you see that laugh emoji at the end of his solutions.Lolll 1 Like Re: Snepco Past Questions by ivumar: 6:48am On Oct 15 SPLENDID25:yes SirAlright Boss Re: Snepco Past Questions by ivumar: 6:49am On Oct 15 NisforNicky:hmmmm........this is what I did tooivumar femi4 pls confirmWrong Sir Re: Snepco Past Questions by NisforNicky: 7:56am On Oct 15 ivumar:Wrong Siralrightpls A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?A. 40 daysB. 23 daysC. 37 ½ daysD. 37 dayscc femi4 Re: Snepco Past Questions by NisforNicky: 7:59am On Oct 15 femi4:Can't you see that laugh emoji at the end of his solutions. As you can see, some of the question were either incorrect or answer missing from the optionsBesides, you can't finish a job working alone in lesser days than the no of days both of them will use to complete same job. A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in A.18 daysB.6 daysC. 4 daysD. 8 dayscc ivumarI got 8 Re: Snepco Past Questions by femi4: 8:50am On Oct 15 NisforNicky:alrightpls A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?A. 40 daysB. 23 daysC. 37 ½ daysD. 37 dayscc femi4A does 80% of job in 20 Days. Hence, 100% of job in (100/80) x 20 = 25 DaysA alone can complete the job in one day (1/25) portionA and B do 20% of job in 3 Days. Hence, 100% of job in (100/20) x 3 = 15 DaysA and B can complete the job in one day (1/15) portionB alone can complete the job in one day[(1/15) - (1/25)] = [(5- 3 )/75] = [2/75] portionB alone can complete the job = (75/2) = 37.5 Days 5 Likes Re: Snepco Past Questions by femi4: 9:02am On Oct 15 NisforNicky:A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in A.18 daysB.6 daysC. 4 daysD. 8 dayscc ivumarI got 84days2A = BHence, A = 12/2 = 6daysWorking together 1/6 + 1/12 = 1/4 of the job/dayHence, the job will be completed in 4days by A and B working together 3 Likes Re: Snepco Past Questions by ivumar: 9:34am On Oct 15 femi has given solutions. Hope you understood? 2 Likes Re: Snepco Past Questions by NisforNicky: 10:04am On Oct 15 femi4:A does 80% of job in 20 Days. Hence, 100% of job in (100/80) x 20 = 25 DaysA alone can complete the job in one day (1/25) portionA and B do 20% of job in 3 Days. Hence, 100% of job in (100/20) x 3 = 15 DaysA and B can complete the job in one day (1/15) portionB alone can complete the job in one day[(1/15) - (1/25)] = [(5- 3 )/75] = [2/75] portionB alone can complete the job = (75/2) = 37.5 Daysthanks femiI gt confused by the 80% Re: Snepco Past Questions by NisforNicky: 10:05am On Oct 15 femi4:4days 2A = B Hence, A = 12/2 = 6days Working together 1/6 + 1/12 = 1/4 of the job/day Hence, the job will be completed in 4days by A and B working together ohhhhh my mistake was doing A=2B thanks again femi4 and ivumar Re: Snepco Past Questions by NisforNicky: 10:36am On Oct 15 femi4:A does 80% of job in 20 Days. Hence, 100% of job in (100/80) x 20 = 25 DaysA alone can complete the job in one day (1/25) portionA and B do 20% of job in 3 Days. Hence, 100% of job in (100/20) x 3 = 15 DaysA and B can complete the job in one day (1/15) portionB alone can complete the job in one day[(1/15) - (1/25)] = [(5- 3 )/75] = [2/75] portionB alone can complete the job = (75/2) = 37.5 Days1. A alone can do a piece of work in 10 days and B alone can do it in 15 days. In how many days will A and B together do the same work?(a) 5(b) 6(c) 8(d) 92. It takes 6 men 10 days to paint 2 rooms. How long will it take 4 men to paint 6 rooms?A. 42B. 45C. 62D. None of the optionscc ivumar femi4 Re: Snepco Past Questions by Xandre: 11:22am On Oct 15 NisforNicky:1. A alone can do a piece of work in 10 days and B alone can do it in 15 days. In how many days will A and B together do the same work?(a) 5(b) 6(c) 8(d) 92. It takes 6 men 10 days to paint 2 rooms. How long will it take 4 men to paint 6 rooms?A. 42B. 45C. 62D. None of the optionscc ivum ar fe mi4BB Yes to your question on Jim Ovia 1 Like Re: Snepco Past Questions by femi4: 12:02pm On Oct 15 NisforNicky:1. A alone can do a piece of work in 10 days and B alone can do it in 15 days. In how many days will A and B together do the same work?(a) 5(b) 6(c) 8(d) 92. It takes 6 men 10 days to paint 2 rooms. How long will it take 4 men to paint 6 rooms?A. 42B. 45C. 62D. None of the optionscc ivumar femi41. 1/15 + 1/10 = 25/150= 1/6 of the job/dayHence, working together will take them 6days to complete the job2. 4men will paint 2 rooms in 6*10/4 = 15daysHence, painting of 6 rooms by 4 men = 15*3 =45days 2 Likes Re: Snepco Past Questions by NisforNicky: 1:58pm On Oct 15 femi4:1. 1/15 + 1/10 = 25/150 = 1/6 of the job/day Hence, working together will take them 6days to complete the job 2. 4men will paint 2 rooms in 6*10/4 = 15days Hence, painting of 6 rooms by 4 men = 15*3 =45days thanks a lot Re: Snepco Past Questions by NisforNicky: 1:59pm On Oct 15 Xandre:BB Yes to your question on Jim Ovia wow since when? Re: Snepco Past Questions by NisforNicky: 2:17pm On Oct 15 femi4:1. 1/15 + 1/10 = 25/150= 1/6 of the job/dayHence, working together will take them 6days to complete the job2. 4men will paint 2 rooms in 6*10/4 = 15daysHence, painting of 6 rooms by 4 men = 15*3 =45days7. Smith and Thomas can do a piece of work in 72 days; Thomas and Clark can do it in 120 days; Smith and Clark can do it in 90 days. In what time can Smith, Thomas and Clark do it, working together?(a) 60 days(b) 66 days(c) 75 days(d) 80 daysI got A. 60 Re: Snepco Past Questions by NisforNicky: 2:32pm On Oct 15 ThankGod001:SPDC when was that? last month, I think Re: Snepco Past Questions by NisforNicky: 3:11pm On Oct 15 no calculators allowed i jxt confirmed dis from the SNEPCO lady Re: Snepco Past Questions by Iamcyborg(f): 4:16pm On Oct 15 NisforNicky:pls can u show full workings7. Smith and Thomas can do a piece of work in 72 days; Thomas and Clark can do it in 120 days; Smith and Clark can do it in 90 days. In what time can Smith, Thomas and Clark do it, working together?(a) 60 days(b) 66 days(c) 75 days(d) 80 daysI got A. 60 Re: Snepco Past Questions by Tobilyn77: 4:17pm On Oct 15 NisforNicky:7. Smith and Thomas can do a piece of work in 72 days; Thomas and Clark can do it in 120 days; Smith and Clark can do it in 90 days. In what time can Smith, Thomas and Clark do it, working together?(a) 60 days(b) 66 days(c) 75 days(d) 80 daysI got A. 60 workings please

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