₦airaland Forum

tensazangetsu20:
Its the same thing I did too in Javascript the only difference is the LinkedList data structure will be a constructor( I dont think you have to created this, its always given in the code) and you add a math.floor to the new carry value in the while loop every other variable can be declared with const the ones reassigned can be done with let but its the exact same code.

tensazangetsu20:
A linked list is its own data structure. You are taking it as an array but it isn't. That's why you are struggling.

Deicide:
What you did there is not linked list

tensazangetsu20:
So practically you are going to construct the new LinkedList and as you are iterating both linked list you are going to add both values and put them in the new linked list then return back that list.

tensazangetsu20:
True but you aren't event iterating the linked list the right way. You are taking it as an array

tensazangetsu20:
public static class LinkedList {
public int value;
public LinkedList next;

public LinkedList(int value) {
this.value = value;
this.next = null;
}
}

public LinkedList sumOfLinkedLists(LinkedList linkedListOne, LinkedList linkedListTwo) {
LinkedList nextHeadPointer = new LinkedList(0);
LinkedList currentNode = nextHeadPointer;
int carry = 0;

LinkedList nodeOne = linkedListOne;
LinkedList nodeTwo = linkedListTwo;
while (nodeOne != null || nodeTwo != null || carry != 0){
int valueOne = (nodeOne != null) ? nodeOne.value : 0;
int valueTwo = (nodeTwo != null) ? nodeTwo.value : 0;
int sumOfValues = valueOne + valueTwo + carry;

int newValue = sumOfValues % 10;
LinkedList newNode = new LinkedList(newValue);
currentNode.next = newNode;
currentNode = newNode;

carry = sumOfValues / 10;
nodeOne = (nodeOne != null) ? nodeOne.next : null;
nodeTwo = (nodeTwo != null) ? nodeTwo.next : null;

}
return nextHeadPointer.next;
}

This is the solution in Java.

LikeAking:
My solution.

function addTwoNumbers(a,b){

let xy = a.toString().replace(/,|\s/g,""

let xz = b.toString().replace(/,|\s/g,""

let zzz = Number(xy) + Number(xz)

return zzz.toString().split("".reverse().join(""

}
console.log(addTwoNumbers([9,9,9,9,9,9,9], [9,9,9,9]))

output = 89990001

NL dey convert some brackets to this green guy .

Any wia u see am use ) = bracket

tensazangetsu20:
True but you aren't event iterating the linked list the right way. You are taking it as an array

LikeAking:
U have learnt JS.

Nice one.

Use map.

use reduce.

reverse the arr with reverse.




Also drop the link.

I was trying to avoid normal javascript array methods at all cost

tensazangetsu20:
You aren't even meant to solve this question like this at all. This is the famous sum of two linked list question asked in companies like Facebook and Google. I will send my solution but in java later. Lemme book space.

Input: l1 = [2,4,3], l2 = [5,6,4]
Output: [7,0,8]
Explanation: 342 + 465 = 807.
Example 2:

Input: l1 = [0], l2 = [0]
Output: [0]
Example 3:

Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
Output: [8,9,9,9,0,0,0,1]

var addTwoNumbers = function(l1, l2) {

   var alpha1 = "" 
   var alpha2 = ""
   var arr = []


 // Looping through first list l1

   for(var i = 0; i< l1.length; i++){
   	alpha1 = l1[i]+alpha1

   	// converting 	l1 to string and setting it to ALPHA 1 
   }

   // Looping through second  list L2
   for(var i = 0; i< l2.length; i++){
   	alpha2 = l2[i]+alpha2

   	// converting 	l2 to string and setting it to ALPHA 2 
   }
   // Coverting alpha1 and apha2 to intergets and making their sum to a new variable string "New"
  var New = parseInt(alpha1) +  parseInt(alpha2)
   New = New + ""
 
  for(var i=0;i<New.length; i++){
// Pushing the New variable is reverse order to arr and also converting it back to interger
arr.push(parseInt(New[New.length-i-1]))

  }
  // Returning the array
  return arr
};
addTwoNumbers([9,9,9,9,9,9,9],[9,9,9,9])

Line 51 in solution.js
             throw new TypeError(__serialize__(ret) + " is not valid value for the expected return type ListNode";
             ^
TypeError: [null,null,null] is not valid value for the expected return type ListNode

charlsecy:
Ok, but it's completely acceptable as a means of identification.

charlsecy:
Not sure they actively issue original currently. You can print the digital and it becomes original.

charlsecy:
Not true. You can get the plastic [or laminated] as soon you have a NIN for a fee of N400 or N1,000 [plus service fee]. Read How to Print Your Improved NIN Slip