prince CEE: u be Samuel Peter

FrancisTony: Lol! I be klitschiko.

prince CEE: it follows from newton's second law of motion

Kunlexic: its 4rm d 1st law,u knw a force will change the state of rest and uniform motion on a straight line of a body.

modewap: Woh ar u nigga doin

Ai-bi-ke:
Una don bid here abi?,...

aysuccess99:
good afternoon boss. Happy New Year to you. hmmmn, when it's almost time for jamb exam, i know that people/jambites would pop in here, so i know that this thread is very useful and I hope all the jambites here will gain admission.
@all, let the asking and answering of questions continue. Best of God and best of luck to us all.

emekakelvin: 3 in 1 question.

Jamb 2013.
Mathematic question4 type 1

.Evaluate 1.25*0.025/0.05, correct to 1 decimal place.
A)0.6
B)6.2
C)6.3
D)0.5

This maths question do me strong thing 4 hall.

Chemistry Jamb 2013 Type D Number 31
Which of the following compounds is a neutral oxide?
A)sulphur(VI)oxide
B)sulphur(IV)oxide
C) carbon(II)oxide
D)carbon(IV)oxide.

Physic Jamb 2014 Type B, number 4
The pair of physical quantities that are scalar only are
A) length and displacement
B)impulse and time
c)volume and area
D) moment and momentum.

Happy New Year

aysuccess99:
[color=#006600]1.A
2. C 3.C.....
I hope am right boss. Let the question keep on loading. I am coming back with my own questions....

emekakelvin: 3 in 1 question.

Jamb 2013.
Mathematic question4 type 1

.Evaluate 1.25*0.025/0.05, correct to 1 decimal place.
A)0.6
B)6.2
C)6.3
D)0.5

This maths question do me strong thing 4 hall.

Chemistry Jamb 2013 Type D Number 31
Which of the following compounds is a neutral oxide?
A)sulphur(VI)oxide
B)sulphur(IV)oxide
C) carbon(II)oxide
D)carbon(IV)oxide.

Physic Jamb 2014 Type B, number 4
The pair of physical quantities that are scalar only are
A) length and displacement
B)impulse and time
c)volume and area
D) moment and momentum.

Happy New Year

emekakelvin: Sir, I know Only number one answer.
I know nothing concerning Number 2 and 3,but your number 1 is wrong.

Ai-bi-ke:
1.25*0.025/0.05
(125*25*100)/(5*1000*100)
5/8=0.625 ans is A
2..optin C
3..opt C
mr aysuccess is very correct

aysuccess99:
why is my number 1 wrong sir.......and please sir what's the answer maybe i didn't get the question correctly.

Ai-bi-ke:
U can as well use dis as a shewing stick,.....The sides of a regular polygon are produced so that evry pair of exterior angle and interior angle is ratio 1:4. Calculate
a.the size of an exterior angle
b.number of sides of d polygon

emekakelvin:

Do not multiply the numerator directly. This is a cunning question, try using your BODMAS.

Doing so, we arrive at 6.3
God bles

emekakelvin: A)36
B)10
Tongue out.

aysuccess99:
okay, i get it bro, that's nice. kudos to you.
this is the workings:
1.25*0.025/0.05
using BODMAS, we first deal with the division rule,
1.25*[0.025/0.05]
We now get:
1.25*0.05=(125/100)*(5\100)=625/10000=0.625, and to 1decimal place, it's 0.63.....
What a tricky maths question. Welldone and thanks oga emakelvin for making that clarification. God Bless.
@oga Ai-bi-ke, am on the road, when I get home, I will tackle your question.

Ai-bi-ke:
And bsyds,...d ans wil stl b dsame if I take dsme step u re talkin abt..cos it is * dats in btwn dem

Ai-bi-ke:
guy u b mathematics bokoharam o!

Ai-bi-ke:
U can as well use dis as a shewing stick,.....The sides of a regular polygon are produced so that evry pair of exterior angle and interior angle is ratio 1:4. Calculate
a.the size of an exterior angle
b.number of sides of d polygon

emekakelvin: Abeg modify ur post, no let nairalander's see am b'cos I am still a learner.

aysuccess99: This is my own questions for Physics, they are jamb based question.
1. The magnitude of the resultant of two mutually perpendicular forces, F1, and F2 is 13N. If the magnitude of F1 is 5N, what is the magnitude of F2?
A2.6N B8.0N C12.0N D18.0N
2. A vibrator of frequency 60Hz is used in generating transverse stationery waves in a long thin wire. If the average distance between successive nodes on the wire is 45cm. Find the speed of the transverse waves in the wire.
A.27m/s B 54m/s C90m/s D108m/s
*workings would be highly appreciated* Thanks a lot.

great.david:
it has been some time now i've been contemplating over this question since you posted it initially.......but within my own knowledge, i resulted into this:
let exterior angle be x and interior angle be 4x.......then x + 4x = 180.....
X=36 degree
thus,
1)size of exterior angle=36
2) 2n-4)90/n=144
n = 10
pls my answer is subject to any correction.....