#Count By
#Suppose you want to count from some number start_num by another number count_by until you hit a final number end_num. Use break_num as the variable that you'll change each time through the loop. For simplicity, assume that end_num is always larger than start_num and count_by is always positive.

#Before the loop, what do you want to set break_num equal to? How do you want to change break_num each time through the loop? What condition will you use to see when it's time to stop looping?

#After the loop is done, print out break_num, showing the value that indicated it was time to stop looping. It is the case that break_num should be a number that is the first number larger than end_num.




start_num = #provide some start number
end_num = #provide some end number that you stop when you hit
count_by = #provide some number to count by

# write a while loop that uses break_num as the ongoing number to
# check against end_num


print(break_num)

#Count By Check
#Suppose you want to count from some number start_num by another number count_by until you hit a final number end_num, and calculate break_num the way you did in the last quiz.

#Now in addition, address what would happen if someone gives a start_num that is greater than end_num. If this is the case, set result to "Oops! Looks like your start value is greater than the end value. Please try again." Otherwise, set result to the value of break_num.


start_num = #provide some start number
end_num = #provide some end number that you stop when you hit
count_by = #provide some number to count by

# write a condition to check that end_num is larger than start_num before looping
# write a while loop that uses break_num as the ongoing number to
# check against end_num


print(result)

#Tag Counter
#Write a for loop that iterates over a list of strings, tokens, and counts how many of them are XML tags. XML is a data language similar to HTML. You can tell if a string is an XML tag if it begins with a left angle bracket "<" and ends with a right angle bracket ">". Keep track of the number of tags using the variable count.

#You can assume that the list of strings will not contain empty strings.


tokens = ['<greeting>', 'Hello World!', '</greeting>']
count = 0

# write your for loop here


print(count)

#Zip Coordinates
#Use zip to write a for loop that creates a string specifying the label and coordinates of each point and appends it to the list points. Each string should be formatted as label: x, y, z. For example, the string for the first coordinate should be F: 23, 677, 4.


x_coord = [23, 53, 2, -12, 95, 103, 14, -5]
y_coord = [677, 233, 405, 433, 905, 376, 432, 445]
z_coord = [4, 16, -6, -42, 3, -6, 23, -1]
labels = ["F", "J", "A", "Q", "Y", "B", "W", "X"]

points = []
# write your for loop here


for point in points:
print(point)

#Zip Lists to a Dictionary
#Use zip to create a dictionary cast that uses names as keys and heights as values.

cast_names = ["Barney", "Robin", "Ted", "Lily", "Marshall"]
cast_heights = [72, 68, 72, 66, 76]

cast = # replace with your code
print(cast)

verse_dict = {'if': 3, 'you': 6, 'can': 3, 'keep': 1, 'your': 1, 'head': 1, 'when': 2, 'all': 2, 'about': 2, 'are': 1, 'losing': 1, 'theirs': 1, 'and': 3, 'blaming': 1, 'it': 1, 'on': 1, 'trust': 1, 'yourself': 1, 'men': 1, 'doubt': 1, 'but': 1, 'make': 1, 'allowance': 1, 'for': 1, 'their': 1, 'doubting': 1, 'too': 3, 'wait': 1, 'not': 1, 'be': 1, 'tired': 1, 'by': 1, 'waiting': 1, 'or': 2, 'being': 2, 'lied': 1, 'don\'t': 3, 'deal': 1, 'in': 1, 'lies': 1, 'hated': 1, 'give': 1, 'way': 1, 'to': 1, 'hating': 1, 'yet': 1, 'look': 1, 'good': 1, 'nor': 1, 'talk': 1, 'wise': 1}
print(verse_dict, '\n')

# find number of unique keys in the dictionary
num_keys =
print(num_keys)

# find whether 'breathe' is a key in the dictionary
contains_breathe =
print(contains_breathe)

# create and sort a list of the dictionary's keys
sorted_keys =

# get the first element in the sorted list of keys
print()

# find the element with the highest value in the list of keys
print()

bonus_question_what_is_the_first_key_in_verse_dict =

#COUNT UNIQUE WORDS

#Your task for this quiz is to find the number of unique words in the text. In the code editor below, complete these three steps to get your answer.
#1. Split verse into a list of words. Hint: You can use a string method you learned in the previous lesson.
#2. Convert the list into a data structure that would keep only the unique elements from the list.
#3. Print the length of the container.

verse = "if you can keep your head when all about you are losing theirs and blaming it on you if you can trust yourself when all men doubt you but make allowance for their doubting too if you can wait and not be tired by waiting or being lied about don’t deal in lies or being hated don’t give way to hating and yet don’t look too good nor talk too wise"
print(verse, '\n')

# split verse into list of words
verse_list =
print(verse_list, '\n')

# convert list to a data structure that stores unique elements
verse_set =
print(verse_set, '\n')

# print the number of unique words
num_unique =
print(num_unique, '\n')

elements = {'hydrogen': {'number': 1, 'weight': 1.00794, 'symbol': 'H'},
'helium': {'number': 2, 'weight': 4.002602, 'symbol': 'He'}}

# todo: Add an 'is_noble_gas' entry to the hydrogen and helium dictionaries
# hint: helium is a noble gas, hydrogen isn't
#hint: After inserting the new entries you should be able to perform these lookups:

#>>>print(elements['hydrogen']['is_noble_gas'])
#<<< False
#>>> print(elements['helium']['is_noble_gas'])
#<<< True

# Define a Dictionary, population,
# that provides information
# on the world's largest cities.
# The key is the name of a city
# (a string), and the associated
# value is its population in
# millions of people.

# Key | Value
# Shanghai | 17.8
# Istanbul | 13.3
# Karachi | 13.0
# Mumbai | 12.5

# Use this playground to experiment with list methods, using Test Run

#Quiz: Slicing Lists
#Select the three most recent dates from this list using list slicing notation. Hint: negative indexes work in slices!

eclipse_dates = ['June 21, 2001', 'December 4, 2002', 'November 23, 2003',
'March 29, 2006', 'August 1, 2008', 'July 22, 2009',
'July 11, 2010', 'November 13, 2012', 'March 20, 2015',
'March 9, 2016']


# TODO: Modify this line so it prints the last three elements of the list
print(eclipse_dates)

#Quiz: List Indexing
#Use list indexing to determine how many days are in a particular month based on the integer variable month, and store that value in the integer variable num_days. For example, if month is 8, num_days should be set to 31, since the eighth month, August, has 31 days.

#Remember to account for zero-based indexing!



month = 8
days_in_month = [31,28,31,30,31,30,31,31,30,31,30,31]

# use list indexing to determine the number of days in month


print(num_days)

#Quiz: Assign and Modify Variables
#Now it's your turn to work with variables. The comments in this quiz (the lines that begin with #) have instructions for creating and modifying variables. After each comment write a line of code that implements the instruction.

#Note that this code uses scientific notation to define large numbers. 4.445e8 is equal to 4.445 * 10 ** 8 which is equal to 444500000.0.

# Write your function here. Make sure to use "population_density" as the name of the fucntion. so, the test below works.



# test cases for your function Dont change anything below this comment.

test1 = population_density(10, 1)
expected_result1 = 10
print("expected result: {}, actual result: {}".format(expected_result1, test1))

test2 = population_density(864816, 121.4)
expected_result2 = 7123.6902801
print("expected result: {}, actual result: {}".format(expected_result2, test2))

#Note that this code uses scientific notation to define large numbers. 4.445e8 is equal to 4.445 * 10 ** 8 which is equal to 444500000.0.

# The current volume of a water reservoir (in cubic metres)
reservoir_volume = 4.445e8
# The amount of rainfall from a storm (in cubic metres)
rainfall = 5e6

# decrease the rainfall variable by 10% to account for runoff




# add the rainfall variable to the reservoir_volume variable




# increase reservoir_volume by 5% to account for stormwater that flows into the reservoir in the days following the storm




# decrease reservoir_volume by 5% to account for evaporation




# subtract 2.5e5 cubic metres from reservoir_volume to account for water that's piped to arid regions.





# print the new value of the reservoir_volume variable

#Quiz: Calculate
#In this quiz you're going to do some calculations for a tiler. Two parts of a floor need tiling. One part is 9 tiles wide by 7 tiles long, the other is 5 tiles wide by 7 tiles long. Tiles come in packages of 6.

#1. How many tiles are needed?
#2. You buy 17 packages of tiles containing 6 tiles each. How many tiles will be left over?




# Fill this in with an expression that calculates how many tiles are needed.
print()

# Fill this in with an expression that calculates how many tiles will be left over.
print()

#1. What is the length of the string variable verse?
#2. What is the index of the first occurrence of the word 'and' in verse?
#3. What is the index of the last occurrence of the word 'you' in verse?
#4. What is the count of occurrences of the word 'you' in the verse?


verse = "If you can keep your head when all about you\n Are losing theirs and blaming it on you,\nIf you can trust yourself when all men doubt you,\n But make allowance for their doubting too;\nIf you can wait and not be tired by waiting,\n Or being lied about, don’t deal in lies,\nOr being hated, don’t give way to hating,\n And yet don’t look too good, nor talk too wise:"
print(verse)

# Use the appropriate functions and methods to answer the questions above
# Bonus: practice using .format() to output your answers in descriptive messages!

Nawao

Thanks

Nice

thanks

lekki1444:
ahhh if he swallowed his tongue he done die be that. no remedy

lekki1444:
referee made sure he did not swallow his tongue. that ref na the real MVP

Assume he swallowed his tongue what will happen sire?


Please am just asking

"""
This is the second task of our HNG intenship program. we are expected to output our name, id and language
"""


def code():

firstName = '[Emmanuel]'
lastName = '[Nduaguba]'
id = '[HNG-01522]'
email = 'nduagubaemma@gmail.com'
language = '[Python]'
print('Hello World,this is', firstName, lastName ,'with HNGi7 ID', id, 'using', language, 'for stage 2 ',email)

code()

my new note 8 redmi battery no dey last guyhs plz i need help seriously

my new redmi note battery does not last please. i need help seriously

abdsamad:


Umm, does your battery last 1 hr after a full charge? Is it 2 hrs. Is it 4. Does it change with your activity. How is it overnight when ure not using it. Surely u know that you didn't provide nearly enough information for anyone to be able to help you. Saying it doesn't last "at all" does not say anything to anyone other than yourself.

Now you have made me to SHALAYA

Yesterday night it was 97 , this early morning it was 85 ... Something is wrong sir

My new redmi note 8 no dey last for battery guys

hardeycute:
Update your phone if you have any pending updates and relax for few days for optimization.

.


Ok sir

abdsamad:


Define "at all"

I don't understand