naturalwaves:

Weldone bro. I guess this is the kind of intelligence akinaphysicist, Godisbiafran and yungmillionaire meant

yorex2011:

Don't mind me jor.. Been in the occupied with some real awesome stuff lately
My BBM wey don nearly cast lol... I go msg you now sha

naturalwaves:

The ideal thing is to first of all use the wuru wuru method now before setting out to solve so that one will have an idea of what the answer should look like. It is a smart way of reasoning. However, you are failing to get my points. Sometimes, the answer set may span a larger loop and because of that we need to set out standard ways of resolving such questions for the sake of other people watching( same thing cacawa was trying to communicate to you). You be chairman now. Who would doubt your ability of being able to solve such question.

naturalwaves:

Thank you bro. Since Akinphysicist has decided to dance in circles and not provide a suitable solution to the question nor provide an alternative method that is more acceptable, let me solve it through a way that is devoid of wuruwuru and trial by error like he did for the benefits of secondary school students and others viewing the thread. See solution attached below.
cc:cacawa

AkinPhysicist:
Okay. CACAWA before I go let me educate you. This is how you solve that problem without taking SQUARES:

You count.

Reduce the problem to a + b = 15. Then count.

1 + 14 is disqualified do you know why?
2 +13 also disqualified do you know why?
3 + 12 also disqualified do you know why?
4 + 11 also disqualified do you know why?
5 + 10 also disqualified do you know why?
go down the list and you will see only 8 and 7 qualifies therefore x = a^2 = 7^2 = 49 OR use b to get the same result.

Cacawa you are a formally trained mathematician but you are not creative. Find out why this method works and get back at me later. I have things to do. BY THE WAY IT TOOK ME LESS THAN A MINUTE USING THE COUNTING METHOD. TRY IT.




Kelvinreality - after giving Cacawe all night to answer the question above, I have concluded he is incapable of basic logic. Here is the explanation:

x^1/2 + (x+15)^1/2 = 15. If an integer solution exist, then you can obtain it by counting. Here is how it works.

Let a = x^1/2 and b= (x+15)^1/2 so the eq. becomes a + b =15. So choose a pair of integer a and b whose sum gives you 15. However, NOT all pairs qualify because a^2 has to be equal to b^2 - 15 (since both have to be equal to x). So all you have to do is count from 0 to 15 to see which pair qualifies. Clearly any pair with a from 0 to 5 fails because in this case a^2 is clearly less than b^2 -15. You don't even need to do any calculation - all you need to know is if b^2 -15 is greater (or smaller) than or equal to a^2. If its equal then you have your solution. No calculator required. Nothing. Just basic logic of counting.

AkinPhysicist:
Okay. CACAWA before I go let me educate you. This is how you solve that problem without taking SQUARES:

You count.

Reduce the problem to a + b = 15. Then count.

1 + 14 is disqualified do you know why?
2 +13 also disqualified do you know why?
3 + 12 also disqualified do you know why?
4 + 11 also disqualified do you know why?
5 + 10 also disqualified do you know why?
go down the list and you will see only 8 and 7 qualifies therefore x = a^2 = 7^2 = 49 OR use b to get the same result.

Cacawa you are a formally trained mathematician but you are not creative. Find out why this method works and get back at me later. I have things to do. BY THE WAY IT TOOK ME LESS THAN A MINUTE USING THE COUNTING METHOD. TRY IT.




Kelvinreality - after giving Cacawe all night to answer the question above, I have concluded he is incapable of basic logic. Here is the explanation:

x^1/2 + (x+15)^1/2 = 15. If an integer solution exist, then you can obtain it by counting. Here is how it works.

Let a = x^1/2 and b= (x+15)^1/2 so the eq. becomes a + b =15. So choose a pair of integer a and b whose sum gives you 15. However, NOT all pairs qualify because a^2 has to be equal to b^2 - 15 (since both have to be equal to x). So all you have to do is count from 0 to 15 to see which pair qualifies. Clearly any pair with a from 0 to 5 fails because in this case a^2 is clearly less than b^2 -15. You don't even need to do any calculation - all you need to know is if b^2 -15 is greater (or smaller) than or equal to a^2. If its equal then you have your solution. No calculator required. Nothing. Just basic logic of counting.

GodIsBiafran:


Akinphysicist (aka Afonja bigot ) In my next life I will like to inherit that your brain - not your Afonja conehead but that quantum wiring in your cerebral cortex

GodIsBiafran:


Akinphysicist (aka Afonja bigot ) In my next life I will like to inherit that your brain - not your Afonja conehead but that quantum wiring in your cerebral cortex

AkinPhysicist:

Shekiri ni yungmill ko gbo yooba dada - PM eh.

CACAWA:


Excellent.

This is what maths should look like.

God bless you

YungMillionaire:
I will like to set up a Nairaland Math/Science club. I see more than a few talents on this thread. Even the textbook warriors have their own little place in my heart Lets bring all these talents together and share ideas, solve problems and have math fun on this forum.

inschool:
any questions for prize tonight.... I need the money sincerely

CACAWA:


Solve this in less than 30 minutes

Find the equation of the normal to the curve f(x) = x^(x squared) at the point x = 3

Just #5 k because it is too easy

inschool:
cc.cacawa

Horllamideh:

Mo tii te msg sii baba nla jare. Emi yin a gun baba mi

AkinPhysicist:


It seems your flaaatttthead is a glutton for punishment. Come closer let me flog that foolishness off your life!

YungMillionaire:

Horllamideh - please send the following details to khalidkay777@gmail.com:
Your fullname:
Bank Name:
Bank Address:
Bank Account:
Your Address:
I will have it wired to you.

GodIsBiafran:

Why should this Hollamide guy get anything. He didn't not even attempt the question. What kind of fvckery is this? Sometimes Akin can be so arbitrary. At least the money should go to a University student who is working hard towards a degree.

CACAWA:

Awww you are good, bit you answered a wrong question.
Y is not equal to x squared
Y = x^(x squared)
That means x to the power of x-square

CACAWA:

Awww you are good, bit you answered a wrong question.
Y is not equal to x squared
Y = x^(x squared)
That means x to the power of x-square

GodIsBiafran:


Why should this Hollamide guy get anything. He didn't not even attempt the question. What kind of fvckery is this? Sometimes Akin can be so arbitrary. At least the money should go to a University student who is working hard towards a degree.