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Nairaland Mathematics Clinic - Education (277) - Nairaland

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Re: Nairaland Mathematics Clinic by itstinaofficial(f): 4:45pm On Oct 08, 2020
YoungDaNaval:
Wow
yeah
Re: Nairaland Mathematics Clinic by officialfestus(m): 12:45pm On Oct 09, 2020
Solved
Re: Nairaland Mathematics Clinic by Najdorf: 8:42pm On Oct 09, 2020
itstinaofficial:

x^(1/√x)=2

x=2^√x

let y=√x

x=2^y

x-2^y=0

x=y²

y²=2^y

hence y=2

x=2²

x=4
I think there are some issues here.
Re: Nairaland Mathematics Clinic by YoungDaNaval(m): 6:14am On Oct 10, 2020
itstinaofficial:

yeah
Hey, let's be friends embarassed
Re: Nairaland Mathematics Clinic by YoungDaNaval(m): 6:14am On Oct 10, 2020
Najdorf:

I think there are some issues here.
Point them out cheesy
Re: Nairaland Mathematics Clinic by Spartancosta(m): 7:02am On Oct 10, 2020
Alao046:
Solve for X anyone. I have already given the answer, but solve to get it.
Lets see how good you are
x^(1/√x)=2
applying natural log
In(x^(1/√x)=In2
(1/√x)Inx=In2
(x^-1/2)Inx=In2
since e^In=1
(e^In(x^-1/2)Inx=In2
(e^-1/2Inx)Inx=In2
multiplying both sides by -1/2
(e^-1/2Inx)(Inx*-1/2)=(-1/2)(In2)
(e^-1/2Inx)(-1/2Inx)=-1/(2In2)
since. W(xe^x)=x
adding W to both sides
-1/2Inx=W(-1/(2In2))
multiplying by -2
Inx=-2W(-1/(2In2)
e^Inx=e^-2W(-1/(2In2)
x=e^-2W((-1/2In2))
x will have 4 solutions including 2 complex solutions
don't have the Wolfram alpha but I'm sure x=4
Re: Nairaland Mathematics Clinic by mathefaro(m): 11:16am On Oct 10, 2020
Spartancosta:

x^(1/√x)=2
applying natural log
In(x^(1/√x)=In2
(1/√x)Inx=In2
(x^-1/2)Inx=In2
since e^Inx=x
(e^In(x^-1/2)Inx=In2
(e^-1/2Inx)Inx=In2
multiplying both sides by -1/2
(e^-1/2Inx)(Inx*-1/2)=(-1/2)(In2)
(e^-1/2Inx)(-1/2Inx)=-1/(2In2)
since. W(xe^x)=x
adding W to both sides
-1/2Inx=W(-1/(2In2))
multiplying by -2
Inx=-2W(-1/(2In2)
e^Inx=e^-2W(-1/(2In2)
x=e^-2W((-1/2In2))
x will have 4 solutions including 2 complex solutions
don't have the Wolfram alpha but I'm sure x=4
Fixed
e^x and lnx are the inverses of each other
Re: Nairaland Mathematics Clinic by mathefaro(m): 11:37am On Oct 10, 2020
YoungDaNaval:
Point them out cheesy
The only/ main issue is the conclusion

"hence y = 2" as a solution to the equation y² = 2^y.

It is tantamount to the following
x^(1/√x)=2
Hence x = 4
Re: Nairaland Mathematics Clinic by Spartancosta(m): 2:35pm On Oct 10, 2020
mathefaro:
Fixed e^x and lnx are the inverses of each other
I don't get you?
Re: Nairaland Mathematics Clinic by Spartancosta(m): 2:59pm On Oct 10, 2020
mathefaro:
Fixed e^x and lnx are the inverses of each other
yeah In(e^x)=e^(Inx)
Re: Nairaland Mathematics Clinic by mathefaro(m): 3:27pm On Oct 10, 2020
Spartancosta:

I don't get you?
what I meant was that. It is not really correct to say
e^ln = 1
There has to be an argument to the log function.
Re: Nairaland Mathematics Clinic by Spartancosta(m): 5:22pm On Oct 10, 2020
mathefaro:
what I meant was that. It is not really correct to say
e^ln = 1
There has to be an argument to the log function.
you are right

2 Likes

Re: Nairaland Mathematics Clinic by ayubasodeeq(m): 6:31pm On Oct 10, 2020
Derive the rules of pascal triangle and solve this using pascal triangle and correct to 2d.p
(1.01)4
Re: Nairaland Mathematics Clinic by Spartancosta(m): 7:08pm On Oct 10, 2020
ayubasodeeq:
Derive the rules of pascal triangle and solve this using pascal triangle and correct to 2d.p
(1.01)4
(a+b)⁴=a⁴+4a³b+6a²b²+4ab³+b⁴
(1.01)=(1+0.01)
1=a
0.01=b
(1.01)⁴=1⁴+4(1³)(0.01)+6(1²)(0.01)²+4(1)(0.01)³+(0.01)⁴
will modify this later, I'm typing on the road
1⁴+4(0.01)+6(0.0001)+4(0.000001)+0.00000001
1+0.04+0.0006+0.000004+0.00000001
=1.04060401
=1.041(app.)

1 Like

Re: Nairaland Mathematics Clinic by simiife: 8:07pm On Oct 10, 2020
Wow,I had no idea there was a thread like this,I need someone to solve these questions

Re: Nairaland Mathematics Clinic by Spartancosta(m): 8:21pm On Oct 10, 2020
simiife:
Wow,I had no idea there was a thread like this,I need someone to solve these questions
1.nth term =3^(n-1)
1st term =3^(1-1)=3°=1
2nd=3^(1-2)=3^-¹=1/3
3rd=3^(1-3)=3^-²=1/9
sum =1/3+1/9=(4/9)+1=13/9
2.
81^(3/4) -27^(1/3)/(3*2³)
(⁴√81)³-(³√27)/(3*2³)
(3)³-(3)/3*2³
=27-3/(3*2³)
24/(3*2³)
24/24=1
4.
sum of interior angles =(180n-360)
1800=180n-360
1800+360=180n
2160=180n
n=2160/180=12
number of sides =12
each angle=1800/12=150°
sum of interior angles and exterior angle of a regular polygon =180
150+e=180
e=180-150
e=30°
3.
y=x³-x
differentiating
y=3x²-1
solving the quadratic equation
a=3,b=0,c=-1
=(√-(4*3*-1))/2*3
=(√12)/6
=2√3/6
=√3/3
Re: Nairaland Mathematics Clinic by ayubasodeeq(m): 8:31pm On Oct 10, 2020
Spartancosta:
(a+b)⁴=a⁴+4a³b+6a²b²+4ab³+b⁴ (1.01)=(1+0.01) 1=a 0.01=b (1.01)⁴=1⁴+4(1³)(0.01)+6(1²)(0.01)²+4(1)(0.01)³+(0.01)⁴ will modify this later, I'm typing on the road 1⁴+4(0.01)+6(0.0001)+4(0.000001)+0.00000001 1+0.04+0.0006+0.000004+0.00000001 =1.04060401 =1.041(app.)
Are you a teacher
Re: Nairaland Mathematics Clinic by Spartancosta(m): 9:44pm On Oct 10, 2020
ayubasodeeq:
Are you a teacher
no sir
Re: Nairaland Mathematics Clinic by itstinaofficial(f): 8:59am On Oct 11, 2020
Najdorf:
I think there are some issues here.
where exactly?
Re: Nairaland Mathematics Clinic by mathefaro(m): 9:22am On Oct 12, 2020
itstinaofficial:

where exactly?
I've stated the issue in a post up there
Re: Nairaland Mathematics Clinic by Entrepreneurrr: 1:34pm On Oct 31, 2020
Help me solve this please

Re: Nairaland Mathematics Clinic by simiife: 3:34pm On Oct 31, 2020
Anyone please

Re: Nairaland Mathematics Clinic by Obinoscopy(m): 5:50pm On Oct 31, 2020
Entrepreneurrr:
Help me solve this please
Have you attempted solving it? If you have, where exactly did you get stuck? Let me know so I can take it up from there.
Re: Nairaland Mathematics Clinic by Obinoscopy(m): 5:51pm On Oct 31, 2020
simiife:
Anyone please
Have you attempted solving them? If you have, where exactly did you get stuck? Let me know so I can take it up from there.
Re: Nairaland Mathematics Clinic by yusman14(m): 6:31pm On Oct 31, 2020
Entrepreneurrr:
Help me solve this please
The answer to the second question is x=5/4
Re: Nairaland Mathematics Clinic by yusman14(m): 6:33pm On Oct 31, 2020
simiife:
Anyone please
the second question Is not clear..is is 2√x-1/x ??
Re: Nairaland Mathematics Clinic by Najdorf: 7:31pm On Oct 31, 2020
Obinoscopy:
Have you attempted solving it? If you have, where exactly did you get stuck? Let me know so I can take it up from there.
Exactly. It feels like he hasn't even looked at the questions at all.
Re: Nairaland Mathematics Clinic by Entrepreneurrr: 9:30pm On Oct 31, 2020
Obinoscopy:
Have you attempted solving it? If you have, where exactly did you get stuck? Let me know so I can take it up from there.

For the first question I didn’t try it because I don’t know how to evaluate different bases.


The second one, i tried but i don’t think i got it right (see the workings)

Re: Nairaland Mathematics Clinic by Entrepreneurrr: 9:38pm On Oct 31, 2020
Najdorf:

Exactly. It feels like he hasn't even looked at the questions at all.

Its not like that I haven’t learn mathematics for the fast 6 years, so my brain is not that active their.

I am trying to brush up my brain
Re: Nairaland Mathematics Clinic by MeetDx(m): 9:42pm On Oct 31, 2020
yusman14:
the second question Is not clear..is is 2√x-1/x ??

No be 1?

Dy/dx = 2rtX/X - 1

= 2*1/1 -1

= 1

Then again maybe it 1/x the problem is not clear
Re: Nairaland Mathematics Clinic by MeetDx(m): 9:43pm On Oct 31, 2020
Entrepreneurrr:
Help me solve this please

X=5/4
Re: Nairaland Mathematics Clinic by mathefaro(m): 7:41am On Nov 01, 2020
Entrepreneurrr:


For the first question I didn’t try it because I don’t know how to evaluate different bases.


The second one, i tried but i don’t think i got it right (see the workings)
This is what you need.

1 Like

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