ANDREW2EIC: Attempt this:

A certain far-sighted person cannot see objects that are closer to the eye than 50cm clearly. Determine the power of the converging lens which will enable him to see at 25cm.

v= -50cm
u= 25cm
1/-50 + 1/25 = 1/f
L.C.M= 50
-1+2/50 = 1/F
F= 50cm
since power= 1/F
power of the converging= 1/50cm
P= 0.02dioptre

The homozygous condition Hbs Hbs results in sickle cell anaemia whereas HbA HbS has the sickling trait. What is the probability that a couple with the sickling trait will give birth to one normal child?
A. 1/2 b. 1/4 c.1/8 d. 0

Simplefemo:
v=3u
1/3u+ 1/u=1/15
1+3/3u=1/15
60=3u
u=20cm
object distance, u= 20cm

U are wrong my guy.

Simplefemo:
v= -50cm
u= 25cm
1/-50 + 1/25 = 1/f
L.C.M= 50
-1+2/50 = 1/F
F= 50cm
since power= 1/F
power of the converging= 1/50cm
P= 0.02dioptre

U are very much correct.

Wow miss alot,ao readn life? Hope sweet!

Simplefemo:
v=3u
1/3u+ 1/u=1/15
1+3/3u=1/15
60=3u
u=20cm
object distance, u= 20cm

oh! U made a mistak there,da object z upright or erect that mean virtual.so da image distnc shld b -3u

buzyguy: oh! U made a mistak there,da object z upright or erect that mean virtual.so da image distnc shld b -3u

Exactly. I guess u are a smart guy. Which part of Nigeria are u from?

Another attempt,The coefficient of linear expansn of aluminum z 23 * 10^-6/k.if the volum of a pot made wif aluminum at temperature To is Vo,what will be the change in temperature resultn in a decrease of 0.20% in volum of the pot?a.-87 b.+87 c.+29 d.-29 all in degreez centigrad

ANDREW2EIC:
Exactly. I guess u are a smart guy. Which part of Nigeria are u from?

u r smart 4bringn such a questn,thks!...and i strngly bliev doze r da kinda questnz jamb lovz to set.Am frm south-west,yourz?

A resonanc tube z 40cm long.The second resonanc z heard when the tube z 3/4 full.what z the frequency of the tunin fork placed near the mouth of da tube?(velocity of sound in air z 334m/s) a.2511Hz b.1670Hz c.835Hz d.345Hz

Simplefemo: The homozygous condition Hbs Hbs results in sickle cell anaemia whereas HbA HbS has the sickling trait. What is the probability that a couple with the sickling trait will give birth to one normal child?
A. 1/2 b. 1/4 c.1/8 d. 0

As crozd with As cuz they are both carrierz,givz AA HEALTHY and NORMAL allele with 1/2 chanc,nd As healthy bt carrier allele with 1/2 chanc.so anza z A!

buzyguy: oh! U made a mistak there,da object z upright or erect that mean virtual.so da image distnc shld b -3u

You are right, thanks for that
1/-3u + 1/u =1/15
-1+3/3u=1/15
3u=30
u=10cm

buzyguy: As crozd with As cuz they are both carrierz,givz AA HEALTHY and NORMAL allele with 1/2 chanc,nd As healthy bt carrier allele with 1/2 chanc.so anza z A!

You have a point
cross between As and As should produce AA, As, As and Ss
AA- normal
As- carrier
ss-sickler
Hence the chance should be 1 out of 4= 1/4

Oh! Thks 4dat correctn,av miscalculatd AA for As.thkz 1nc again

Simplefemo:
You have a point
cross between As and As should produce AA, As, As and Ss
AA- normal
As- carrier
ss-sickler
Hence the chance should be 1 out of 4= 1/4

buzyguy: Another attempt,The coefficient of linear expansn of aluminum z 23 * 10^-6/k.if the volum of a pot made wif aluminum at temperature To is Vo,what will be the change in temperature resultn in a decrease of 0.20% in volum of the pot?a.-87 b.+87 c.+29 d.-29 all in degreez centigrad

Honestly, this question is too good to be jamb question, i.e, jamb can hardly give this kind of question considering time limit. Well, this is the solution:

Let the volume or cubic expansivity of the pot = ¥, initial volume of the pot = Vo, final volume of the pot = V1, change in temperature (To - T1) = T.
Therefore:
¥ = Vo - V1/VoT
(N.B the initial volume came first cos there was decrease in volume during temperature change, hence Vo>V1)

From the question, Vo - V1 = 0.20% of Vo. But 0.20% of Vo = Vo/500. Hence, Vo - V1 = Vo/500 = 0.002Vo = 2x10^-3Vo. Again, ¥ = 3 times linear expansivity of aluminium. ¥ = 3x23x10^-6/K, ¥ = 69x10^-6/K.
Substituting the values into the equation,
¥ = Vo - V1/VoT, 69x10^-6 = 2x10^-3Vo/VoT, Vo will cancel each other. Hence, 69x10^-6 = 2x10^-3/T.
Thus, T = 2x10^-3/69x10^-6, T = 28.9 degree celsius. Therefore change in temperature, T, is approximately +29 degree celsius.
Is that really lengthy? Well, that's the only way i could solve it for others to understands. Thanks for bringing this kind of question.

buzyguy: A resonanc tube z 40cm long.The second resonanc z heard when the tube z 3/4 full.what z the frequency of the tunin fork placed near the mouth of da tube?(velocity of sound in air z 334m/s) a.2511Hz b.1670Hz c.835Hz d.345Hz

Length of resonance tube filled with water = 3/4 of 40 = 3x40/4 = 30cm. Therefore, the length of resonance tube filled with air, i.e, air column = length of resonance tube - length filled with water = 40 - 30 = 10cm.
At 2nd resonance, column of air = 3/4 of wavelength of the vibrating air(assuming i represent it with ¥). Hence, 10 = 3/4 of ¥. 10 = 3x¥/4. Multiply both sides by 4. 10x4 = 3x¥x4/4. 3¥ = 40. ¥ = 40/3 = 13.3cm. Therefore, wavelength,¥, = 13.3cm. Divide 13.3cm by 100 to convert it to metre. 13.3/100 = 0.133m. Hence, ¥ = 0.133m.
But, frequency,f = velocity(v)/wavelength(¥). F = ?, v = 334m/s, ¥ = 0.133m. Substituting:
f = 334/0.133, f = 2511.2Hz. Therefore, the frequency of the tuning fork is approximately 2511Hz.

buzyguy: u r smart 4bringn such a questn,thks!...and i strngly bliev doze r da kinda questnz jamb lovz to set.Am frm south-west,yourz?

Thanks for the compliment. I am not really surprised that you are from south-western part of Nigeria. Ordinarily, i believe that most guys from that region are academically outstanding. Well, I am from south-east.

wow! Ds z perfect,vry xplanatory stepz.thks 4dat

ANDREW2EIC:

Length of resonance tube filled with water = 3/4 of 40 = 3x40/4 = 30cm. Therefore, the length of resonance tube filled with air, i.e, air column = length of resonance tube - length filled with water = 40 - 30 = 10cm.
At 2nd resonance, column of air = 3/4 of wavelength of the vibrating air(assuming i represent it with ¥). Hence, 10 = 3/4 of ¥. 10 = 3x¥/4. Multiply both sides by 4. 10x4 = 3x¥x4/4. 3¥ = 40. ¥ = 40/3 = 13.3cm. Therefore, wavelength,¥, = 13.3cm. Divide 13.3cm by 100 to convert it to metre. 13.3/100 = 0.133m. Hence, ¥ = 0.133m.
But, frequency,f = velocity(v)/wavelength(¥). F = ?, v = 334m/s, ¥ = 0.133m. Substituting:
f = 334/0.133, f = 2511.2Hz. Therefore, the frequency of the tuning fork is approximately 2511Hz.

Thanks 4 ur commendmnt,am so apy nd challengd to av sum1 lyk u nd even sumodaz here.thks 1nc again!

ANDREW2EIC:

Thanks for the compliment. I am not really surprised that you are from south-western part of Nigeria. Ordinarily, i believe that most guys from that region are academically outstanding. Well, I am from south-east.

Very complete xplanatn and real workings.But u knw there z reductn of volume,dat z da diffrnc btw the new volume nd old volum shld b negativ cuz it resultz in a decreas in volume.da chang stil remainz Vf-Vo,whre that vf z lez dan Vo then da chang bcomes negativ wich bringz a negativ temperatur chang.thks for ur detailed xplanatn,any notice or objectn z welcm

ANDREW2EIC:

Honestly, this question is too good to be jamb question, i.e, jamb can hardly give this kind of question considering time limit. Well, this is the solution:

Let the volume or cubic expansivity of the pot = ¥, initial volume of the pot = Vo, final volume of the pot = V1, change in temperature (To - T1) = T.
Therefore:
¥ = Vo - V1/VoT
(N.B the initial volume came first cos there was decrease in volume during temperature change, hence Vo>V1)

From the question, Vo - V1 = 0.20% of Vo. But 0.20% of Vo = Vo/500. Hence, Vo - V1 = Vo/500 = 0.002Vo = 2x10^-3Vo. Again, ¥ = 3 times linear expansivity of aluminium. ¥ = 3x23x10^-6/K, ¥ = 69x10^-6/K.
Substituting the values into the equation,
¥ = Vo - V1/VoT, 69x10^-6 = 2x10^-3Vo/VoT, Vo will cancel each other. Hence, 69x10^-6 = 2x10^-3/T.
Thus, T = 2x10^-3/69x10^-6, T = 28.9 degree celsius. Therefore change in temperature, T, is approximately +29 degree celsius.
Is that really lengthy? Well, that's the only way i could solve it for others to understands. Thanks for bringing this kind of question.

buzyguy: Very complete xplanatn and real workings.But u knw there z reductn of volume,dat z da diffrnc btw the new volume nd old volum shld b negativ cuz it resultz in a decreas in volume.da chang stil remainz Vf-Vo,whre that vf z lez dan Vo then da chang bcomes negativ wich bringz a negativ temperatur chang.thks for ur detailed xplanatn,any notice or objectn z welcm

Thanks for the correction. I was thinking it would be Vo - V1. I am really improving from what I get here everyday. Thanks once again.

buzyguy: Thanks 4 ur commendmnt,am so apy nd challengd to av sum1 lyk u nd even sumodaz here.thks 1nc again!

The pleasure will always be mine.

At least u hav done it all.itz jst da sign!i laud ur effort.

ANDREW2EIC:

Thanks for the correction. I was thinking it would be Vo - V1. I am really improving from what I get here everyday. Thanks once again.

ANDREW2EIC:
Am biased towards option a) cos when they react with carboxylic or alkanoic acids they give out water. Is that correct?

good trial,but the best option is (c)
carbonyl group react with hydrazine and its derivatives known has condensation reaction.......
RRC{O + H2}N3....

ANDREW2EIC:

Velocity(v) of the particle = dy/dt = 4x4xt^3 - 3x3xt^2, v = 16t^3 - 9t^2.
Acceleration(a) of the particle = dv/dt = 16x3xt^2 - 9x2xt, a = 48t^2 - 18t., but t = 3seconds, hence:
a = 48(3^2) - 18x3, a = 48x9 - 18x3, a = 432 - 54, a = 378m/s

therefore the acceleration of the particle is 378m/s.
My 2cent on the question.

respect my bros
.The question was extracted from oau post ume

Simplefemo:
1. A- In esterification reaction, acid and alkanols condenses to give a dimer with the elimination of water molecule.
2. D- Reaction between NO2 and NAOH will form NANO3 and NANO2

number 2 is correct

Coelom is absent in the class of animal termed?
A.mollusca B.reptila C.arthropoda D.coelenterata

2. The most recently evolved structure in animals is the
A.hair B.cilium C.scale D.feather

t.boy007:
respect my bros
.The question was extracted from oau post ume

Oau must be damn serious in their post ume questions. I was only able to solve that question with further maths knowledge.

1-A,2-A

Simplefemo: Coelom is absent in the class of animal termed?
A.mollusca B.reptila C.arthropoda D.coelenterata

2. The most recently evolved structure in animals is the
A.hair B.cilium C.scale D.feather

Grab this:
which of the following inhibit the decomposition of H202?
a)glycerol
b)Mn02
c)NaOH
d)oxygen
what is the shape of the compound of iodine and sulphur subscript 7 (IS7)?
a)linear
b)pentagonal bypyramidal
c)heptagonal pyramidal
d)trigonal bypyramidal

1-A,bt i thnk itz hindered by H3PO4.2-B, 2 z subtractd frm that seven remaining 5,dat 2means bi,while dat 5means pentagonal,itz pyramidal in shape cuz da subscript more dan 2...'dou variatns may occur'making pentagonalbipyramidal

t.boy007:
Grab this:
which of the following inhibit the decomposition of H202?
a)glycerol
b)Mn02
c)NaOH
d)oxygen
what is the shape of the compound of iodine and sulphur subscript 7 (IS7)?
a)linear
b)pentagonal bypyramidal
c)heptagonal pyramidal
d)trigonal bypyramidal

buzyguy: 1-A,bt i thnk itz hindered by H3PO4.2-B, 2 z subtractd frm that seven remaining 5,dat 2means bi,while dat 5means pentagonal making pentagonalbipyramidal

you're good my bro...indeed H3P04 is a catalystic inhibitor but it's not suitable for H202.....(a) is the best answer