Please Help Solve This Chemistry Question - Education - Nairaland
Nairaland Forum / Nairaland / General / Education / Please Help Solve This Chemistry Question (89 Views)
Please Who Can Answer This Chemistry Question? / Help Solve This Chemistry Question / I Need Someone To Solve This Chemistry Question For Me (2) (3) (4)
(1) (Reply)
| Please Help Solve This Chemistry Question by banky200: 7:27am On May 14 |
. If 50cm3 of a saturated solution of potassium chloride at 30oC yielded 18.62g of dry salt, calculate the solubility of the salt in mol/dm3 at 30oC |
| Re: Please Help Solve This Chemistry Question by CodeTemplar: 8:05am On May 14 |
18.62 X mols in a gram. Incomplete question. A constant is missing. |
| Re: Please Help Solve This Chemistry Question by Light78: 8:25am On May 14 |
5 mol/dm3 Potassium Chloride = KCL Solubility ( mol/dm3) = mass of solute (g) / molar mass ÷ volume of solvent.......equ 1 Remember Mole = Mass/Molar mass Molar mass of KCL = K is 39.10g/mol, and CL is 35.45g/mol. Adding them together, = 74.55 which is the molar mass of KCL. Mass of dry salt is 18.62g Mole of KCL = mass of dry salt/ molar mass of KCL = 18.62/74.55 = 0.249 mol We go back to equ 1 Solubility = Mole/ volume of solvent. Remember, the volume of solvent is given in Cm3, it should be converted to dm3; 50/1000 = 0.05 dm3 From equ 1 Solubility= mole of KCL/ volume of solvent in dm3 = 0.249/0.05 = 5 mol/dm3 Hence, the solubility of KCL in Mol/dm3 at 30°C is 5 mol/dm3
|
(1) (Reply)
How To Increase The Profit You Make From Your School Business / Be Mindful Of Fake News Which Content Creators Leverage For Gain, Popularity / Why HVDC Is Not Prefer In Modern World?
(Go Up)
| Sections: politics (1) business autos (1) jobs (1) career education (1) romance computers phones travel sports fashion health religion celebs tv-movies music-radio literature webmasters programming techmarket Links: (1) (2) (3) (4) (5) (6) (7) (8) (9) (10) Nairaland - Copyright © 2005 - 2024 Oluwaseun Osewa. All rights reserved. See How To Advertise. 15 |