pls anyone 5(x-1)+3(2x+9)-2=4(3x-1)+2(4x+3)...@sap

kidrossy:
pls anyone
5(x-1)+3(2x+9)-2=4(3x-1)+2(4x+3)...@sap

are u sure about this question??

Check it again pls 'cos this is JSS1 maths question

dejt4u:
are u sure about this question??
Check it again pls 'cos this is JSS1 maths question

I don't think the options are correct...that is why I brought it here...

2!

maverickboy:
2!

2! = 2* 1 =2

kidrossy:
pls anyone 5(x-1)+3(2x+9)-2=4(3x-1)+2(4x+3)...@sap

5 (x-1)+3 (2 x+9)-2 = 4 (3 x-1)+2 (4 x+3) Solve for x: -2+5 (x-1)+3 (2 x+9) = 4 (3 x-1)+2 (4 x+3) 5 (x-1) = 5 x-5: -2+5 x-5+3 (2 x+9) = 4 (3 x-1)+2 (4 x+3) 3 (2 x+9) = 6 x+27: 6 x+27+5 x-5-2 = 4 (3 x-1)+2 (4 x+3) Grouping like terms, 6 x+5 x-5-2+27 = (5 x+6 x)+(-2-5+27): (5 x+6 x)+(-2-5+27) = 4 (3 x-1)+2 (4 x+3) 5 x+6 x = 11 x: 11 x+(-2-5+27) = 4 (3 x-1)+2 (4 x+3) -2-5+27 = 20: 11 x+20 = 4 (3 x-1)+2 (4 x+3) 4 (3 x-1) = 12 x-4: 11 x+20 = 12 x-4+2 (4 x+3) 2 (4 x+3) = 8 x+6: 11 x+20 = 8 x+6+12 x-4 Grouping like terms, 12 x+8 x-4+6 = (12 x+8 x)+(-4+6): 11 x+20 = (12 x+8 x)+(-4+6) 12 x+8 x = 20 x: 11 x+20 = 20 x+(-4+6) 6-4 = 2: 11 x+20 = 20 x+2 Subtract 20 x from both sides: (11 x-20 x)+20 = (20 x-20 x)+2 11 x-20 x = -9 x: -9 x+20 = (20 x-20 x)+2 20 x-20 x = 0: 20-9 x = 2 Subtract 20 from both sides: (20-20)-9 x = 2-20 20-20 = 0: -9 x = 2-20 2-20 = -18: -9 x = -18 Divide both sides of -9 x = -18 by -9: (-9 x)/(-9) = (-18)/(-9) (-9)/(-9) = 1: x = (-18)/(-9) The gcd of -18 and -9 is -9, so (-18)/(-9) = (-9×2)/(-9×1) = (-9)/(-9)×2 = 2: Answer: | | x = 2

Karmanaut:

5 (x-1)+3 (2 x+9)-2 = 4 (3 x-1)+2 (4 x+3)
Solve for x:
-2+5 (x-1)+3 (2 x+9) = 4 (3 x-1)+2 (4 x+3)
5 (x-1) = 5 x-5:
-2+5 x-5+3 (2 x+9) = 4 (3 x-1)+2 (4 x+3)
3 (2 x+9) = 6 x+27:
6 x+27+5 x-5-2 = 4 (3 x-1)+2 (4 x+3)
Grouping like terms, 6 x+5 x-5-2+27 = (5 x+6 x)+(-2-5+27):
(5 x+6 x)+(-2-5+27) = 4 (3 x-1)+2 (4 x+3)
5 x+6 x = 11 x:
11 x+(-2-5+27) = 4 (3 x-1)+2 (4 x+3)
-2-5+27 = 20:
11 x+20 = 4 (3 x-1)+2 (4 x+3)
4 (3 x-1) = 12 x-4:
11 x+20 = 12 x-4+2 (4 x+3)
2 (4 x+3) = 8 x+6:
11 x+20 = 8 x+6+12 x-4
Grouping like terms, 12 x+8 x-4+6 = (12 x+8 x)+(-4+6):
11 x+20 = (12 x+8 x)+(-4+6)
12 x+8 x = 20 x:
11 x+20 = 20 x+(-4+6)
6-4 = 2:
11 x+20 = 20 x+2
Subtract 20 x from both sides:
(11 x-20 x)+20 = (20 x-20 x)+2
11 x-20 x = -9 x:
-9 x+20 = (20 x-20 x)+2
20 x-20 x = 0:
20-9 x = 2
Subtract 20 from both sides:
(20-20)-9 x = 2-20
20-20 = 0:
-9 x = 2-20
2-20 = -18:
-9 x = -18
Divide both sides of -9 x = -18 by -9:
(-9 x)/(-9) = (-18)/(-9)
(-9)/(-9) = 1:
x = (-18)/(-9)
The gcd of -18 and -9 is -9, so (-18)/(-9) = (-9×2)/(-9×1) = (-9)/(-9)×2 = 2:
Answer: |
| x = 2

modified...
My answer to question is x = 2

Karmanaut:

2! = 2* 1
=2

just remember I shouldn't have used the sign (!). the answer is 2 and not 2! (2 factorial)

kidrossy:
pls anyone
5(x-1)+3(2x+9)-2=4(3x-1)+2(4x+3)...@sap

X equals 2 not 3/2

Please help

All workings are needed (step to step workings with full details) on how it is solve

Thanks in anticipation






1) Using 4 sub intervals in the composite trapezium rule approximate intergral 5-1 I.e integral of 5 upper limit and 1 lower limit (square root Xdx)


2) The function f is known to have a second derivative with the property that /f"(x)/ < 12
For x between 2 and 3. Using the error bound giving earlier in this section determine how many sub intervals are required so that the composite trapezieum rule used to approximate integral 5-2 f(x)dx


3) Using 4 sub intervals in the composite simpson rule approximate. Integral 5-1 square root xdx

4) The function f is known to have a forth derivative with the property that f^(iv) (x)<6
For x between -1 and 5. Determine how many sub intervals are required so that the composite trapezium rule use to approximate integral 5 - (-2) f(x)dx incurs an error that is less than 0.001.

worthing:
integrate In(cosx)dx

I doubt if an analytical solution to this exist.

Good evening guys,
Please take a look at this question.

Three digit numbers re formed from the digits 1,2,4,5,6. If repetition is not allowed and a number is picked at random, find the probability that it's a multiple of 5 or an odd number.

From my calculations, I got 2/5 but the text says it's 3/5. Who is wrong?

Karmanaut:

5 (x-1)+3 (2 x+9)-2 = 4 (3 x-1)+2 (4 x+3)
Solve for x:
-2+5 (x-1)+3 (2 x+9) = 4 (3 x-1)+2 (4 x+3)
5 (x-1) = 5 x-5:
-2+5 x-5+3 (2 x+9) = 4 (3 x-1)+2 (4 x+3)
3 (2 x+9) = 6 x+27:
6 x+27+5 x-5-2 = 4 (3 x-1)+2 (4 x+3)
Grouping like terms, 6 x+5 x-5-2+27 = (5 x+6 x)+(-2-5+27):
(5 x+6 x)+(-2-5+27) = 4 (3 x-1)+2 (4 x+3)
5 x+6 x = 11 x:
11 x+(-2-5+27) = 4 (3 x-1)+2 (4 x+3)
-2-5+27 = 20:
11 x+20 = 4 (3 x-1)+2 (4 x+3)
4 (3 x-1) = 12 x-4:
11 x+20 = 12 x-4+2 (4 x+3)
2 (4 x+3) = 8 x+6:
11 x+20 = 8 x+6+12 x-4
Grouping like terms, 12 x+8 x-4+6 = (12 x+8 x)+(-4+6):
11 x+20 = (12 x+8 x)+(-4+6)
12 x+8 x = 20 x:
11 x+20 = 20 x+(-4+6)
6-4 = 2:
11 x+20 = 20 x+2
Subtract 20 x from both sides:
(11 x-20 x)+20 = (20 x-20 x)+2
11 x-20 x = -9 x:
-9 x+20 = (20 x-20 x)+2
20 x-20 x = 0:
20-9 x = 2
Subtract 20 from both sides:
(20-20)-9 x = 2-20
20-20 = 0:
-9 x = 2-20
2-20 = -18:
-9 x = -18
Divide both sides of -9 x = -18 by -9:
(-9 x)/(-9) = (-18)/(-9)
(-9)/(-9) = 1:
x = (-18)/(-9)
The gcd of -18 and -9 is -9, so (-18)/(-9) = (-9×2)/(-9×1) = (-9)/(-9)×2 = 2:
Answer: |
| x = 2

personal59:
Please help

All workings are needed (step to step workings with full details) on how it is solve

Thanks in anticipation






1) Using 4 sub intervals in the composite trapezium rule approximate intergral 5-1 I.e integral of 5 upper limit and 1 lower limit (square root Xdx)


2) The function f is known to have a second derivative with the property that /f"(x)/ < 12
For x between 2 and 3. Using the error bound giving earlier in this section determine how many sub intervals are required so that the composite trapezieum rule used to approximate integral 5-2 f(x)dx


3) Using 4 sub intervals in the composite simpson rule approximate. Integral 5-1 square root xdx

4) The function f is known to have a forth derivative with the property that f^(iv) (x)<6
For x between -1 and 5. Determine how many sub intervals are required so that the composite trapezium rule use to approximate integral 5 - (-2) f(x)dx incurs an error that is less than 0.001.

agentofchange1:

I doubt if an analytical solution to this exist.

personal59:
Please help

All workings are needed (step to step workings with full details) on how it is solve

Thanks in anticipation






1) Using 4 sub intervals in the composite trapezium rule approximate intergral 5-1 I.e integral of 5 upper limit and 1 lower limit (square root Xdx)


2) The function f is known to have a second derivative with the property that /f"(x)/ < 12
For x between 2 and 3. Using the error bound giving earlier in this section determine how many sub intervals are required so that the composite trapezieum rule used to approximate integral 5-2 f(x)dx


3) Using 4 sub intervals in the composite simpson rule approximate. Integral 5-1 square root xdx

4) The function f is known to have a forth derivative with the property that f^(iv) (x)<6
For x between -1 and 5. Determine how many sub intervals are required so that the composite trapezium rule use to approximate integral 5 - (-2) f(x)dx incurs an error that is less than 0.001.

Pls help me with my question pls


The details is here and also before this post

personal59:
Please help

All workings are needed (step to step workings with full details) on how it is solve

Thanks in anticipation






1) Using 4 sub intervals in the composite trapezium rule approximate intergral 5-1 I.e integral of 5 upper limit and 1 lower limit (square root Xdx)

Solution is attached.

Karmanaut:

Solution is attached.

Thanks brother but the question u solve first I can't see some of the f() very well nd u solve most with it I don't know if u can help m rewrite it clearly


And also I need answer to other questions sir thanks

Show that the curve x²+xy+y²-2=0 is an ellipse. Hence, obtain it's
(i) centre
(ii) vertices
(iii) co-vertices
(iv) foci
(v) axes of symmetry
(vi) semi-major axis length

tags: Karmanaut, Laplacian, dejt4u, jaryeh, agentofchange1, AlphaMaximus, doubleDx, etc

personal59:


Thanks brother but the question u solve first I can't see some of the f() very well nd u solve most with it I don't know if u can help m rewrite it clearly


And also I need answers to other questions sir thanks

Noted.
I also made an error concerning the width of subintervals I used; I didn't read the question well.
Will correct it and do the rest at my leisure.

jackpot:

Show that the curve x²+xy+y²-2=0 is an ellipse. Hence, obtain it's
(i) centre
(ii) vertices
(iii) co-vertices
(iv) foci
(v) axes of symmetry
(vi) semi-major axis length

Solution:
Foci:
(2/√3, -2/√3)

Vertices:
(√2, -√2)

Center:
(0,0)

Semi major axis length:
2

Semi minor axis length:
2/√3

@Personal59, the solution for question 1. I trued to make my writing bigger.

Karmanaut:
@Personal59, the solution for question 1.
I trued to make my writing bigger.

ok thanks bro
Its very clear and straightforward
Checking regularly too am very grateful opful for the other answers
too bro

personal59:

ok thanks bro
Its very clear and straightforward
Checking regularly too am very grateful opful for the other answers
too bro

Cheers.
Doing question 3 now.
I'll research 2 & 4 later.
Edit:
Solution to Question 3 attached.

Karmanaut:
Cheers. Doing question 3 now. I'll research 2 & 4 later. Edit: Solution to Question 3 attached.

Thanks bro am very very grateful

Seamione:
Good evening guys,
Please take a look at this question.

Three digit numbers re formed from the digits 1,2,4,5,6. If repetition is not allowed and a number is picked at random, find the probability that it's a multiple of 5 or an odd number.

From my calculations, I got 2/5 but the text says it's 3/5. Who is wrong?

total ways of selection = 5C3 = 10ways

sample space

S={(124),(125),(126),(245),(246),(145),(156),(645),(641),(265)}

check where we have an odd number or multiple of 5

thus, we get

6/10=3/5


hope you get?

Karmanaut:
Cheers. Doing question 3 now. I'll research 2 & 4 later. Edit: Solution to Question 3 attached.

Thanks bro am very very grateful

agentofchange1:





total ways of selection = 5C3 = 10ways

sample space

S={(124),(125),(126),(245),(246),(145),(156),(645),(641),(265)}

check where we have an odd number or multiple of 5

thus, we get

6/10=3/5


hope you get?

No, I kinda disagree with your sample space, it can't just be 5C3. For instance, where Is 421, 521 and 621 in your sample space? At least, they're also of 3 digits which are odd numbers..

Seamione:
No, I kinda disagree with your sample space, it can't just be 5C3. For instance, where Is 421, 521 and 621 in your sample space? At least, they're also of 3 digits which are odd numbers..

c'mmon bro, the question says no repetition

5C3 means total number of ways we could form the 3-digit number without repetition

421 (124) ,521(125) , 621( 126) already exist in the sample space.

Karmanaut:

Solution: Foci: (2/√3, -2/√3)
Vertices: (√2, -√2)
Center: (0,0)
Semi major axis length: 2
Semi minor axis length: 2/√3

please, kindly show full workings.

agentofchange1:


c'mmon bro, the question says no repetition

5C3 means total number of ways we could form the 3-digit number without repetition

421 (124) ,521(125) , 621( 126) already exist in the sample space.

Oga General Ben, I think the "no repetition" in the question means we can't have numbers like 111, 222, 444, 555 and 666.
Moreover, 421 and 124 are not exactly the same number, they're just numbers with the same digits so we can't consider that as repetition because if that's the case, I don't think we should also have 124 and 125 because 1 and 2 have been repeated.
I hope you understand what I'm trying to say

Seamione:
Oga General Ben, I think the "no repetition" in the question means we can't have numbers like 111, 222, 444, 555 and 666.
Moreover, 421 and 124 are not exactly the same number, they're just numbers with the same digits so we can't consider that as repetition because if that's the case, I don't think we should also have 124 and 125 because 1 and 2 have been repeated.
I hope you understand what I'm trying to say

hmmm, i won't say much bro

let others shed more light.

agentofchange1:


hmmm, i won't say much bro

let others shed more light.

Exactly, waiting for others to come in on this

Seamione:
Exactly, waiting for others to come in on this

u definitely know little about probability..

hmmm.

its ok then..