Geofavor:
nice course

Thank u Geofavour

teeblinkz001:



Maths, English, chemistry and physics

Thank you so much

Pls what's the UTME subject combination for applied geophysics that's acceptable in any University in Nigeria?

Pls... Help me I'm still waiting for your kind response ..

Pls if you are in the business already.... Pls kindly share your experience with us. Thank you very much

Please I need an advice for a friend of mine... It's kinda urgent....
My friend is writing a business plan for cosmetics business.. (a small scale business... as in a retail shop in the neighborhood.) and she don't know much about the business.... But she loves cosmetics a lot. How can she learn the business...?
And where can she buy from in wholesales between Aba and Onitsha in cheap prices...?
Also in terms of make up products. . Which brand is more demanding in Nigeria?

Pls kindly help with any information you know will benefits her.. . Thank you

Pls guys help me to solve this...

Find the number of ways the digits 0, 1, 2 and 3 can be permuted to give a rise to a number greater than 2000.


Merci beaucoup et bonne année en avance

@mathfaro n other maths expert in d house help me solve dis...am not sure of My answers...
.
.
1. Find the distance between the point (4, 3) and the point common to the lines 2x - y = 4 and x + y = 2.

.

2. A(5, 3) and B(2, -1) are two vertices of a square ABCD and D is on the x-axis. Find the coordinates of C and D.

.

3. A point P moves so that it is equidistant from points L(-2, 2) and M(5, 1).
a. Find the locus of P
b. Show that the locus of P is a perpendicular bisector of the line LM.

.

4. The vertices of a parallelogram PQRS are P(a, 7), Q(7, 5), R(0, 4) and S(6, 2). Calculate
a. the gradient of PQ
b. the value of a
c. the gradient of SR


Thank you

mathefaro:
I'm not sure you guys are prepping for UTME with the kind of questions you're throwing in especially the mathematics. If you feel like flexing muscles with strong questions, you can move over to the nairaland maths clinic. Most of these questions you guys are posting are beyond the scope of UTME.

Thank God, u observed it too.
@Ben should do something about dis. thank u

Segipaul:
Resultant should be 50N

Kindly show how u got it....

what volume of Carbon(II)Oxide is produced by reacting excess carbon with 10dm cube of oxygen?

@Mathefaro...n other maths expert in d house...
Help me solve this:

1. The first term of an AP is 3 and the eleventh term is 18. Find the number of terms in the progression if the sum is 81.



thank u

Benjaminbest:
no doubt d second question u got it ryt but d first is wrong

@Benjamin
let's know where he got it wrong....
we are here to learn

1. A car travelling at 50m/s from rest covers a distance of 10km in 40min. Calculate the acceleration.

mathefaro:
First and foremost, convert the average velocity to m/s by multiplying by 5/18
==> v = 54 * 5/18 = 15m/s;
Then recall that distance = average velocity * time taken i.e. S = vt
S = ?; v = 15m/s; t = 10s
Therefore, S = 15 * 10 = 150m


Since the car started from rest, initial velocity, u = 0, v = 30m/s; t = 6a; a = v/t = 30/6 = 5m/s²; S = ?
So with the available parameters, S, u, a and t, the appropriate equation to use is S = ut + (1/2)*at²;
Therefore, S = 0(6) + 0.5*5*36
S = 0+ 90
S = 90m


V - U = 5m/s; t = 30s; U = 20m/s;
a = (V - U)/t = 5/30 = 1/6m/s²
S =ut + ½at²
S = 20(30) + ½*1/6*30*30
==> S =600 + 75
==> S = 675m

u = 50m/s; v = 0; t = ?, g = 10m/s²
=> V = u - gt (minus because the body is going up against gravity)
=> 0 = 50 - 10t
=> 10t = 50
=> t = 5s

Good morning lovely people

Wao...u re gud
thank u

@chim and other physics expert in d house..
Help me in dis, I need to know if I got it right.thank u.

1. The average velocity of a car is 54km/h. what is the distance covered if the time taken is 10s?

2. A car starts from rest and travels at uniform acceleration until it attains a velocity of 30m/s after 6s. The distance covered is?

3. A man increased his speed by 5m/s after 30s, if his initial velocity was 20m/s. The average distance covered if his speed was at uniform acceleration would be?

4. A ball is thrown vertically upwards from the ground with an initial velocity of 50m/s. What is the total time spent by the ball in the air (g=100m/s.sq)

thank you

chimhigher:

No 2...d magnitude wuld b Mgsin@ = 30*10*sin30=300sin30= 150N

Thnk u

chimhigher:
Ok..4 number 1...Frictional force(F)=coefficient f reaction(U) X normal Reaction(R)...so making coefficient of friction d subject of formulae it becomes U=F/R.... Recall F= sin@ while R=cos@...so U=sin@/cos@= tan@..so d coefficient of friction is tan@=tan60= √3 so no 1 ansa is √3

Thnk u

mathefaro:
To convert the binary number(110011.1001) to hex is easy just break it into groups of four numbers, 0011 0011 . 1001 (note that I added extra two 0s to the left to make it balanced) now with it broken into segments of four use the conversion for binary, so using the table below you get your Hex number 33.9

Hex Binary
0 = 0000
1 = 0001
2 = 0010
3 = 0011
4 = 0100
5 = 0101
6 = 0110
7 = 0111
8 = 1000
9 = 1001
A = 1010
B = 1011
C = 1100
D = 1101
E = 1110
F = 1111

Now for octal,all you do is break it down into groups of three, your number(110011.1001) broken down would look like this 110 011 . 100 100 (note that I added extra two 0s to the right side to make it balance) then all you do is convert to octal using the table below. which you get 63.44 in octal.

Octal Binary
0 000
1 001
2 010
3 011
4 100
5 101
6 110
7 111

hope that helps.

thank u very much

pls kindly help me in this...@mathefaro n other maths expert in d house...

Express 110011.1001 base 2 to
1. Octal
2. Hexadecimal
3. Base 4


I got the whole number side...but find it hard to get the fractional parts...after converting it to base 10, can't convert d fractional parts to the bases above..

Thank you very much

apexviper:
plzz bro ,m hearing sum tins dat maths iz nau compulsory even 4 medical students in jamb.Au true iz diz?

its not true.....ur subject combination should be Eng, phy, chem and bio...if u re applying for Medicine

Benjaminbest:
guys before i go update....make una tell me d differences between moving coil galvanometer and hot iron ammeter. Guys before u una resonate with my question make una wave for mind so dat u guys will b frequent with maximum velocity. Jst before i accelerate to d next level make my weight no become scalar

Moving coil Galvanometer is an instrument that is used for the DETECTION of electric currents through electric circuit..

and

Hot Iron Ammeter is an instrument used to MEASURE the flow of electric current in a circuit.

Capableben:

yes 100 level chemical engr but because of the sluggish nature of my schools academic calendar, and some confidential reasons I wanna write jamb and apply to a faster school....

Which school is that? sorry to ask..n which school do u Av in mind nw?

Capableben:

which course are u applying for?

Elect Elect
Are u a student?

1. A rough wooden block on a rough plank is drawn along the plane of the plank when inclined at 60 degree to the horizontal. Determine the coefficient of friction between two surfaces.

2. If a force of 50N moves a load of 30kg up an inclined plane. Determine the magnitude of the force if the plane is inclined at an angle of 30 degree.


Thank you

Benjaminbest:
[color=#006600][/color] chemistry update come up ........... Physics update comes up later in d day

I think its time for physics update...or isn't it?

mathefaro:
like I said in the other thread, bearing is bearing irrespective of where you've seen it

thank u

mathefaro:
my sister, bearing is bearing, whether physics or math. It's obvious that the 5km there is not needed, it's just a distraction

got it
thank u

mathefaro:
It's a mathematics question
If the bearing B from A is 030, then the bearing of A from B is 210^o or S30^oW.

thank u @mathefaro
ok...but I found d question via physics textbook

beatsbyj2g:
I was talking abt both coz have not written yet apart from GCE (awaiting result). Did u offer/ write f/math in ur waec some people say its important.

Yes...its was very gud
I hope u studied it...cus u really have to work hard..for d exams....
But u can still used maths

beatsbyj2g:
d answer is. =210°
Solution;
Bearing of b from a = 30° (falling on d 3red cordrant )
Therefore 90-30=60° (angles in a right angled triangle )
Hence 90-60=30°
Then 30+180=210°

Its physics question not maths...
ok...its still complicated...
what about the 5km?