smurfy: @ benbuks, is that your picture?

benbuks:

yes boss , surprised .?

whose do you expect ..?

smurfy:

Nice boy! I've always known you were a good 'boy'. I want you to know that I like your person very much. That's the truth.

jaryeh: Congrats bro. Happy Nairaland birthday to you.

benbuks:

thanks man..

its been a while .. hw u dey na .?

benbuks: use first principle differentiate x^1/3
hence or otherwise compute f ' [ x^1/n ]

also by first principle

NB: use of binomials/series prohibited

asap.

thanks .

guys kindly give this a try plzzz..

Allenkee: Please help me prove that
Log(1+2+3)= Log 1+ Log2+ Log3

I did it by opening the bracket to get exactly what is at the right side but was told t'was wrong.

dejt4u:
LHS: Log(1+2+3) =Log(6)
RHS: Log 1+ Log2+ Log3= log(1x2x3)=log(6),
therefore, LHS=RHS...proved

efficiencie:

If i get your theory right:

log[x(1)+x(2)+x(3)+...+x(n)]=logx(1) + logx(2) + logx(3) + ... + logx(n)

then why is it that:

log10=log[1+2+3+4]=log1 + log2 + log3 + log4 = log(1x2x3x4)=log(24)

hence

log10=log24

which is a great contradiction!!!

BestInDeeWorld: Pls ooooo, cn someone make t the subject of the formula here? S=ut+1/2at. NB: It is not squared. It has no square.

dejt4u:
this one na pry skul maths ooo..
t=2s/(2u+a)..

If the last t is squared,
t= 1/a (-u +/- sqrt(u²+2as))

dejt4u:
this one na pry skul maths ooo..
t=2s/(2u+a)..

If the last t is squared,
t= 1/a (-u +/- sqrt(u²+2as))

BestInDeeWorld:
thanks man

Arithmetic:
2)¥(2^x+2+5)+¥(5.2^x-9)=¥(3.2^x+2+21).
Find x. NB:Let ¥ rep. square root.

√(2^x+2 + 5) + √(5.2^x - 9) = √(3.2^x+2 + 21)
let 2^x = p
√(4p+5) + √(5p-9) = √(12p+21)
Squaring both sides
4p+5+5p-9+2√(4p+5)(5p-9) = 12p + 21
9p-4+2√(4p+5)(5p-9) = 12p+21
2√(4p+5)(5p-9) = 3p+25
Square both sides
4(4p+5)(5p-9) = (3p+25)
4(20p²-36p+25p-45) = 9p²+150p+625
4(20p²-11p-45) = 9p²+150p+625
80p²-44p-180 = 9p²+150p+625
71p²-194p-805 = 0
Solving quadratically,
p = 5 or -2.26
Since 2^x = p
2^x = 5
Simplifying, using log,
X = 2.3219
The second value of p which is -2.26 cannot generate real value

Drniyi4u:
I got x = 2.3219
this is d working

Arithmetic: 1)¥(x²+ax-1)+¥(x²+bx-1)=¥a+¥b.
2)¥(2^x+2+5)+¥(5.2^x-9)=¥(3.2^x+2+21).
Find x. NB:Let ¥ rep. square root.

erigwe: Please, great maths men help out with this questions.


1. A man travels from Nigeria to Ghana by air and from Ghana to Liberia by ship. He returns by the same means. He has 6 airlines and 4 shippings to choose from. In how many ways can he make his journey without using the same airline or shipping line twice. ( further maths/2006/theory/13b)


2. (a) There are 6 points in a plane. How many triangles can be formed with the points?
(b) A family of 6 is to be seated in row. In how many ways can this be done, if the father and the mother are not to sit together? (further maths/2006/theory/5)

Arithmetic: 1)¥(x²+ax-1)+¥(x²+bx-1)=¥a+¥b.
2)¥(2^x+2+5)+¥(5.2^x-9)=¥(3.2^x+2+21).
Find x. NB:Let ¥ rep. square root.

Kendzyma: rt(x^2+ax-1)+rt(x^2+bx-1)=rt(a)+rt(b)
rt(x^2+ax-1)=rt(a)
x^2+ax-1=a
x^2+a(x-1)=1..........eq 1
rt(x^2+bx-1)=rt(b)
x^2+bx-1=b
x^2+b(x-1)=1........eq 2
dividing eq 1 by eq 2
1+a/b=1
a=0
....subtituting a=0 in equation 1
x=+/-1
subtituting x=-1 in equation 2

b=0
subtituting x=1 in equation 2
b=0
hence b=a

erigwe: Please, great maths men help out with this questions.


1. A man travels from Nigeria to Ghana by air and from Ghana to Liberia by ship. He returns by the same means. He has 6 airlines and 4 shippings to choose from. In how many ways can he make his journey without using the same airline or shipping line twice. ( further maths/2006/theory/13b)


2. (a) There are 6 points in a plane. How many triangles can be formed with the points?
(b) A family of 6 is to be seated in row. In how many ways can this be done, if the father and the mother are not to sit together? (further maths/2006/theory/5)