₦airaland Forum

Area kor, area boy ni. You go see how afonja dem go avoid this post with all their life.

ifada123:
Solid foods belongs to matured people, at this time everyone know what eight sided polygon is called, but what, how do we interact with an irregular polygon I believe it is a problem to many,
Show your workings
What is the area of the eight sided polygon?

Mitocyan:
This is very smart and intelligent. Although cos 135degree is -ve of cos45degree. This will alter your final answer. As a result you should obtain R as Sqrt[(13/2)+3sqrt2]=3.2776 which tallies with my answer. There shouldn't be minus inside that sqrt like you got. At the end my answer will still be correct. Shoot me an email at TERECUKAMAYA_AT_GMAIL_DOT_COM let's relate

Yes I actually use the + to evaluate, the final answer,
Check your solution again sir, because from all methods ihave used the answer ends up at 13+12√2

Mitocyan:
This is very smart and intelligent. Although cos 135degree is -ve of cos45degree. This will alter your final answer. As a result you should obtain R as Sqrt[(13/2)+3sqrt2]=3.2776 which tallies with my answer. There shouldn't be minus inside that sqrt like you got. At the end my answer will still be correct. Shoot me an email at TERECUKAMAYA_AT_GMAIL_DOT_COM let's relate

Yes I actually use the + to evaluate, the final answer,
Check your solution again sir, because from all methods ihave used the answer ends up at 13+12√2

Mitocyan:
Was it Heron's formula you used to arrive at the areas of triangles with bases 2 and 3?

Find the height and use it for evaluation or you can also use hero's formula ,

femi4:
r should be √ 13/2 + 3√2

Cos 135 = - cos 45

Yes that is true. Is + not - thanks.
that was what I used later to evaluate

Mitocyan:
Ok, I understand now. It is just like dividing the Octagon into 8 triangles and rearranging the triangles to suit our agenda. Smart move. Now I must admit you are truly MR Shape. Haha

Exertly you got the idea.
Thanks for the acknowledgement

ifada123:
Check it out
I skiped some simplification though

I just corrected the solution down from R and I still arrived at the answer I got with my method.

Mitocyan:
Was it Heron's formula you used to arrive at the areas of triangles with bases 2 and 3?

No 1/2 X base X height

You took squaroot of your semi perimeter,
Whe n you sum all the sides you divide by 2
The you get s
That's is when you take the squaroot of(s(s-a)(s-b)(s-c)
If I observed your solution clearly,
Please check

ifada123:
Smile
Since you know the name can you please solve its area for us?

Area? Abeg explain

Hatima:
Area? Abeg explain

I have solved it check my solution diagram above.

Mitocyan:
Was it Heron's formula you used to arrive at the areas of triangles with bases 2 and 3?

The height of base 2
Will be √((radius^2 -(3/2)^2))
The height of 2
Will be √((radius)^2-(2/2)^2)
Then you already know the height you can then use 1/2xbase xheight to get the area

ifada123:
I have solved it check my solution diagram above.

Seen..why u cm ask us..

Hatima:
Seen..why u cm ask us..

Lol, I just posted the solution after someone got the answer,
There is beauty in variety,
U might think of Connections I have never taught of,
So we can learn from each other.