Nairaland Mathematics Clinic - Education (181)

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Nairaland Mathematics Clinic - Education (181) - Nairaland

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Re: Nairaland Mathematics Clinic by sandrannna(f): 3:44pm On Jun 23, 2015

Geofavor:
Good afternoon guys. I hail all the gurus in da house.

Pls help me solve this,

if 1atm = 760mmhg = 101325N/m^2

then 1mmhg = XN/m^2

what is X?

X is the alphabet beside N .

Re: Nairaland Mathematics Clinic by Geofavor(m): 3:53pm On Jun 23, 2015

sandrannna:

X is the alphabet beside N .

lmao. Pls be serious

Re: Nairaland Mathematics Clinic by Ahmedie25(m): 4:53pm On Jun 23, 2015

let me try

Re: Nairaland Mathematics Clinic by Geofavor(m): 5:38pm On Jun 23, 2015

dejt4u:

X = 101325Nm^-2/760mmHg
= 133.32Nm^-2

understood! ...

Don't, mind me. It happens to me sometimes - I just get really confused over little things.
Thnx again

Re: Nairaland Mathematics Clinic by dejt4u(m): 6:38pm On Jun 23, 2015

Uwc

Geofavor:

understood! ...

Don't, mind me. It happens to me sometimes - I just get really confused over little things.
Thnx again

Re: Nairaland Mathematics Clinic by dejt4u(m): 6:42pm On Jun 23, 2015

m coming bk to solve some of ur Questions..

Pending the time.. There is a mistake in ur Question one.. It shld be like this
Simplify (x² - 1)/(x³ -2x² - x + 2)

tobillionaire:
Gurus in. D aous pls hlp o.... Simplify x^2-1/x^3-2x^2-x-2. (A) 1/x+2 (B) x+1/x+2 (C) x+1/x-2 (D) 1/x-2

2. Which of the following binary operation is commutative in the set of integers? (A) a-b=a-2b (B) a.b=a+b-ab (C) a-b=a^2+b (D) a.b=a(a+1)/2.
In triangle XYZ, <YXZ=44, and <XYZ=112, calculate the acute angle between the internal bisectors of <XYZ and <XZY. (A) 12 (B) 56 (C) 68 (D) 78

11. Two perpendicular lines PQ and QR intersect at (1, -1), if the equation of PQ is x-2y+4=0, find the equation of QR. (A) x-2+1=0 (B) 2x+y-3=0 (C) x-2y-3=0 (D) 2x+y-1=0.
Find the area bounded by the curve y=3x^2-2x +1, the ordinate x=1 and x=3 and the x-axis. (A) 24 (B) 22 (C) 21 (D) 20

33. Two variables x and y are such that dy/dx=4x-3 and y=5 when x=2. Find y in terms of x (A) 2x^2-3x +5 (B) 2x^2-3x+3 (C) 2x^2-3x (D) 4.
What is the solution set for the equation /2x-3/=13? (A) (5, (B) (-5,

Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:50pm On Jun 23, 2015

dejt4u:
m coming bk to solve some of ur Questions..

Pending the time.. There is a mistake in ur Question one.. It shld be like this
Simplify (x² - 1)/(x³ -2x² - x + 2)

yea man you're right ....

here ------$01u10n from down

*)
Given |2x-3|=13

which => +/- (2x-3)=13

i.e 2x-3=13 , => 2x=16. => x=8

or -(2x-3)=13 , => -2x+3=13 , => -2x=10 , => x=-5

hence we have (-5 , 8 ) as solution set .

*)
y= 3x^2 -x^2 +x

we compute integral for 1<x<3

=> $(3x^2 -2x+1)dx = x^3 -x^2 +x for 1<x<3
now for F(x)=x^2 -x^2 +x

we compute F(b)-F(a) (where a=1 , b=3)

so that

=> [(3^3 -3^2 +3)-(1^3 -1^2 +1)] = 21-1= 20

*)
dy/dx = 4x-3 , computing 'y' at (2,5) , we take integral on both sides

=> y=$(4x-3)dx = 4x^2 -3x +K

y=2x^2 -3x +k , now at (2,5) .

for x=2. , y=5

=> 5=2(2)^2 -3(2) +k
=> 5=2+k , thus k= 3

hence we have. y= 2x^2 -3x +3

*)
For two perpendicular lines ,

m1*m2=-1
equation of PQ = x-2y+4=0

or y= x/2 +2 , so that m1 =1/2

=> m2/2=-1. or m2=-2

now , by definition, m=(y-y1)/(x-x2)

or y-y1=m(x-x1)

Given PQ's coordinate as (1 ,-1) ..I.e x1=1 , y1=-1

thus we have

y-(-1)= -2(x-1)

or y+1=-2x+2

or 2x+y-1=0

*)

Given two angles 44° & 112°

known that sum of angles in a triangle gives 180°

thus let's call the third angle @

=> @+44+112=180
=> @= 180-156=24°

since its a bisector , => 24/2=12 °

*)
by testing a.b=a+b-ab. . is commutative .

*) option D

(wait for solution from my boss.)

Re: Nairaland Mathematics Clinic by naturalwaves: 9:22pm On Jun 23, 2015

tobillionaire:

11. Two perpendicular lines PQ and QR intersect at (1, -1), if the equation of PQ is x-2y+4=0, find the equation of QR. (A) x-2+1=0 (B) 2x+y-3=0 (C) x-2y-3=0 (D) 2x+y-1=0.
Find the area bounded by the curve y=3x^2-2x +1, the ordinate x=1 and x=3 and the x-axis. (A) 24 (B) 22 (C) 21 (D) 20

33. Two variables x and y are such that dy/dx=4x-3 and y=5 when x=2. Find y in terms of x (A) 2x^2-3x +5 (B) 2x^2-3x+3 (C) 2x^2-3x (D) 4.
What is the solution set for the equation /2x-3/=13? (A) (5, (B) (-5,

Re: Nairaland Mathematics Clinic by naturalwaves: 9:50pm On Jun 23, 2015

tobillionaire:
In triangle XYZ, <YXZ=44, and <XYZ=112, calculate the acute angle between the internal bisectors of <XYZ and <XZY. (A) 12 (B) 56 (C) 68 (D) 78

1 Like

Re: Nairaland Mathematics Clinic by tobillionaire(m): 5:32am On Jun 24, 2015

dejt4u:
m coming bk to solve some of ur Questions..

Pending the time.. There is a mistake in ur Question one.. It shld be like this
Simplify (x² - 1)/(x³ -2x² - x + 2)

. OMG... Can't download d solution

Re: Nairaland Mathematics Clinic by tobillionaire(m): 5:38am On Jun 24, 2015

agentofchange1:

yea man you're right ....

here ------$01u10n from down
*) Given |2x-3|=13
which => +/- (2x-3)=13
i.e 2x-3=13 , => 2x=16. => x=8
or -(2x-3)=13 , => -2x+3=13 , => -2x=10 , => x=-5
hence we have (-5 , 8 ) as solution set .
*) y= 3x^2 -x^2 +x
we compute integral for 1<x<3
=> $(3x^2 -2x+1)dx = x^3 -x^2 +x for 1<x<3 now for F(x)=x^2 -x^2 +x
we compute F(b)-F(a) (where a=1 , b=3)
so that
=> [(3^3 -3^2 +3)-(1^3 -1^2 +1)] = 21-1= 20
*) dy/dx = 4x-3 , computing 'y' at (2,5) , we take integral on both sides
=> y=$(4x-3)dx = 4x^2 -3x +K
y=2x^2 -3x +k , now at (2,5) .
for x=2. , y=5
=> 5=2(2)^2 -3(2) +k => 5=2+k , thus k= 3
hence we have. y= 2x^2 -3x +3
*) For two perpendicular lines ,
m1*m2=-1 equation of PQ = x-2y+4=0
or y= x/2 +2 , so that m1 =1/2
=> m2/2=-1. or m2=-2
now , by definition, m=(y-y1)/(x-x2)
or y-y1=m(x-x1)
Given PQ's coordinate as (1 ,-1) ..I.e x1=1 , y1=-1
thus we have
y-(-1)= -2(x-1)
or y+1=-2x+2
or 2x+y-1=0
*)
Given two angles 44° & 112°
known that sum of angles in a triangle gives 180°
thus let's call the third angle @
=> @+44+112=180 => @= 180-156=24°
since its a bisector , => 24/2=12 °
*) by testing a.b=a+b-ab. . is commutative .
*) option D
(wait for solution from my boss.)

tanx boss

Re: Nairaland Mathematics Clinic by dejt4u(m): 8:28am On Jun 24, 2015

tobillionaire:
Gurus in. D aous pls hlp o.... Simplify x^2-1/x^3-2x^2-x-2. (A) 1/x+2 (B) x+1/x+2 (C) x+1/x-2 (D) 1/x-2

the correct question is;
Simplify (x² - 1)/(x³ - 2x² - x + 2)

Solution:
(x² - 1)/(x³ - 2x² - x + 2) = (x² - 1²)/(x - 1)(x + 1)(x - 2),
!diff. of 2squares will be applied to the numerator while I factorize the denumerator(Long division cn be used after getting one factor)

=(x - 1)(x + 1)/(x - 1)(x + 1)(x - 2),

= 1/(x -2) Option D

Re: Nairaland Mathematics Clinic by Nobody: 9:22am On Jun 24, 2015

Question (1) missing an item

Question (2):
if number is to be greater than 4000, then it can only start with any of 4,5,6 (3 ways of starting), i.e. 3 x....
second term can have any of the other 4 numbers, once first term is fixed (no repetition), then third any of 3, then fourth any of 2.
Hence, 3 x 4 x 3 x 2 = 72 numbers

The correct answer to Question 2 is 192, i.e. 72 + 120.

Re: Nairaland Mathematics Clinic by rameoblak: 1:05pm On Jun 24, 2015

Because of these kind of mathematics clubs we can easily get the solution on the subject of maths through online. It will be more helpful for many of the members.

essay writing service uk

Re: Nairaland Mathematics Clinic by Nobody: 6:45pm On Jun 24, 2015

Please all the math gurus, help me integrate x^x dx with respect to x. Tnx

Re: Nairaland Mathematics Clinic by donriddo(m): 6:46pm On Jun 24, 2015

help Sirs.
Prove that sec^2x - (3/4)secx = 1/2

Re: Nairaland Mathematics Clinic by Profmaojo: 9:30pm On Jun 24, 2015

Pls help with dis question...FIND the root of the equation if x^3-x-1=0 using bisection method, let epsulum =0.001

Re: Nairaland Mathematics Clinic by frob0genius(f): 3:25pm On Jun 25, 2015

Profmaojo:
Pls help with dis question...FIND the root of the equation if x^3-x-1=0 using bisection method, let epsulum =0.001

Firstly, you need to find two points say a and b such that if you put a or b in f(x) either f(a) or f(b) would give you opposite signs i.e either f(a) can be negative or f(b). But they can't have the same sign.
Let the interval be [1,2].
This implies that a=1 f(a) =-1
b=2 f(b) =5
Next find xo which is (1+2)/2=1.5
F(xo) =0.875
Since your f(a) * f(xo) <0 your new interval is [1,1.5]
Continue your iteration until your error =0.001

Re: Nairaland Mathematics Clinic by Profmaojo: 7:30pm On Jun 25, 2015

Pls ma i didn't get d answer , can u help me to complete it pls

frob0genius:

Firstly, you need to find two points say a and b such that if you put a or b in f(x) either f(a) or f(b) would give you opposite signs i.e either f(a) can be negative or f(b). But they can't have the same sign.
Let the interval be [1,2].
This implies that a=1 f(a) =-1
b=2 f(b) =5
Next find xo which is (1+2)/2=1.5
F(xo) =0.875
Since your f(a) * f(xo) <0 your new interval is [1,1.5]
Continue your iteration until your error =0.001

Re: Nairaland Mathematics Clinic by frob0genius(f): 7:58pm On Jun 25, 2015

Profmaojo:
Pls ma i didn't get d answer , can u help me to complete it pls

I didn't get the answer, I just started it.
Do you know how to use bisection method?

Something like this.
But you continue iterating until the absolute value of your f(xn) minus f(xn-1) is less than or equal to epsilon

2 Shares

Re: Nairaland Mathematics Clinic by MaxGraviton: 11:23am On Jun 26, 2015

Pls Someone help me with this. . .

Re: Nairaland Mathematics Clinic by Antoinne: 3:00pm On Jun 26, 2015

^^please check the question again; looks funny.

Re: Nairaland Mathematics Clinic by Nobody: 10:35pm On Jun 26, 2015

All the math guruz in the house, help me integrate x^x dx.

Re: Nairaland Mathematics Clinic by Seriallinks(m): 3:54am On Jun 27, 2015

timonski:
All the math guruz in the house, help me integrate x^x dx.

I don't think there is any solution to your problem in terms of standard mathematical functions!

Re: Nairaland Mathematics Clinic by Profmaojo: 8:44pm On Jun 27, 2015

Tanks alot ..My lecturer just introduce it to us in mth201 and he gave us dis assignment

frob0genius:

I didn't get the answer, I just started it.
Do you know how to use bisection method?

Something like this.
But you continue iterating until the absolute value of your f(xn) minus f(xn-1) is less than or equal to epsilon

Re: Nairaland Mathematics Clinic by agentofchange1(m): 5:21pm On Jun 28, 2015

tobillionaire:
tanx boss

Uwc man.

Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:18pm On Jun 28, 2015

hey guys. ...try out

compute the Laplace transform
given f(t)= tan(kt )

Re: Nairaland Mathematics Clinic by aman2(m): 12:23am On Jun 29, 2015

Ehinafe:

Solomon111, you are quite correct, but you should realize that dynamic programming and Non-linear programme are better-suited to real-life situation than all other mathematical models

purely for statisticians. if u really guru. prove d simpson1/3 rule n state it axiom

Re: Nairaland Mathematics Clinic by aman2(m): 12:29am On Jun 29, 2015

mr guru. kindly determine the inner product of (f g)=integral as c(a~b). using d 4 axioms

Re: Nairaland Mathematics Clinic by benji93: 7:10pm On Jun 29, 2015

aman2:

purely for statisticians. if u really guru. prove d simpson1/3 rule n state it axiom

how much will you pay if i prove it

Re: Nairaland Mathematics Clinic by benji93: 7:18pm On Jun 29, 2015

prove the intersecting chord theorem?

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