Who can solve this tricky illustration, gurus in the house let's see how good you are in mathematics.

27kg. ✅

This one no be guru dem mathematics

meum:
27kg. ✅

This one no be guru dem mathematics

Show all working

Stanweezy:


Show all working

For what you should have added options A,B,C,D & E E for us to choose from?

Let me give it a shot.

Assuming weight of Cat & Mouse are 7kg & 3kg respectively,
Then dog will be 17kg since Dog & mouse equals 20kg.

From the above values, weight of dog + weight of cat equals 24 (I.e. 17kg + 7kg)

Therefore the weight of all three animals(mouse, cat & dog) equals 27kg (I.e. 3kg + 7kg + 17kg) QED😁

meum:

For what you should have added options A,B,C,D & E E for us to choose from?

Let me give it a shot.

Assuming weight of Cat & Mouse are 7kg & 3kg respectively,
Then dog will be 17kg since Dog & mouse equals 20kg.

From the above values, weight of dog + weight of cat equals 24 (I.e. 17kg + 7kg)

Therefore the weight of all three animals(mouse, cat & dog) equals 27kg (I.e. 3kg + 7kg + 17kg) QED😁

Hahahaha

In mathematics we don't assume, you have to show how you arrived at the individual weight of those animals

C= Cat
D= Dog
R = Rat.
C + R = 10.
D + R = 20.
C + D = 24.
C = 10 - R
D = 20- R
C + D = (10-R)+(20-R)
I know say I dey do rubbish.

Stanweezy:



Hahahaha

In mathematics we don't assume, you have to show how you arrived at the individual weight of those animals

Do you know about “if statements” & “let X be…” in computer programming & mathematics? These are assumptions.
So assumptions are valid as long as you can prove your final answer based on it

meum:

Do you know about “if statements” & “let X be…” in computer programming & mathematics? These are assumptions.
So assumptions are valid as long as you can prove your final answer based on it

If you are using X, Y and Z or any other letter for equation, you have to show how you arrived at your answer

In mathematics theory question, the instruction states "show all working"

Let x be mouse
Let y be cat and z be dog.
From the diagram
x+y=10 ----------(1)
x+z=20 -----------(2)
y+z=24 -----------(3)

(1) + (2) ===>. 2x + y + z= 30 -------(4)
Put (3) in (4) ===>. 2x + 24= 30
===> 2x=30 -24=6
.•. x= 3
Put x =3 in (1)
Gives y= 10 - 3=7

Put y=7 in (3)
Gives z=24 - 7 = 17

So x+y+z = 3 + 7 + 17= 27

D

Las las na olodo be una president now and forever more.

27kg.

Cheap Data on my signature

Aba
The sum of the first three pictures is 2times the animals in the questions picture.

If we sum the 3 picture and their weights, we get 2dogs, two cats and two rats which their sum is 57.

This simply means the 1 dog, 1 cat and 1 rat will be half of 54.... Which is 27.

It's a no brainer...