Welcome, Guest: Register On Nairaland / LOGIN! / Trending / Recent / New
Stats: 3,195,260 members, 7,957,638 topics. Date: Tuesday, 24 September 2024 at 04:30 PM

Nairaland Mathematics Clinic - Education (76) - Nairaland

Nairaland Forum / Nairaland / General / Education / Nairaland Mathematics Clinic (495293 Views)

Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)

(1) (2) (3) ... (73) (74) (75) (76) (77) (78) (79) ... (284) (Reply) (Go Down)

Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 2:36pm On Oct 13, 2013
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 2:46pm On Oct 13, 2013
Eng. Tino:
choii...........all dese ones are uni maths....i hail oo.....i av a question.......a four digit positive number 'N' is given.....when d tens digit and unit digit of d numba is swapped and the thousand digit and hundred digit is also swapped, a new number T(N) is formed.... M is a number such dat T(M)=4M................what are d last 3 digits of M
I think there's insufficient information in this word problem,that is, unless someone produces a reasonable solution to this problem without any 'wayo-wayo' method
Re: Nairaland Mathematics Clinic by Mbahchiboy(m): 2:53pm On Oct 13, 2013
Laplacian:
almost everybody gave solutions to your questions on the previous pages...unless u have not viewed them....
DIAS WAS NOT D ANSWER
Re: Nairaland Mathematics Clinic by omololla(f): 2:57pm On Oct 13, 2013
[b][/b]please help me solve the math naw embarassed[color=#000099][/color]
Re: Nairaland Mathematics Clinic by Mbahchiboy(m): 2:58pm On Oct 13, 2013
Laplacian:
for your first question use Maclaurin's series...the solution is;
tanhx=x-2x^3/3!+4x^5/5!-...+...
(-2)^n*x^(2n+1)/(2n+1)! For
n=0,1,2...
For your second question,
x^5-32=0 may be written as
x^5=32e^(2#i) where #=22/7 and e=2.71828, it follows that
x=2e^(2#ni/5) for n=0,1,2,3,4 they provide all solutions to the equation...for other soutions check preivous pages...
i will b glad if u do d no 1 hear caus am not so gud in maths and ur soln to no 2 is somehow
Re: Nairaland Mathematics Clinic by Mbahchiboy(m): 3:04pm On Oct 13, 2013
find x if.
8^x=4x
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 3:06pm On Oct 13, 2013
omololla: can you please solve this for me.

!: sola sells her books to customers at the price marked in her shop. titi allows her own customer 8% reduction from the marked price which means that she sells for 1104 naira the same books sola sells for 112o. determine titi marked price for the books that sola sells 56o naira.
a; what is titi selling price to her customers of this goods in (1) above.
b: find sola selling price for goods titi sells 736 naira.

2: a man left his fortune to be divided so that each of his3 sons receive 1/10,each of his 2 daughter receive 1/8.
#5000 was to be paid to her hospital and the rest to his widow. if the widow received #49000, how much did he leave behind.
for question 2:
Let the amount of money be 'X'.....3 of his sons receive 1/10 of 'X' each and 1/10 =0.1 since its three sons, we have 0.1*3*'X'=0.3X.......again, his two daughters are entitled to 1/8 of 'X' each and 1/8 =0.125, since its 2 daughters, we have:0.125*2*'X'=0.25x.....it is also known that a #5000 hospital bill was paid and his widow received #49,000...the sum of these amounts is 54000.....now the linear equation is: 0.3X + 0.25X + 54000 = X
0.55X + 54000 =X
1X-0.55X =54000
0.45X=54000
Therefore, X =54000/0.45 = #120,000...
As for no. 1 , I'm not sure if you mean 112o instead of 1,120 and 56o(fifty-six o) instead of 560(five hundred and sixty).....please clarify no. 1....I hope the no. 2 solution helped
Re: Nairaland Mathematics Clinic by omololla(f): 3:44pm On Oct 13, 2013
Alpha Maximus: for question 2:
Let the amount of money be 'X'.....3 of his sons receive 1/10 of 'X' each and 1/10 =0.1 since its three sons, we have 0.1*3*'X'=0.3X.......again, his two daughters are entitled to 1/8 of 'X' each and 1/8 =0.125, since its 2 daughters, we have:0.125*2*'X'=0.25x.....it is also known that a #5000 hospital bill was paid and his widow received #49,000...the sum of these amounts is 54000.....now the linear equation is: 0.3X + 0.25X + 54000 = X
0.55X + 54000 =X
1X-0.55X =54000
0.45X=54000
Therefore, X =54000/0.45 = #120,000...
As for no. 1 , I'm not sure if you mean 112o instead of 1,120 and 56o(fifty-six o) instead of 560(five hundred and sixty).....please clarify no. 1....I hope the no. 2 solution helped
Thanks. no1 is one thousand, one hundred and twenty naira and the other is five hundred and sixty naira
Re: Nairaland Mathematics Clinic by dcitizen1: 3:50pm On Oct 13, 2013
@ mbachiboy,

I have provided a clue to ur problem especially x5 -32 =0. Check my post. Am down with fever. Sorry for not proviving answers to engineering mathematics problem. Jacpot, u are welcome on board. Am the one and only five star math general
Re: Nairaland Mathematics Clinic by dcitizen1: 3:55pm On Oct 13, 2013
It is really painful for math general in the house for misrepresenting the simple law of logarithm

Log a + log b = logab

There is no validity for the following

Log (a+ b) = logab

Log (a-b) = log a/b

So if u are given an expression as follow:

a + b = c

Introducing log to both side do not mean

Log a + logb = log c ( never, there is no such law in logarithm)

My fellow, math general, let us post realistic problem and learn the correction of common and silly error in math be it pure, applied and engineering mathematics
Re: Nairaland Mathematics Clinic by dcitizen1: 4:01pm On Oct 13, 2013
It is really painful for math generals in the house to make simple mistake in mathematics and failing to learn the right correction

Pls, take note

Log (a b) is not equal to log ab

So if u are given such expression as

a b = c

Introduce log to bothside cannot mean the following:

Log a log b = log c

Math general, pls take note. I wasnot able to provide solutions to questions posted becos i was down with fever. Once my recovery, i will be very active again. Your and only five star general

1 Like

Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:02pm On Oct 13, 2013
omololla: Thanks. no1 is one thousand, one hundred and twenty naira and the other is five hundred and sixty naira
No probs....but I doubt its 1,120...are you sure its not 1,200 cause my calculations are not in sync with your information...when 8% of 1,200 is deducted from 1,200 it gives the value of 1,104 which you have given and this would be appropriate but am afraid the deduction of 8% of 1,120 from 1,120 is not equal to 1,104....double - check your typing please
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:05pm On Oct 13, 2013
d citizen:
@ mbachiboy,

I have provided a clue to ur problem especially x5 -32 =0. Check my post. Am down with fever. Sorry for not proviving answers to engineering mathematics problem. Jacpot, u are welcome on board. Am the one and only five star math general
Mathematics fever? Heard that's contagious grin......
Re: Nairaland Mathematics Clinic by dcitizen1: 4:08pm On Oct 13, 2013
@alpha, u are not serious

Am a mechanical engineer by profession and a mathematician by passion

1 Like

Re: Nairaland Mathematics Clinic by Laplacian(m): 4:11pm On Oct 13, 2013
Mbahchiboy: i will b glad if u do d no 1 hear caus am not so gud in maths and ur soln to no 2 is somehow
even me am not very gud in maths, here's my attempt
From Maclaurin's series;
f(x)=f+xf'+x^2f"/2!+x^3f"'/3!+...
Where all derivatives are @ x=0,
now f(x)=tanhx=sinhx/coshx so f(0)=0, f'(x)=(cosechx)^-2 so that f'(0)=1,
f"(x)=-2tanhx*(cosechx)^-2 so that f"(0)=0
f"'(x)=-2tanhx*f"(x)-2[f'(x)]^2...so that f"'(0)=-2 and so on, substitutn now gives;
tanhx=x-2x^3/3!+...
Pls ignore my previous solution for ur first questn....the second solution remains d same and i left d answer in polar form...
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:18pm On Oct 13, 2013
d citizen:
@alpha, u are not serious

Am a mechanical engineer by profession and a mathematician by passion
......nice job man! I was joking by the way.....its just amazing how people dedicate their time to solving other people's problems here on this thread.....good initiative anyway....you are a good contributor too, Mr '5 Star General'
Re: Nairaland Mathematics Clinic by omololla(f): 4:23pm On Oct 13, 2013
Alpha Maximus: No probs....but I doubt its 1,120...are you sure its not 1,200 cause my calculations are not in sync with your information...when 8% of 1,200 is deducted from 1,200 it gives the value of 1,104 which you have given and this would be appropriate but am afraid the deduction of 8% of 1,120 from 1,120 is not equal to 1,104....double - check your typing please
I think it should be 8% of 1,104 which is 88.32 and you add it to 1,104 that will be 1,192.32 so therefore you subtract 1,192.32 from 88.32 which will give you 1,104. just saying ooo, wanna be sure that's why I posted it here for you please. because this is the way I solved it. besides that's what the lecturer wrote
Re: Nairaland Mathematics Clinic by omololla(f): 4:31pm On Oct 13, 2013
incase that is giving you headache can you please solve this instead.....

In 1992, the amount of taxes collected in a country amounted to #200,000 per 100 person in 1993, the population increased by 8% and the revenue from taxation by 25%.
a: calculate, to 3 significant figures, the percentage increase taxation per person
b: if in 1993 the government decided to reduce taxation per person by 2%, calculate correct to the nearest naira the revenue from taxation per 100 person.
thanks
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:58pm On Oct 13, 2013

1 Like

Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 5:03pm On Oct 13, 2013
omololla: I think it should be 8% of 1,104 which is 88.32 and you add it to 1,104 that will be 1,192.32 so therefore you subtract 1,192.32 from 88.32 which will give you 1,104. just saying ooo, wanna be sure that's why I posted it here for you please. because this is the way I solved it. besides that's what the lecturer wrote
...well, when you put it that way, it makes the details more ambiguous.....I was working on the assumption that both Sola and Titi's goods have the same original marked price
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 5:16pm On Oct 13, 2013
omololla: I think it should be 8% of 1,104 which is 88.32 and you add it to 1,104 that will be 1,192.32 so therefore you subtract 1,192.32 from 88.32 which will give you 1,104. just saying ooo, wanna be sure that's why I posted it here for you please. because this is the way I solved it. besides that's what the lecturer wrote
.....Besides , your approach is still wrong.....if 1,104 is the discounted price, this is how to find the original marked price:
Let the original marked price be X
Since we obtain a discount by deducting the percentage of the original, we have an equation as follows:
X-8%X=1,104
1X-0.08X = 1,104
0.92X=1,104
X=1,104/0.92
X=1,200
Re: Nairaland Mathematics Clinic by omololla(f): 5:23pm On Oct 13, 2013
Alpha Maximus: .....Besides , your approach is still extremely wrong.....if 1,104 is the discounted prices, this is how to find the original marked price:
Let the original marked price be X
Since we obtain a discount by deducting the percentage of the original, we have an equation as follows:
X-8%X=1,104
1X-0.08X = 1,104
0.92X=1,104
X=1,104/0.92
X=1,200
Wow, would you look at that! The original marked price of Titi's goods is the exact same value which I think 1,200 is meant to be!! Coincidence? I think not!!
that is why I posted it here for you to solve for me because am not a lover of math at all. please solve it for me and the rest questions too. lol

Thanks
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 5:42pm On Oct 13, 2013
omololla: that is why I posted it here for you to solve for me because am not a lover of math at all. please solve it for me and the rest questions too. lol

Thanks
alright, I'll see what I can do about that No.1 question...I'll also try out the new one
Re: Nairaland Mathematics Clinic by omololla(f): 5:48pm On Oct 13, 2013
Alpha Maximus: alright, I'll see what I can do about that No.1 question...I'll also try out the new one

thanks
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 6:22pm On Oct 13, 2013
omololla: incase that is giving you headache can you please solve this instead.....

In 1992, the amount of taxes collected in a country amounted to #200,000 per 100 person in 1993, the population increased by 8% and the revenue from taxation by 25%.
a: calculate, to 3 significant figures, the percentage increase taxation per person
b: if in 1993 the government decided to reduce taxation per person by 2%, calculate correct to the nearest naira the revenue from taxation per 100 person.
thanks
.....Voila!!! Here's the solution:
Statistics for 1992: #200,000/100 guys and #2000/each guy(don't write 'guy' for your lecturer)
Statististics for 1993: 8% pop increase and 25% taxation increase resulting in: #250,000/108 guys and #2,314.8148/each guy
(A)Objective: To find the percentage increase in taxation per guy
Change in taxation=new taxation per guy - old taxation per guy = 2,314.8148-2000= 314.8148
Percentage increase in taxation=change in taxation divided by old taxation then multiplied by 100
Thus,
(314.8148/2000)*100=15.74071%=15.7% to 3 significant figures
(B) Objective: To obtain new taxation revenue in 1993, given a 2%(stingy) discount by government
First obtain taxation per 100 guyz in 1993
Taxation per 100 guyz in 1993=(250,000/108)*100=231,481.48 per 100 guyz
Now including 2% discount
(2/100)*231,481.48=4,629.6296
New taxation revenue per 100 guyz in 1993=231,481.48- 4,629.6296=226,851.5=#226,852 to the nearest naira........hope that helped

2 Likes

Re: Nairaland Mathematics Clinic by Mbahchiboy(m): 6:24pm On Oct 13, 2013
d citizen:
@ mbachiboy,

I have provided a clue to ur problem especially x5 -32 =0. Check my post. Am down with fever. Sorry for not proviving answers to engineering mathematics problem. Jacpot, u are welcome on board. AM THE ONE AND ONLY FIVE STAR MATH GENERAL
Re: Nairaland Mathematics Clinic by Cashio(m): 1:30pm On Oct 14, 2013
Alpha Maximus: .....Voila!!! Here's the solution:
Statistics for 1992: #200,000/100 guys and #2000/each guy(don't write 'guy' for your lecturer)
Statististics for 1993: 8% pop increase and 25% taxation increase resulting in: #250,000/108 guys and #2,314.8148/each guy
(A)Objective: To find the percentage increase in taxation per guy
Change in taxation=new taxation per guy - old taxation per guy = 2,314.8148-2000= 314.8148
Percentage increase in taxation=change in taxation divided by old taxation then multiplied by 100
Thus,
(314.8148/2000)*100=15.74071%=15.7% to 3 significant figures
(B) Objective: To obtain new taxation revenue in 1993, given a 2%(stingy) discount by government
First obtain taxation per 100 guyz in 1993
Taxation per 100 guyz in 1993=(250,000/108)*100=231,481.48 per 100 guyz
Now including 2% discount
(2/100)*231,481.48=4,629.6296
New taxation revenue per 100 guyz in 1993=231,481.48- 4,629.6296=226,851.5=#226,852 to the nearest naira........hope that helped
maan u tear the tin no be small.when i first saw de question,i thought it was too hard but after seeing ur approach,i said i can it. And sure i did it!!..i am improving seriously
Re: Nairaland Mathematics Clinic by Mikebis(m): 2:20pm On Oct 14, 2013
I hate bussiness maths
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:52pm On Oct 14, 2013
smiley
Cashio: maan u tear the tin no be small.when i first saw de question,i thought it was too hard but after seeing ur approach,i said i can it. And sure i did it!!..i am improving seriously
......Thanks!! Its all about breaking the complex info into more basic units......simplifying is the key....and keep practising!! smiley
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 4:57pm On Oct 14, 2013
Re: Nairaland Mathematics Clinic by rhydex247(m): 7:43am On Oct 15, 2013
I'm veri sowie for my mistakes. Nobody is perfect. I still remain rhydex 247 either u prove me rigorously or by venn diagram. Happy Eid-il-Kabir.
Enjoy.
Re: Nairaland Mathematics Clinic by cconcept: 8:19am On Oct 15, 2013
any MATLAB guru here? smiley

(1) (2) (3) ... (73) (74) (75) (76) (77) (78) (79) ... (284) (Reply)

Mastercard Foundation Scholarship, Enter Here / DIRECT ENTRY Admission. / Jamb Result Checker 2012/2013 – UTME Result Checker

(Go Up)

Sections: politics (1) business autos (1) jobs (1) career education (1) romance computers phones travel sports fashion health
religion celebs tv-movies music-radio literature webmasters programming techmarket

Links: (1) (2) (3) (4) (5) (6) (7) (8) (9) (10)

Nairaland - Copyright © 2005 - 2024 Oluwaseun Osewa. All rights reserved. See How To Advertise. 69
Disclaimer: Every Nairaland member is solely responsible for anything that he/she posts or uploads on Nairaland.