benbuks:

could also be done thus ,

$[√(tanx) /(sinx.cosx) ] dx

take product & ratio with sec^2 x

=> $√(tanx).sec^2 x /tanx dx

=> $sec^2 x /√tanx dx ..........( de-rationalize )

not put tanx = ben

=sec^2 xdx = dben

=>$dben/√ben

= 2√ben + k

hence we have

2√tanx + k

that's it

kk thanks, I actually used u = rut(tanx) instead of u = tan x. do it made things complicated

efficiencie:

∫(sec^2(x)/√tanx) dx
= 2√tanx + c

boss, please I'm having problems getting this, do you mind breaking that part down?

Wizzycliff: congrat! Fasodecapo, You have won 250mb data bundle with 30days validity. Drop ur mtn phone and get ur data.

oh sorry, I saw this late, I've been offline for some days. this is the mtn number: 07038308437

masperano: A girls present age is the age her brother will be when she will be twice the age he was when her age was half the sum of their present ages. How old are they presently

Aaaargh! small but mighty. lemme see if I can get a way around it.

oh boy! I'll need to go and apply for mathematics o. It's quite painful that I can't solve most of the questions here even as i love maths. Chai! DiarisGod o!

jackpot: now, from your bolded comment, if Lim_{x ->0}e^x = Lim_x->0cos x = 1, so can we say e^x= cos x?

I don't think so, since we can't say cos x is a function of e^x.

Germany and Brazil

I've got mixed feelings for the data loss cos of some vital points lost her and the fact that we might need to organise another math quiz

[quote
author=mathefaro]Guys please I need help on getting back my Jiayu
g2(dual core 1gb RAM) to work. The problem us that the phone came with
ICS 4.0.3 and I asked a guy to help me upgrade it to jellybean since I
heard that it's possible. But after the upgrade, I realized that the
phone is no longer normal ( can't switch on WiFi/ Bluetooth, can't' use
the camera and serious lagging while trying to scroll down or across
pages), and the real problem now is that I can't get a hold of the guy
to help me revert the upgrade to the normal OS. Somebody please come to
my rescue, I've not even used the phone for a day. my contact:
phone& whatsapp: 08103986669, email: sfarominiyi@yahoo.com or
mathefaro@gmail.com. thanks in advance[/quote]

mathefaro: A day old jiayu g2 for sale at a very cheap price, check out its specs below:

Basic Information
Model Dual Core Edition JIAYU G2
Band 2G: GSM 850/900/1800/1900MHz
3G: WCDMA 850/2100MHz
Sim Card Dual Sim Card Dual Standby
Service Provide Unlocked
Style Bar
Color Black
Shell Material Plastic
System
OS Android 4.0.3
CPU MTK6577, 1.0GHz
ROM 4GB
RAM 1GB
Screen
Display Size 4.0 Inch
Type IPS, capacitive touch screen
Resolution 800 x 480 pixels
Screen Color 16000K Colors
Support Format
Ringtones Type Polyphonic/MP3
Audio File Format MP3/WAV/AMR/AWB
Video File Format 3GP/MPEG4
Image File Format JPEG/BMP/GIF/PNG/GIF
E-book Format TXT/CHM/DOC/HTML
FM Radio Yes, earphone needed
Earphone Port 3.5mm
Card Extend Support TF card up to 32GB
extended
Data Transfer & Connectivity
Data transfer USB/Bluetooth
Mobile internet WAP/WIFI
General
Camera/Picture Resolution Dual Cameras, front
camera: 0.3MP, back camera: 8.0MP
with flashlight and auto focus
Support video record@720P
Phonebook 500
Message SMS/MMS
Input Handwrite/Keypad
TV No
GPS Yes, built in, support A-GPS and voice
navigation
With EPO assistance to speed up postioning
JAVA No
WIFI Yes, 802.11 b/g
Bluetooth Bluetooth 2.0
Gravity Sensor Yes
Multi-Touch Yes, 5 point touch
Dimensions 124 × 63 × 10.6mm
Net Weight(Including battery) 139g
Standby Time About 2~3 days
Other Feature 3G, GPS,WIFI, Play Store,
Bluetooth,FM radio, Ebook, Email,
Messaging, VPN Services, Google search, Gmail,
wallpapers,
calendar, calculator, clock, tethering & portable
hotspot,
camera, etc
Accessories
1 x Battery(2050mAh )

interested persons should contact me on whatsapp: 08103986669 or 2go: mathefaro
reason for sale: urgent need of money. Lagos and ogun only. 23k negotiable

bros let me give you 18k

If you know you have nothing to cobtribute, or u dont have a store where one can get the aforementioned phones, why dont you just ignore the thread and move to the next one. Is it a must that you make comment on every thread? For the fact it made front page doesnt mean it must have somwthing to do with you. peace!

washingtonklef: the kings... No 6 otigba street [b][/b]

thanks, I'll check there today

Guys please na

anyone please? or UK used Samsung galaxy phones

Where in computer village can I get any of these
Android phones?
w450 smartphone
thl w100
jiayu g2s or g3.
(or any other related Chinese droids)
or UK used Samsung S II / S III mini
Please it's very urgent, if you know of any store
where I can get them between now and weekend,
don't hesitate to signify.

Where in computer village can I get any of these
Android phones?
w450 smartphone
thl w100
jiayu g2s or g3.
(or any other related Chinese droids)
or UK used Samsung S II / S III mini
if you know of any store
where I can get them in ikeja
don't hesitate to signify.

What's the last price for your Samsung s2? and do you have Samsung sIII mini

Where in computer village can I get any of these Android phones?
w450 smartphone
thl w100
jiayu g2s or g3.
(or any other related Chinese droids)
Please it's very urgent, if you know of any store where I can get them between now and weekend, don't hesitate to signify.

Please is there anybody close to sango area or in lagos that can give me live guidiance and instructions on how to upgrade my jiayu g2h which curently runs on 4.0 to the official jb 4.1.2? Or better stil help me get it done.

Please guys, i need a guide on how to upgrade my jiayu g2 from 4.0 to jb 4.1.2. I'll appreciate it if anyone staying in lagos around ijaye or sango can even help me out with it

Please, how can i upgrade the os of my jiayu g2h from 4.0 to jb 4.1.2?

I got mine today at boostert communications in 8a otigba street, opposite microstation for just 13,500. Mehn the phone is cool. I immediately changed the memory card to 16gb. And when i asked for what to do when it got faulty, i was told to bring it back to them.

Does anybody get knows of any engineer that can replace broken Android screens cos a dude raised an issue on p2's thread over the unavailability of cc for this phone yet in Nigeria? That's the only fear I've got now cos over can never tell when the screen will break

can anyone here help fix or replace a broken Android screen. please if you can, pm me on whatsapp:08103986669

Thanks a lot guys! Whatsapp is now on virtually all the phones around me now.

doubleDx:

Thanks for that observation. The error was from my typing, I'll fix it now....

Aiit boss

doubleDx:

Thanks and that makes it wrong!




@Mr Calculus, Check ur steps => Log₂ can't just cancel out like that... it ignores the laws of log... Applying laws of Log on the LHS, you should arrive @ =>

Log{(x² + 7x - 2)/(x² + 3x - 6)}₂ = 3/2, Since Log2₂ = 1 on the RHS.

Eliminating Log₂ should give you =>

(x² + 7x - 2)/(x² + 3x - 6) = 2^(3/2)
(x² + 7x - 2)/(x² + 3x - 6) = √2³
(x² + 7x - 2)/(x² + 3x - 6) = √8
So that => x² + 7x - 2 = 2√2(x² + 3x - 6) when you cross multiply the fraction on the LHS.



Yeah bruv, on point! Typing some mathematical symbols here ain't easy.... One of the reason why some questions are ignored on this thread!

Exactly what I was about to tell Mr calculus

doubleDx:


Solution

Log(x² + 7x - 2)₂ = Log(x² + 3x - 6)₂ + Log8₄

Log(x² + 7x - 2)₂ = Log(x² + 3x - 6)₂ + Log2³_2²
Log(x² + 7x - 2)₂ - Log(x² + 3x - 6)₂ = 3/2Log2₂

Log2₂ = 1, also we have same bases on the LHS, so we apply the law of log here to yield=>

Log{(x² + 7x - 2)/(x² + 3x - 6)}₂ = 3/2 * (1)

Eliminating Log₂ yields =>

(x² + 7x - 2)/(x² + 3x - 6) = 2^(3/2)
(x² + 7x - 2)/(x² + 3x - 6) = √2³
(x² + 7x - 2)/(x² + 3x - 6) = 2√2
x² + 7x - 2 = 2√2 (x² + 3x - 6)
x² + 7x - 2 = 2√2 x² + 6x√2 - 12√2

Collecting like terms yields =>

x² - 2√2 x² + 7x - 6x√2 + 12√2 - 2 = 0
x²( 1 - 2√2) + x (7 - 6√2) + 12√2 - 2 = 0

Applying quadratic formula to the above =>

a = ( 1 - 2√2), b = (7 - 6√2) and c = 12√2 - 2
x = {-b±√(b² - 4ac)}/2a
x = {(6√2 - 7) ± √[(7 - 6√2)² - 4(1 - 2√2)(12√2 - 2)]}/2( 1 - 2√2)

√2 = 1.44 approx, substituting and evaluating yields =>

x = {(6(1.44) - 7) ± √[(7 - 6(1.44))² - 4(1 - 2(1.44))(12(1.44) - 2)]}/2( 1 - 2(1.44))
x = {1.64 ± √(2.69 + 114.91)}/(-3.76)
x = {1.64 ± √117.6}/(-3.76)
x = {1.64 ± 10.84/(-3.76)

Splitting =>

x = (1.64 + 10.84)/(-3.76) or (1.64 - 10.84)/(-3.76)
x = 12.48/(-3.76) or 9.2/3.76

Rounding the values of x to one decimal place yields=>

x = -3.3 approx or 2.4 approx

I hope that helps. 1heart man

good work bro, although_/2 is approximately 1.41 and not 1.44. minor error anyway

rashywire: Log(x sq + 7x - 2) base 2 equal to Log(x sq + 3x -6)base 2 + Log8 base 4

log₂(x² + 7x -2) = log₂(x² + 3x - 6) + log₄8;
log₂(x² + 7x -2) = log₂(x² + 3x - 6)+ 1/2log₂8;
log₂(x² + 7x -2) = log₂(x² + 3x - 6) + log₂8^3/2;
log₂(x² + 7x -2) = log₂(8^3/2)(x² + 3x - 6);
x² + 7x -2 = (8^3/2)(x² + 3x - 6);
please check the question very well if it's truly base 4, if it is notify me to finish this.

i got a tecno d5 yesterday and since it hasnt got what i needed, m putin it on for sales for 12k no more no less. Or if u hav tecnot3, we can swap.