biolabee: truman u are a demon

a + b + c = 8
(a+b+c) ^2 = 64
====> a2 + b2 + c2 + 2(ab+ac+bc) = 64
====> hence ab+ac+bc = 48/2 = 24 ------------(1)


(a+b+c)^3 = 512
a3+b3+c3+ 3a(b2+c2+ + 3b(a2+c2) + 3c(a2+b2) + 6abc = 512

I only need one more equation
product of abc

I don tire

coolexy2: ](1)what is the real application of mathematics in our live?

(2) prove that:
a. Sin^3 x = 1/4(3sinx - sin3x)
b. Find 2nd derivative of:
y = cos^3 x

ositadima1: ^^^ cool

calculusx:

Bro. I want to confirm if you are the one that purchased 99 Camry Xle from me some years ago? I was doing my NYSC then if you can remember. I misplaced your contact number

ositadima1:

No be me, probably a namesake.

ositadima1:

Lol, no answer for dat, if u plot both equations the never meet each other. In other words u fabricated it

Mathano: At cryptic,It is finitely generated.A group is said to be finitely generated when there exist a^n=e. a is d generator and n is d order of d group.for a polynomial ring generated by a group dere will b a point where a^n will be equal to the identity element.

Obinoscopy:

I didn't fabricate anything but i made a little mistake in the number, will correct it though. Just solve it

I'll repeat the qxn once more:
x^x+y^y=46912, x+y=10 Find x and y.

ositadima1:

, the answers are x=6, y=4. but u still fabricated it though

ositadima1:

, the answers are x=6, y=4. but u still fabricated it though

Obinoscopy:

Show ur workings dude

Calebsworld: Prove by the principle of induction.1/1.3 +1/3.5 +1/5.7+...+1/(2n-1)(2n+1)=n/2n+1.thanks

math-diva:
Thumbs up guys for the good job. I studied pure maths in unilag and I must say that my life has been the better for it. For all those who have the passion for maths I encourage you to study it in school and learn to make your passion work for you. Maths forms the base of all science and engineering courses so it's very easy to convert to other professions. A lot of my colleagues work in banks, audit firms, marketing firms, oil and gas, telecoms, food and beverages etc

I remember in 300 and final year I rarely used my calculator cos most of the courses we did were theoretical and used more of x, y and z rather than numbers. Then I was so sure Prof Olaleru was making up some of the stuff he taught us. So you can imagine how surprised I was to find all those pure maths principles embedded in stuff I do at work.

What am just trying to tell you all who want to know if it's worth their time to study maths or stats the answer is yes, especially if your a natural guru. All the maths gurus in my class spent more time playing games than reading, in maths once u know it you know it and unless your ecturer na witch, there is no way he wants to set his questions that u will not answer it and get method mark.

masperano: @calculusx nd 2good I disagree wit u guyz wen u say anything raise to power zero is one, I can prove to u dat d definition is erroneous and ambiguous!and even any number raise to power zero is not one! So pls kindly edit ur definition!

2good: proof me wrong then.

j2012: Pls prove the following trig identities

1) Sin(t)/1+cos(t)=1/cosec(t)+cot(t)

2)2tan(t)/1-tan square(t)=2sin(t)cos(t)/(cos square(t)-sin square (t)

3)1+cot square(t)sin(t)=cosec(t)

Mathano: At johnpaul,D first thing is dat most students cram in groups and rings,If u can try to understand it and knw d basis of hw to proof it wil b easy to play with,I wil give u an example to proove dat d inverse of any group is unique,u will first make an assumption dat there are two inverses,since we are trying to proove dat it is unique d two must be equal.pf suppose dere are two inverses b and b1.let a be an element of d group ab=e,ab1=e,since b and b1 are inverses,there multiplication must give d identity element,b=eb(identity multiplied by any number will give dat number)but e=ab1,we can nw subst dat,b=ab1b,b=(ab)b1(Just reordering)but ab=e,there4 b=eb1,b=b1(since identity multiplied by any no will give d no)b=b1.Therefore d inverse is unique.Dere are loads of textbook onlyn 4 abstract algebra,u can also use kuku's textbuk,A prof in UI.

doubleDx:

Question 1.

Prove that sin t/1+ cos t = 1/cosec t + cot t.

Taking from the RHS, Since cosec t = 1/sin t and cot t = 1/tan t or cos t/sin t,
1/cosec t + cot t becomes :
= 1/[1/sin t + cos t/sin t]
=1/(1+cos t)/sin t,
inverting:
= sin t/(1+ cos t)
Hence:
sin t/(1+ cos t) = 1/cosec t + cot t.

Question 2.

Prove that:
2tan t/(1-tan^2 t) = 2cos t sin t/(cos^2 t - sin^2 t)

From the LHS,
Since tan t = sin t/cos t
2tan t/(1-tan^2 t) becomes:
=2sin t/cos t /[1/1 - (sin^2 t)/cos^2 t], inverting:
=2sin t/ cos t * cos^2 t/(cos^2 t - sin^2 t)
=2sin t cos^2 t / cos t [cos^2 t - sin^2 t]
=2sin t cos t/(cos^2 t - sin^2 t)

Hence 2tan t/(1-tan^2 t) = 2cos t sin t/(cos^2 t - sin^2 t)

Question 3.

Prove that 1+cot^2(t) sin (t) = cosec (t).

This question is prolly wrong because from the LHS,

If you substitute cot t = cos t/sin t
1 + cot^2 t sin t
=1/1 + cos^2 t * sin t/sin^2 t
sin^2 t + cos^2 t * sin t/ sin^2 t

Since the above can only be multiplied before addition is initiated according to BODMAS, there is no way the result can cancel out to give cosec t

If we add before multiplying sin^2 t + cos^2 t would be 1 to give us sin t/sin^2 t = 1/sin t or cosec t, but it's mathematically wrong to add before multiplying, meaning the question is logically incorrect!

Thus :
1+cot^2(t) sin (t) is NOT equal to cosec (t)

biolabee: Superb Doubledx

For no 3 it came to

sint + cos2t = 1

There is a missing sint
I think the original Q shd have been

sin t + cot2tsint = cosec t

j2012:

Thanks man, I appreciate.